I'm writing a library system using struct as seen
struct Book
{
char name[50];
int ID;
char author[50];
double price;
int copies;
};
and the file is organised as seen.
ID Name Author Price Copies
1 HarryPotter Lol 30 5
2 EnglishMan English 30 5
3 Spiderman Marvel 30 5
4 Avengers Marvel 30 5
Let's say I want to use the program to update book no. 2 (EnglishMan) and change its name to IronMan, how can I do that using files?
If you use plain text files as data storage you just have to follow this inconvenient workflow:
Read the complete file into your data structures.
Alter the data.
Truncate or remove the file.
Write all the data into the file.
There are ugly hacks to edit parts of the file, but they don't make things better.
For managing tabular data, as in your example, relational databases have been invented a long time ago. Start to learn SQLite, and your life will be much easier in the long run.
What you are doing is, essentially, trying to create your own database which is counterproductive at best. But if it's for learning file I/O and string streams, following code can help you understand the concepts although It's probably not the most efficient way of doing things.
In general, as #Murphy said, you need to read a file, copy it to a buffer, adjust the buffer to your liking, truncate the file and write your own buffer to the file.
int searchbyID(string filename, string ID, string newName);
int main()
{
searchbyID("d:\\test.txt", "2", "silmarillion");
}
int searchbyID(string filename, string ID, string newName)
{
// open an input file stream
ifstream inputfile(filename);
if (!inputfile)
return -1; // couldn't open the file
string line,word;
string buffer;
// read the file line by line
while (getline(inputfile, line))
{
std::stringstream record(line);
//read the id from the file and check if it's the asked one
record >> word;
if (word == ID)
{
// append the ID first
buffer += ID + "\t";
//append the new name instead of the old one
buffer += newName + "\t";
//pass the old name
record >> word;
//copy the rest of the line just as it is
while (record >> word)
buffer += "\t" + word + "\t";
buffer += "\n";
}
else
{
//if not, just pass the line as it is
buffer += line + "\n";
}
}
// close input file stream
inputfile.close();
// open an output file stream
ofstream outputfile(filename);
// write new buffer to the file
outputfile << buffer;
//close the output file stream
outputfile.close();
return 0;
}
Related
I need to write an 8 ball code that has eleven options to display and it needs to pull from a text file. I have it taking lines from the text file but sometimes it takes an empty line with no writing. And I need it to only take a line that has writing.
Here are that options it needs to draw from:
Yes, of course!
Without a doubt, yes.
You can count on it.
For sure!Ask me later.
I'm not sure.
I can't tell you right now.
I'll tell you after my nap.
No way!I don't think so.
Without a doubt, no.
The answer is clearly NO.
string line;
int random = 0;
int numOfLines = 0;
ifstream File("file.txt");
srand(time(0));
random = rand() % 50;
while (getline(File, line))
{
++numOfLines;
if (numOfLines == random)
{
cout << line;
}
}
}
IMHO, you need to either make the text lines all the same length, or use a database (table) of file positions.
Using File Positions
Minimally, create a std::vector<pos_type>.
Next read the lines from the file, recording the file position of the beginning of the string:
std::vector<std::pos_type> text_line_positions;
std::string text;
std::pos_type file_position = 0;
while (std::getline(text_file, text)
{
text_line_positions.push_back(file_position);
// Read the start position of the next line.
file_position = text_file.tellg();
}
To read a line from a file, get the file position from the database, then seek to it.
std::string text_line;
std::pos_type file_position = text_line_positions[5];
text_file.seekg(file_position);
std::getline(text_file, text_line);
The expression, text_line_positions.size() will return the number of text lines in the file.
If File Fits In Memory
If the file fits in memory, you could use std::vector<string>:
std::string text_line;
std::vector<string> database;
while (getline(text_file, text_line))
{
database.push_back(text_line);
}
To print the 10 line from the file:
std::cout << "Line 10 from file: " << database[9] << std::endl;
The above techniques minimize the amount of reading from the file.
I'm trying to edit a .dat file. I want to read a line by line number, turn the content to int, edit and replace it.
like I want to edit line number 23, it says "45" I need to make it "46". How do I do that?
ofstream f2;
theBook b;
f2.open("/Users/vahidgr/Documents/Files/UUT/ComputerProjects/LibraryCpp/LibraryFiles/Books.dat", ios::app);
ifstream file("/Users/vahidgr/Documents/Files/UUT/ComputerProjects/LibraryCpp/LibraryFiles/Books.dat");
cout<<"In this section you can add books."<<endl;
cout<<"Enter ID: "; cin>>b.id;
cout<<"Enter Name: "; cin>>b.name;
string sID = to_string(b.id);
string bookName = b.name;
string line;
int lineNumber = 0;
while(getline(file, line)) {
++lineNumber ;
if(line.find(bookName) != string::npos && line.find(sID) != string::npos) {
int countLineNumber = lineNumber + 4;
registered = true;
f2.close();
break;
}
}
Inside the file:
10000, book {
author
1990
20
20
}
If your file is small (such as under 1GB), you can just read the entire file into memory line-by-line as a std::vector<std::string> (Hint: use std::getline). Then, edit the required line, and overwrite the file with an updated one.
