finding pattern between two "CERRADO}" strings using negative look-ahead - regex

Question

I have a text file containing lines like these:
CERRADO}165856}TICKET}DESCRIPTION}some random text here\r\n
other random text here}158277747\r\n
CERRADO}165856}TICKET}FR2CODE}more random text also here}1587269339\r\n
My ultimate goal is to concatenate those lines not beginnning with "CERRADO}" string with their preceding line. There might be an arbitrary number of lines not beginning with that string on the file. This is the end result:
CERRADO}165856}TICKET}DESCRIPTION}some random text here other random text here}158277747\r\n
CERRADO}165856}TICKET}FR2CODE}more random text also here}1587269339\r\n
My first attempt was to create a simple regex to match those lines.
CERRADO\}.+\r\n(?!CERRADO\})(.+\r\n)+
After having that regex right, to create a matching group and replace it getting rid of the \r\n patterns, here is what I have so far:
The proposed regex matches all the lines in the file and not just the wanted ones.
Any ideas would be appreciated

Answer 1

You may use
\R(?!CERRADO\})
and replace with a space.
The regex matches:
\R - a line break sequence that is...
(?!CERRADO\}) - not followed with CERRADO}.
Or,
^(CERRADO\}.*)\R(?!CERRADO\})
and replace with \1 . This regex matches:
^ - start of a line
(CERRADO\}.*) - Capturing group 1 (later referred to with \1 backreference from the replacement pattern): CERRADO} substring and then the rest of the line
\R - a line break sequence
(?!CERRADO\}) - not followed with CERRADO}.
To make multiple replacements with this one, you will need to hit Replace All several times.