Use variant from dependency - ocaml

I have this code:
cnf.mli
type literal
type clause
type cnf
type l_diff
val l_compare: literal -> literal -> l_diff
cnf.ml (partial)
type l_diff = Same | Negation | Different
checker.ml (partial)
open Cnf
type solution = (literal * bool) list
let rec solve_literal sol l =
match sol with
| [] -> false
| (hl, b)::rs when (l_compare l hl) = Same -> b
| (hl, b)::rs when (l_compare l hl) = Negation -> not b
| _::rs -> solve_literal rs l
This works in utop using:
#mod_use "cnf.ml";;
#use "checker.ml";;
But if I try to compile checker I get the following error:
compile command:
ocamlbuild cnf.cma
ocamlbuild checker.cma
error:
+ /home/user/.opam/4.05.0/bin/ocamlc.opt -c -o checker.cmo checker.ml
File "checker.ml", line 7, characters 42-46:
Error: Unbound constructor Same
Hint: Did you mean Some?
Command exited with code 2.
Compilation unsuccessful after building 6 targets (2 cached) in 00:00:00.
Am I using a variant the wrong way, or using the compiler incorrectly?

Neither, you are using abstract types in signature in the wrong way. When you write in cnf.mli
type l_diff
this declares the type l_diff as an abstract type, in other words a black box whose content is hidden.
Contrarily, when using #mod_use "cnf.ml" the toplevel infers a signature by itself and makes all type declarations transparent:
type literal = …
type clause = …
type cnf = …
type l_diff = Same | Negation | Different
val l_compare: literal -> literal -> l_diff
(If you want to see the full inferred signature ocamlbuild cnf.inferred.mli should work.)
With this signature, the constructor of l_diff are visible and it becomes possible to construct directly or pattern match values of type l_diff.
More generally, your signature cnf.mli is far too restrictive:
With this signature, the only way to create a value of type l_diff is to call l_compare. However it would be then impossible to observe the content of the type. Similarly, with the interface cnf.mli that you provided, it is impossible to create a value of type literal.

Related

How do I compare values for equality by Type Constructor?

Background
I'm a relative newcomer to Reason, and have been pleasantly suprised by how easy it is to compare variants that take parameters:
type t = Header | Int(int) | String(string) | Ints(list(int)) | Strings(list(string)) | Footer;
Comparing different variants is nice and predictable:
/* not equal */
Header == Footer
Int(1) == Footer
Int(1) == Int(2)
/* equal */
Int(1) == Int(1)
This even works for complex types:
/* equal */
Strings(["Hello", "World"]) == Strings(["Hello", "World"])
/* not equal */
Strings(["Hello", "World"]) == Strings(["a", "b"])
Question
Is it possible to compare the Type Constructor only, either through an existing built-in operator/function I've not been able to find, or some other language construct?
let a = String("a");
let b = String("b");
/* not equal */
a == b
/* for sake of argument, I want to consider all `String(_)` equal, but how? */
It is possible by inspecting the internal representation of the values, but I wouldn't recommend doing so as it's rather fragile and I'm not sure what guarantees are made across compiler versions and various back-ends for internals such as these. Instead I'd suggest either writing hand-built functions, or using some ppx to generate the same kind of code you'd write by hand.
But that's no fun, so all that being said, this should do what you want, using the scarcely documented Obj module:
let equal_tag = (a: 'a, b: 'a) => {
let a = Obj.repr(a);
let b = Obj.repr(b);
switch (Obj.is_block(a), Obj.is_block(b)) {
| (true, true) => Obj.tag(a) == Obj.tag(b)
| (false, false) => a == b
| _ => false
};
};
where
equal_tag(Header, Footer) == false;
equal_tag(Header, Int(1)) == false;
equal_tag(String("a"), String("b")) == true;
equal_tag(Int(0), Int(0)) == true;
To understand how this function works you need to understand how OCaml represents values internally. This is described in the section on Representation of OCaml data types in the OCaml manual's chapter on Interfacing C with OCaml (and already here we see indications that this might not hold for the various JavaScript back-ends, for example, although I believe it does for now at least. I've tested this with BuckleScript/rescript, and js_of_ocaml tends to follow internals closer.)
Specifically, this section says the following about the representation of variants:
type t =
| A (* First constant constructor -> integer "Val_int(0)" *)
| B of string (* First non-constant constructor -> block with tag 0 *)
| C (* Second constant constructor -> integer "Val_int(1)" *)
| D of bool (* Second non-constant constructor -> block with tag 1 *)
| E of t * t (* Third non-constant constructor -> block with tag 2 *)
That is, constructors without a payload are represented directly as integers, while those with payloads are represented as "block"s with tags. Also note that block and non-block tags are independent, so we can't first extract some "universal" tag value from the values that we then compare. Instead we have to check whether they're both blocks or not, and then compare their tags.
Finally, note that while this function will accept values of any type, it is written only with variants in mind. Comparing values of other types is likely to yield unexpected results. That's another good reason to not use this.