Iterate Byte for Byte through the file and count line breaks (\n or \r\n on Windows).
After 22 breaks, insert bytes that say “46”. It should overwrite the existing bytes.
If your modifications are the exact size of the original text, you can write back to the same file. Otherwise, you will need to write your modifications to a new file.
Since your file is variable length text, separated by newlines, we'll have to skip lines until we get to the desired line:
const unsigned int desired_line = 23;
std::ifstream original_file(/*...*/);
std::ofstream modified_file(/*...*/);
// Skip lines
std::string text_line;
for (unsigned int i = 0; i < desired_line - 1; ++i)
{
std::getline(original_file, text_line);
modified_file << text_line << std::endl;
}
// Next, read the text, modify and write to the original file
//... (left as an exercise for the OP, since this was not explicit in the post.
// Write remaining text lines to modified file
while (std::getline(original_file, text_line))
{
modified_file << text_line << std::endl;
}
Remember to write your modified text to the modified file before copying the remaining text.
Edit 1: By record / object
This looks like an X-Y problem.
A preferred method is to read in the objects, modify the object, then write the objects to a new file.
I am working on a program that can encode and then decode text in C++. I am using the stack library. The way the program works is that it first asks you for a cypher key, which you put in manually. It then asks for the file name, which is a text file. If it is a normal txt file, it encodes the message to a new file and adds a .iia files extension. If the text file already has a .iia file extension, then it decodes the message, as long as the cypher key is the same as the one used to encode it.
My program does encode and decode, but how many characters it decodes is determined by temp.size() % cypher.length() that is in the while loop in the readFileEncode() function. I think this is what is keeping the entire file from being encoded and then decoded correctly. Another words, the ending file after it has been decoded from say "example.txt.iia" back to "example.txt" is missing a large portion of the text from the original "example.txt" file. I tried just cypher.length() but of course that does not encode or decode anything then. The entire process is determined by that argument for the decoding and encoding.
I cannot seem to find out the exact logic for this to encode and decode all the characters in any size file. Here is the following code for the function that does the decoding and encoding:
EDIT: Using WhozCraig's code that he edited for me:
void readFileEncode(string fileName, stack<char> &text, string cypher)
{
std::ifstream file(fileName, std::ios::in|std::ios::binary);
stack<char> temp;
char ch;
while (file.get(ch))
temp.push(ch ^ cypher[temp.size() % cypher.length()]);
while (!temp.empty())
{
text.push(temp.top());
temp.pop();
}
}
EDIT: A stack is required. I am going to implement my own stack class, but I am trying to get this to work first with the stack library. Also, if there is a better way of implementing this, please let me know. Otherwise, I believe that there is not much wrong with this except to get it to go through the loop to encode and decode the entire file. I am just unsure as to why it stops at, say 20 characters sometimes, or ten characters. I know it has to do with how long the cypher is too, so I believe it is in the % (mod). Just not sure how to rewrite.
EDIT: Ok, tried WhozCraig's solution and I don't get the desired output, so the error now must be in my main. Here is my code for the main:
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
#include <cstdlib>
#include <cctype>
#include <stack>
using namespace std;
void readFileEncode(string fileName, stack<char> &text, string cypher);
int main()
{
stack<char> text; // allows me to use stack from standard library
string cypher;
string inputFileName;
string outputFileName;
int position;
cout << "Enter a cypher code" << endl;
cin >> cypher;
cout << "Enter the name of the input file" << endl;
cin >> inputFileName;
position = inputFileName.find(".iia");//checks to see if the input file has the iia extension
if (position > 1){
outputFileName = inputFileName;
outputFileName.erase(position, position + 3);// if input file has the .iia extension it is erased
}
else
//outputFileName.erase(position, position + 3);// remove the .txt extension and
outputFileName = inputFileName + ".iia";// add the .iia extension to file if it does not have it
cout << "Here is the new name of the inputfile " << outputFileName << endl; // shows you that it did actually put the .iia on or erase it depending on the situation
system("pause");
readFileEncode(inputFileName, text, cypher); //calls function
std::ofstream file(outputFileName); // calling function
while (text.size()){// goes through text file
file << text.top();
text.pop(); //clears pop
}
system("pause");
}
Basically, I am reading .txt file to encrypt and then put a .iia file extension on the filename. Then I go back through, enter the file back with the .iia extension to decode it back. When I decode it back it is gibberish after about the first ten words.
