Match words which have given regex around - regex

Question

I need to get all the text that have two or more spaces "\s{2,}" around them.
Given the following text:
IP Address Name Location Type
10.1.10.5 USLAXBOWC01RB Santa Monica, CA local
I need to extract:
Line1: "IP Address", "Name", "Location", "Type"
Line2: "10.1.10.5", "USLAXBOWC01RB", "Santa Monica, CA", "local"
EDIT:
Text eligible for extraction:
"IP Address" & "Name" are two or more spaces apart so they are eligible to be extracted. Similarly, "Santa Monica, CA" & "local".

Answer 1

You try to split your text according the pattern "\s{2,}".
Thus, in Python, the regex lib re give you all the needed tools:
import re
line = "IP Address Name Location Type"
result = re.split('\s{2,}',line)
Which gives:
['IP Address', 'Name', 'Location', 'Type']
EDIT
I guess i understood a little more your question : you more care about isolating a sequence between \s{2,}, than splitting it. In your example, however, the solution above seems to be the most suitable.
You asked for a regex, here it is :
reg1 = "[^\s](?!\s{2,})(?:.(?!\s{2,}))*[^\s]"
It first selects a character which is not a space with [^\s](?!\s{2,}) not followed by two spaces or more. To do so, I used the negative lookahead assertion (?!...) ;
Then, it isolates a group (?:...) composed in this way : any character . which is not followed by \s{2,} ;
Repeat with * ;
It happens that the final character is not selected if we stop now. So we should add one more [^\s].
A re.findall(reg1,line), and you should be done. One drawback maybe : it detects sequences which are at least two characters long.
In that case, an other and simpler regex could eventually complete the job : reg2 = "\s{2,}([^\s])\s{2,}". It selects single non-space characters surrounded by two spaces or more. The use of the bracket (...), forces to return only the character.
By the way, I strongly advise a look on the documentation : https://docs.python.org/2/library/re.html
Hope you found what you are looking for :-)