I'm trying to write a program, which shows a custom message in the console when I type load. But I can't seem to get it to work. :/
#include "stdafx.h"
#include "iostream"
#include "string"
using namespace std;
int main()
{
int commands();
string text;
cout << "Write your registered e-mail to continue...\n";
cin >> text;
string input;
cout << "\n";
cout << "Welcome " << text << endl;
cout << "\n";
cout << "www.steamcommunity.com/id/thetraderdazz> ";
cin >> input;
if (input = load);
cout << "loading...";
system("pause");
return 0;
}
It also gives me the following error:
identifier "load" is undefined.
if (input = load);
There are three mistakes with this line. The first is that you used the assignment operator = instead of comparison operator ==. The former assigns, the latter compares.
The second mistake is that you placed a semicolon after the parenthesis, indicating an empty body. Your compiler should have given you a warning about this.
Finally, there is no variable load. You mean to compare to string literal "load".
Fix to
if (input == "load")
cout << "loading...\n";
You probably intended the following
if (input == "load") {
cout << "loading...";
}
Related
so I have been learning C++ and was working on a monkey see monkey do program and i managed to get the first input working but the second input it just skips straight over it, i have no clue why and any help would be apreciated.
#include <iostream>
#include <string>
using namespace std;
char monkey_1;
char monkey_2;
int msmd()
{
cout << "monkey one:"; cout << endl;
cin >> monkey_1;
system("cls");
cout << "monkey two:"; cout << endl;
cin.clear();
cin >> monkey_2;
cout << "waiting"; cout << endl;
if (monkey_1 == monkey_2)
{
cout << "both monkeys are happy."; cout << endl;
}
else
{
cout << "the monkeys are upest."; cout << endl;
}
return 0;
}
void main()
{
msmd();
}
Do you intent to only get a single character from the input as the monkeys are of type char? If not, change them to string, otherwise it will only assign a single character per cin.
If you want to input a sentence, cin also splits on spaces, so if you enter "something else", the first cin will assign something to monkey_1, and the second cin will automatically assign else to monkey_2.
To get around this you can use getLine(cin,monkey_x).
There are two point needs to be modified.
char monkey_1 and mokeny_2 should be declared as string for get more than 1 character.
void main need to be changed as int main.
I'm trying to use std::cin whilst having one option loop back to the start. The loop works perfectly but when I add in an extra option to one of the if statements then type that in, it doesn't think that what I chose is an option.
#include <iostream>
#include <string>
#include <windows.h>
#include <chrono>
#include <thread>
using namespace std;
int main() {
string choice;
char restart;
do {
choice.clear();
cout << "Which do you take? " << endl;
cin >> choice;
if (choice == "all") {
//cout code
restart = 'y';
}
else if (choice == "dagger" || choice == "the dagger") {
choice.clear();
cout << "You pick up the dagger" << endl << endl;
return 0;
}
else {
choice.clear();
cout << "That isn't an option, pick again... "<< endl << endl;
sleep_for(1s);
restart = 'y';
}
} while (restart == 'y');
}
When I type in "dagger", it works just fine, but when I type in " the dagger" it says runs the else code, then loops back to "Which do you take" and then chooses "dagger" instantly.
You're using std::cin with the >> operator. This operator reads formatted input (words) instead of unformatted input (lines). Rather than reading "the dagger", your program is simply reading "the", and leaving "dagger" in the input buffer for later.
To read unformatted input to choice, use std::getline(std::cin, choice); instead.
I'm trying to check two separate inputs if they are integers or not. I'm able to error check one input but I'm not quite sure how to check two separate ones if I'm using the 'get' function and both inputs are from the 'cin' stream. Using c++.
My code for checking one integer is displayed below.
#include <iostream>
using namespace std;
int main() {
int input;
cout << "Enter an integer: ";
cin >> input;
char next;
int x=0;
int done = 0;
while (!done){
next = cin.get();
if (next == ' ' || next == '\n'){
cout << "The Integer that you have entered is: " << input << "\n";
done = 1;
}
else if (next == '.'){
cerr << "Error: Invalid Input. Not an Integer." << "\n";
done = 1;
}
else{
cerr << "Error: Invalid Input. Not a number." << "\n";
done = 1;
}
}
return 0;
}
Well you could use >> into an int all the way through, drop all that get() stuff and character handling, and check cin.fail(). For example (I'll leave working this into your program and repeating it in a loop as an exercise for you):
int x;
cin >> x;
if (cin.fail())
cout << "Not a valid integer." << endl;
You can handle all subsequent input in exactly the same way. There's no reason to only limit operator >> to the first input.
I just started learning files and I understand how to set it up and get it to work. I have to write this program where I have to allow the user to enter some information and have the user also update and adjust any data, using binary.
