I'm using SAS and trying to automatically pick up today's date and put it into the where clause for a proc freq.
it looks likes this:
proc freq data=data_name;
tables date_col;
where date_col > '30aug2017'd;
run;
Instead of 30aug2017 i want today() but i'm struggling to get this working, i 've tried:
data create_date;
current1 = today();
format current1 date9.;
run;
proc freq data=data_name;
tables date_col;
where date_col > current1;
run;
but the error i get is that variable is not on file
Any help appreciated,
cheers guys
You can use TODAY() directly in your WHERE statement.
where date_col > today();
Related
I have a table where I compare the results week to week.
I have aggregations of old dates using these functions.
%let date_old=%sysfunc(intnx(year,%sysfunc(Today()),-1,s));
%put &=date_old;
proc format;
value vintf low-&date_old = 'OLD' other=[yymmd7.];
run;
/*agregujemy wyniki do daty vintf jako old*/
proc summary data=tablea_new nway;
class policy_vintage;
format policy_vintage vintf.;
var AKTYWNE WYGASLE;
output out=newtabe sum=;
And I would like to do exactly the same, only to aggregate the dates to show the yearly range, i.e. 2021-01-2022-01. Or the current year 2021-01-2021-12. Is the following sample okay? What's the best way to do this?
%let date_future=%sysfunc(intnx(year,%sysfunc(Today()),+12,s));
%put &=date_future;
proc format;
value vintfutr +&date_future= 'FUTURE' other=[yymmd7.];
run;
%let date_old=%sysfunc(intnx(year,%sysfunc(Today()),-1,s));
%let date_future=%sysfunc(intnx(year,%sysfunc(Today()),+1,s));
proc format;
value vintf
low-&date_old = 'OLD'
&date_future-high = 'FUTURE'
other=[yymmd7.]
;
run;
I have the following statement
Proc Freq data =test;
tables gender;
run;
I want this to generate an output based on a condition applied to the gender variable. For example - if count of gender greater than 2 then output.
How can I do this in SAS?
Thanks
If you mean an output dataset, you can put a where clause directly in the output dataset options.
Proc Freq data =sashelp.class;
tables sex/out=sex_freq(where=(count>9));
run;
I'm not aware of how you can accomplish this only using proc freq but you can redirect the output to a data set and then print the results.
proc freq data=test;
tables gender / noprint out=tmp;
run;
proc print data=tmp;
where count > 2;
run;
Alternatively you could use proc summary, but this still requires two steps.
proc summary data=test nway;
class gender;
output out=tmp(where=(_freq_ > 2));
run;
proc print data=tmp;
run;
How can I print (and export to file) monthly and weekly average of value? The data is stored in a library and the form is following:
Obs. Date Value
1 08FEB2016:00:00:00 29.00
2 05FEB2016:00:00:00 29.30
3 04FEB2016:00:00:00 29.93
4 03FEB2016:00:00:00 28.65
5 02FEB2016:00:00:00 28.40
(...)
3078 08MAR2004:00:00:00 32.59
3079 05MAR2004:00:00:00 32.75
3080 04MAR2004:00:00:00 32.05
3081 03MAR2004:00:00:00 31.82
EDIT: I somehow managed to get the monthly data but I'm returning average for each month separately. I would to have it done as one result, namely Month-Average+export it to a file or a data set. And still I have no idea how to deal with weeks.
%macro printAvgM(start,end);
proc summary data=sur1.dane(where=(Date>=&start
and Date<=&end)) nway;
var Value;
output out=want (drop=_:) mean=;
proc print;
run;
%mend printAvgM;
%printAvgM('01jan2003'd,'31jan2003'd);
EDIT2: Here is my code, step by step:
libname sur 'C:\myPath';
run;
proc import datafile="C:\myPath\myData.csv"
out=SUR.DANE
dbms=csv replace;
getnames=yes;
run;
proc sort data=sur.dane out=sur.dane;
by Date;
run;
libname sur1 "C:\myPath\myDB.accdb";
run;
proc datasets;
copy in=sur out=sur1;
select dane;
run;
data sur1.dane2;
set sur1.dane;
date2=datepart(Date);
format date2 WEEKV11.;
run;
The last step results in NOTE: SAS variable labels, formats, and lengths are not written to DBMS tables. and the format of dane2 variable is DATETIME19..
Ok, it's small enough to handle easily then. I would recommend first converting your datetime variable to a date variable using DATEPART() function and then use a format within PROC MEANS. You can look up the WEEKU and WEEKV formats to see if they meet your needs. The code below should be enough to get you started. You could do the monthly without the date conversion, but I couldn't find a weekly format for the datetime variable.
*Fake data generated;
data fd;
start=datetime();
do i=1 to 3000000 by 120;
datetime=start+(i-1)*30;
var=rand('normal', 25, 5);
output;
end;
keep datetime var;
format datetime datetime21.;
run;
*Get date variable;
data fd_date;
set fd;
date_var = datepart(datetime);
date_month = put(date_var, yymon7,);
Date_week = put(date_var, weekv11.);
run;
*Monthly summary;
proc means data=fd_date noprint nway;
class date_var;
var var;
output out=want_monthly mean(var)=avg_var std(var)=std_var;
format date_var monyy7.;
run;
*Weekly summary;
proc means data=fd_date noprint nway;
class date_var;
var var;
output out=want_weekly mean(var)=avg_var std(var)=std_var;
format date_var weekv11.;
run;
Replace date_var with the new monthly and weekly variables. Because these are character variables they won't sort properly.
Hello I am trying to put an specific date from a dataset into a macro so i can use it in a DATA step , but i always get 01-JAN-1960 insteed of the date that i want
my code is the next one:
proc sql noprint ;
select WEEK_START
into :WEEK_START
from date_table
WHERE FW= 5;
quit;
%let start=&WEEK_START;
%LET TODAY= TODAY();
I made this so i can see the date that i want:
DATA TEMP;
DATE =&TODAY;
DATE1= &start;
FORMAT DATE DATE1 datE11.;
RUN;
And the result is:
DATE : 06-OCT-2014
DATE1 : 01-JAN-1960
proc sql noprint ;
select today()-1 as WEEK_START
into :WEEK_START
from maps.africa;
quit;
%let start=&WEEK_START;
%LET TODAY= TODAY();
DATA TEMP;
DATE =&TODAY;
DATE1= &start;
FORMAT DATE DATE1 datE11.;
RUN;
When I run this, both populate correctly.
Additionally, the value of Date1 in your example is the date value for the numeric value of 0. It looks like your original data is being populated incorrectly.
I have a SAS dataset similar to the one created here.
data have;
input date :date. count;
cards;
20APR2012 10
20APR2012 20
20APR2012 20
27APR2012 15
27APR2012 5
;
run;
proc sort data=have;
by date;
run;
I want to create a column containing the sum for each date, so it would look like
date total
20APR2012 50
27APR2012 20
I have tried using first. but I think my syntax is off. Thanks.
This is what proc means is for.
proc means data=have;
class date;
var count;
output out=want sum=total;
run;
The code below works to give you your desired result.
proc sql;
create table wanted_tab as
select
date format date9.,
sum(count) as Total
from have
group by date;
;
quit;