#WhozCraig Does it matter what white space, newlines, or punctuation is in the file? Maybe with the full solution here you can direct me at what is wrong.
just for information: never read file char by char it will take you hours to finish 100Mb.
read at least 512 byte(in my case i read directly 1 or 2Mb ==> store in char * and then process).
If I understand what you're trying to do correctly, you want the entire file rotationally XOR'd with the chars in the cipher key. If that is the case, you can probably address your immediate error by simply doing this:
void readFileEncode(string fileName, stack<char> &text, string cypher)
{
std::ifstream file(fileName, std::ios::in|std::ios::binary);
stack<char> temp;
char ch;
while (file.get(ch))
temp.push(ch ^ cypher[temp.size() % cypher.length()]);
while (!temp.empty())
{
text.push(temp.top());
temp.pop();
}
}
The most notable changes are
Opening the file in binary-mode using std::ios::in|std::ios::binary for the open-mode. this will eliminate the need to invoke the noskipws manipulator (which is usually a function call) for every character extracted.
Using file.get(ch) to extract the next character. The member will pull the next char form the file buffer directly if one is available, otherwise load the next buffer and try again.
Alternative
A character by character approach is going to be expensive any way you slice it. That this is going through a stack<>, which will be backed by a vector or deque isn't going to do you any favors. That it is going through two of them just compounds the agony. You may as well load the whole file in one shot, compute all the XOR's directly, then push them on to you stack via a reverse iterator:
void readFileEncode
(
const std::string& fileName,
std::stack<char> &text,
const std::string& cypher
)
{
std::ifstream file(fileName, std::ios::in|std::ios::binary);
// retrieve file size
file.seekg(0, std::ios::end);
std::istream::pos_type pos = file.tellg();
file.seekg(0, std::ios::beg);
// early exit on zero-length file.
if (pos == 0)
return;
// make space for a full read
std::vector<char> temp;
temp.resize(static_cast<size_t>(pos));
file.read(temp.data(), pos);
size_t c_len = cypher.length();
for (size_t i=0; i<pos; ++i)
temp[i] ^= cypher[i % c_len];
for (auto it=temp.rbegin(); it!=temp.rend(); ++it)
text.push(*it);
}
You still get your stack on the caller-side, but I think you'll be considerably happier with the performance.
I'm trying to write a program that reads in a CSV file (no need to worry about escaping anything, it's strictly formatted with no quotes) but any numeric item with a value of 0 is instead just left blank. So a normal line would look like:
12,string1,string2,3,,,string3,4.5
instead of
12,string1,string2,3,0,0,string3,4.5
I have some working code using vectors but it's way too slow.
int main(int argc, char** argv)
{
string filename("path\\to\\file.csv");
string outname("path\\to\\outfile.csv");
ifstream infile(filename.c_str());
if(!infile)
{
cerr << "Couldn't open file " << filename.c_str();
return 1;
}
vector<vector<string>> records;
string line;
while( getline(infile, line) )
{
vector<string> row;
string item;
istringstream ss(line);
while(getline(ss, item, ','))
{
row.push_back(item);
}
records.push_back(row);
}
return 0;
}
Is it possible to overload operator<< of ostream similar to How to use C++ to read in a .csv file and output in another form? when fields can be blank?
Would that improve the performance?
Or is there anything else I can do to get this to run faster?
Thanks
The time spent reading the string data from the file is greater than the time spent parsing it. You won't make significant time savings in the parsing of the string.
To make your program run faster, read bigger "chunks" into memory; get more data per read. Research on memory mapped files.
One alternative way to handle this to get better performance is to read the whole file into a buffer. Then go through the buffer and set pointers to where the values start, if you find a , or end of line put in a \0.
e.g. https://code.google.com/p/csv-routine/
I need to make a program in C++ that must read and write text files line by line with an specific format, but the problem is that in my PC I work in Windows, and in College they have Linux and I am having problems because of line endings are different in these OS.
I am new to C++ and don't know could I make my program able read the files no matter if they were written in Linux or Windows. Can anybody give me some hints? thanks!
The input is like this:
James White 34 45.5 10 black
Miguel Chavez 29 48.7 9 red
David McGuire 31 45.8 10 blue
Each line being a record of a struct of 6 variables.