So I can write up until the point where the user can write to and read from the file. But I don't know how to let the user adjust data or add data.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
class client {
public:
string name;
int balance;
string id;
};
int main()
{
int ans;
int x;
string nameIn;
string adjName;
client client1;
ofstream out("client1.dat", ios::binary);
cout << "\nDo you want to add information or update info" << endl;
cin >> ans;
if (ans == 1)
{
cout << "\nPlease enter the name of your client" << endl;
cin >> nameIn;
x = nameIn.length();
if (x <= 10)
{
for (int i; i < 10; i++)
{
adjName[i] = nameIn[i];
}
}
else
{
for (int i = x; i < 10; i++)
{
adjName[i] = ' ';
}
}
client1.name = adjName;
cout << "\nPlease enter the balance of your client" << endl;
cin >> client1.balance;
cout << "\nPlease enter the id of your client" << endl;
cin >> client1.id;
cout << "\nThe name of your client is " << endl << client1.name
<< endl << "\nThe balance of your client is " << endl
<< client1.balance << endl << "\nThe id of your client is "
<< endl << client1.id;
out.write(reinterpret_cast<const char*> (&client1), sizeof(client));
}
/*
else if (ans == 2)
{
string answer, newName,line;
cout << "\nWhat name do you want to update? " << endl;
cin >> answer;
cout << "\nWhat is the new name?" << endl;
cin >> newName;
if (out)
}
*/
system("pause");
return 0;
}
so the name needs to be only 10 characters long, so that we can adjust/update it. It compiles and runs, but every time the compiler gets to the part where it checks the name length, it freaks out and says "debug assertion failed"
string subscript out of range.
Also a thing about this code-- if i run it without the bits where you adjust the name to a certain array length, the program runs, and stores everything nicely. But when I try to read back the .dat, it reads it back but exits with an access violation, forcing me to manually stop the debugging. What am I doing wrong?
this is the code for reading the file
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
class client {
public:
string name;
int balance;
string id;
};
int main()
{
client client1;
char ans;
cout << "\nDo you want to view the information about your client?"
<< endl;
cin >> ans;
ifstream in("client1.dat", ios::binary);
if (ans == 'y' || ans == 'Y')
{
in.read(reinterpret_cast<char*> (&client1), sizeof(client));
cout << "The name is " << endl << client1.name << endl
<< "The balance is " << endl << client1.balance << endl
<< "The id is " << endl << client1.id << endl;
}
system("pause");
return 0;
}
As for the 1st part:
for (int i; i < 10; i++)
// ^
misses to initialize i to zero. Also what if the input was smaller than 10 characters? You're going to access the std::string out of bounds. You should replace the if/else and loops with simply
adjName = nameIn;
while(adjName.length() <= 10) {
adjName += ' ';
}
to get rid of the debug assertion.
For the 2nd part of the question, as already mentioned in the comments you cannot do this with a structure containing classes like std::string.
The reinterpret_cast<char*> (&client1) just obfuscates that std::string uses a pointer to the dynamically allocated character data internally, and that cannot be restored meaningfully when reading the stored data back later (hence the access violation you get).
A viable way might be to use something like
struct client {
char name[11];
int balance;
char id[5];
};
As I guess you need to do this for a homework exercise, and for this purpose that would probably be sufficient.
But you quickly can see the drawbacks, that the character data needs to be fixed in size and you cannot have arbitrary length strings. I never would use such for production ready code.
Another pitfall (as also mentioned) is, that int isn't represented in the same way (order of bytes used, i.e. endianess) in the same way for different CPU architectures. So the binary file can't be used portably with different computers.
The simplest solution is not to use a binary file, but a text formatted file and overload the std::ostream& operator<<(std::ostream&, const client&) and std::istream& operator>>(std::istream&, client&) output/input operators.
Or use some 3rd party library like boost::serialization or google protocol buffers, that supports de-/serialization to binary files.
I posted an earlier question asking for help with using a validation script in my code. After a very helpful answer I was able to sort of figure out how I needed to proceed. Well, I've hit a big obstacle;
#include <iostream>
#include <sstream>
#include <string>
#include <ctype.h>
using namespace std;
int main()
{
unsigned __int64 input = 0;
int n, i;
char str[]="c3po...";
i=1;
n=0;
for (cout << "Input a number" << endl; cin >> input; cin.ignore(numeric_limits<int>::max(), '\n'))
{
cout << "We're parsing your input '" << input << "'\n";
if (input % 2 == 0)
{
cout << "Even!" << endl;
}
else if (input % 2 == 1)
{
cout << "Odd" << endl;
cout << "Lets make it even shall we? " << "Your new number is... " << input + 1 << endl;
}
else (isalnum(str[i]));i++;
{
cout << "We could not parse '" << input << "' as a number.\n";
}
}
system ("pause");
return 0;
}
As you can see from my code, the validation script is well, sort of working. I have some bugs I wish to iron out.
1- When I input a number, it runs though the code as it should but it also displays
Could not parse 'inputted number' as a number
obviously when a number is inputted you don't want this to happen!
2- For the error message, it is showing the inputted number as [0]. Is this to do with using an integer? How can this be fixed?
Thanks!
your problem is quite simple, you have small mistake on this line
else (isalnum(str[i]));
Your else statement ends at the semicolon and does actually nothing. Following statements will be executed every time.
i++;
{
cout << "We could not parse '" << input << "' as a number.\n";
}