ABAP equality check is wrong for INT4 and CHAR numeric

I've ran into an issue here, and I can't figure out exactly what SAP is doing. The test is quite simple, I have two variables that are a completely different type as well as having two completely different values.
The input is an INT4 of value 23579235. I am testing the equality function against a string '23579235.43'. Obviously my expectation is that these two variables are different because not only are they not the same type of variable, but they don't have the same value. Nothing about them is similar, actually.
EXPECTED1 23579235.43 C(11) \TYPE=%_T00006S00000000O0000000302
INDEX1 23579235 I(4) \TYPE=INT4
However, cl_abap_unit_assert=>assert_equals returns that these two values are identical. I started debugging and noticed the 'EQ' statement was used to check the values, and running the same statement in a simple ABAP also returns 'true' for this comparison.
What is happening here, and why doesn't the check fail immediately after noticing that the two data types aren't even the same? Is this a mistake on my part, or are these assert classes just incorrect?
report ztest.
if ( '23579235.43' eq 23579235 ).
write: / 'This shouldn''t be shown'.
endif.
As #dirk said, ABAP implicitly converts compared or assigned variables/literals if they have different types.
First, ABAP decides that the C-type literal is to be converted into type I so that it can be compared to the other I literal, and not the opposite because there's this priority rule when you compare types C and I : https://help.sap.com/http.svc/rc/abapdocu_752_index_htm/7.52/en-US/abenlogexp_numeric.htm###ITOC##ABENLOGEXP_NUMERIC_2
| decfloat16, decfloat34 | f | p | int8 | i, s, b |
.--------------|------------------------|---|---|------|---------|
| string, c, n | decfloat34 | f | p | int8 | i |
(intersection of "c" and "i" -> bottom rightmost "i")
Then, ABAP converts the C-type variable into I type for doing the comparison, using the adequate rules given at https://help.sap.com/http.svc/rc/abapdocu_752_index_htm/7.52/en-US/abenconversion_type_c.htm###ITOC##ABENCONVERSION_TYPE_C_1 :
Source Field Type c -> Numeric Target Fields -> Target :
"The source field must contain a number in mathematical or
commercial notation. [...] Decimal places are rounded commercially
to integer values. [...]"
Workarounds so that 23579235.43 is not implicitly rounded to 23579235 and so the comparison will work as expected :
either IF +'23579235.43' = 23579235. (the + makes it an expression i.e. it corresponds to 0 + '23579235.43' which becomes a big Packed type with decimals, because of another rule named "calculation type")
or IF conv decfloat16( '23579235.43' ) = 23579235. (decfloats 16 and 34 are big numbers with decimals)