Using the std::getline overload without the last (i.e. delimiter) parameter should take care of the end-of-line conversions automatically:
std::ifstream in("TheFile.txt");
std::string line;
while (std::getline(in, line)) {
// Do something with 'line'.
}
Here's a simple way to strip string of an extra "\r":
std::ifstream in("TheFile.txt");
std::string line;
std::getline(input, line));
if (line[line.size() - 1] == '\r')
line.resize(line.size() - 1);
If you can already read the files, just check for all of the newline characters like "\n" and "\r". I'm pretty sure that linux uses "\r\n" as the newline character.
You can read this page: http://en.wikipedia.org/wiki/Newline
and here is a list of all the ascii codes including the newline characters:
http://www.asciitable.com/
Edit: Linux uses "\n", Windows uses "\r\n", Mac uses "\r". Thanks to Seth Carnegie
Since the result will be CR LF, I would add something like the following to consume the extras if they exist. So once your have read you record call this before trying to read the next.
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
If you know the number of values you are going to read for each record you could simply use the ">>" method. For example:
fstream f("input.txt" std::ios::in);
string tempStr;
double tempVal;
for (number of records) {
// read the first name
f >> tempStr;
// read the last name
f >> tempStr;
// read the number
f >> tempVal;
// and so on.
}
Shouldn't that suffice ?
Hi I will give you the answer in stages. Please go trough in order to understand the code.
Stage 1: Design our program:
Our program based on the requirements should...:
...include a definition of a data type that would hold the data. i.e. our
structure of 6 variables.
...provide user interaction i.e. the user should be able to
provide the program, the file name and its location.
...be able to
open the chosen file.
...be able to read the file data and
write/save them into our structure.
...be able to close the file
after the data is read.
...be able to print out of the saved data.
Usually you should split your code into functions representing the above.
Stage 2: Create an array of the chosen structure to hold the data
...
#define MAX 10
...
strPersonData sTextData[MAX];
...
Stage 3: Enable user to give in both the file location and its name:
.......
string sFileName;
cout << "Enter a file name: ";
getline(cin,sFileName);
ifstream inFile(sFileName.c_str(),ios::in);
.....
->Note 1 for stage 3. The accepted format provided then by the user should be:
c:\\SomeFolder\\someTextFile.txt
We use two \ backslashes instead of one \, because we wish it to be treated as literal backslash.
->Note 2 for stage 3. We use ifstream i.e. input file stream because we want to read data from file. This
is expecting the file name as c-type string instead of a c++ string. For this reason we use:
..sFileName.c_str()..
Stage 4: Read all data of the chosen file:
...
while (!inFile.eof()) { //we loop while there is still data in the file to read
...
}
...
So finally the code is as follows:
#include <iostream>
#include <fstream>
#include <cstring>
#define MAX 10
using namespace std;
int main()
{
string sFileName;
struct strPersonData {
char c1stName[25];
char c2ndName[30];
int iAge;
double dSomeData1; //i had no idea what the next 2 numbers represent in your code :D
int iSomeDate2;
char cColor[20]; //i dont remember the lenghts of the different colors.. :D
};
strPersonData sTextData[MAX];
cout << "Enter a file name: ";
getline(cin,sFileName);
ifstream inFile(sFileName.c_str(),ios::in);
int i=0;
while (!inFile.eof()) { //loop while there is still data in the file
inFile >>sTextData[i].c1stName>>sTextData[i].c2ndName>>sTextData[i].iAge
>>sTextData[i].dSomeData1>>sTextData[i].iSomeDate2>>sTextData[i].cColor;
++i;
}
inFile.close();
cout << "Reading the file finished. See it yourself: \n"<< endl;
for (int j=0;j<i;j++) {
cout<<sTextData[j].c1stName<<"\t"<<sTextData[j].c2ndName
<<"\t"<<sTextData[j].iAge<<"\t"<<sTextData[j].dSomeData1
<<"\t"<<sTextData[j].iSomeDate2<<"\t"<<sTextData[j].cColor<<endl;
}
return 0;
}
I am going to give you some exercises now :D :D
1) In the last loop:
for (int j=0;j<i;j++) {
cout<<sTextData[j].c1stName<<"\t"<<sTextData[j].c2ndName
<<"\t"<<sTextData[j].iAge<<"\t"<<sTextData[j].dSomeData1
<<"\t"<<sTextData[j].iSomeDate2<<"\t"<<sTextData[j].cColor<<endl;}
Why do I use variable i instead of lets say MAX???
2) Could u change the program based on stage 1 on sth like:
int main(){
function1()
function2()
...
functionX()
...return 0;
}
I hope i helped...