OUnit: assert value is instance of type

Using the OUnit unit testing framework in OCaml, I would like to test that the result of evaluating a function is an instance of a specified type.
Defining such a test in Python's PyTest would be done as follows:
def test_foo():
assert isinstance(foo(2), int)
How can this logic be translated to OUnit? That is, how are assertions of type membership specified?
I'm aware that, assuming the function under test is annotated with the proper type signature, this testing might be unnecessary.
This is the job of a type checker, and it is made automatically during the compilation (at static time). The type checker (i.e., the compiler) guarantees that all values that are created by a function has the same type, and the type is defined statically at the compilation time. You will not be able to compile a function, that creates values of different types, as you will get a type error during the compilation. This is an essential property of all statically typed languages, e.g., Java, C and C++ also has the same property.
So, probably, you're using are confusing terminology. It might be the case, that what you're actually trying to test, is that the value belongs to a particular variant of a sum type. For example, if you have a sum type called numbers defined as:
type t =
| Float of float
| Int of int
and you would like to test that function truncate, defined as
let truncate = function
| Float x -> Int (truncate x)
| x -> x
always returns the Int variant, then you can do this as follows:
let is_float = function Float _ -> true | _ -> false
let is_int = function Int _ -> true | _ -> false
assert (is_int (truncate 3.14))

Code compiling on OCaml 3.11 but not on 4.01

I have the following code that compiles fine in OCaml 3.11:
module type T =
sig
type test
val create : int -> test (* line 44 *)
...
end
...
type test = (string, clause list) Hashtbl.t
let create = Hashtbl.create (* line 332 *)
But when I try to compile it with OCaml 4.01, it gives me the following error:
Error: Signature mismatch:
...
Values do not match:
val create : ?random:bool -> int -> ('a, 'b) Hashtbl.t
is not included in
val create : int -> theory
File "test1.ml", line 44, characters 2-28: Expected declaration
File "test1.ml", line 332, characters 6-12: Actual declaration
make[1]: *** [test1.cmo] Error 2
make: *** [byte-code] Error 2
What changed in OCaml 4 so that it now can't compile it? I am sure it has a very easy explanation but I am still learning the inner workings of OCaml types.
The type of the function has changed --of course! Since the addition is of an optional argument, it will affect anyone who is aliasing the function (which will carry over the type, inc. the optional parameter). You will have to eta-expand the arguments of the create function to fix this issue, as in...
let create i = Hashtbl.create i
In fact it should be noted that you only need to eta-expand one argument to remove the optional arguments from the inferred type signature as in...
let create ?random1 ?random2 x y z = Hashtbl.create (x+y+z);;
(* ?random1:'a -> ?random2:'b -> int -> int -> int -> ('c, 'd) Hashtbl.t *)
let create7 = create 7;;
(* create7 : int -> int -> ('_a, '_b) Hashtbl.t *)

Ocaml: Error - this expression has type x but is used with type x

This is my error:
Error: This expression has type nfa but is here used with type nfa
What could possibly be happening to cause this? I'm using emacs tuareg, and loading evaluating files one by one. Sometimes this happens, and other times it doesn't.
There's a good description of this in the ocaml tutorial. What's happened is you have shadowed a type definition with a new definition:
type nfa = int
let f (x: nfa) = x
type nfa = int
let g (x: nfa) = x
Restarting the top-level will clear out the old definitions.
Update:
Since OCaml 4.01.0 (released Sept. 2013) the general problem is the same, but the error message adds a number to the type definition, to make evident the types are internally different.
Full example from the old OCaml FAQ in the toplevel:
type counter = Counter of int;; (* define a type *)
type counter = Counter of int
# let x = Counter 1;; (* use the new type *)
val x : counter = Counter 1
type counter = Counter of int;; (* redefine the type, use it *)
type counter = Counter of int
# let incr_counter c = match c with Counter x -> Counter (x + 1);;
val incr_counter : counter -> counter = <fun>
# incr_counter x;; (* now mix old and new defs *)
Error: This expression has type counter/1029
but an expression was expected of type counter/1032
#