what I wanna do is
change
1.apple2.cat3.green(1)table(2)computer①what②can i③do?●help●me●plz
this to
1.apple
2.cat
3.green
(1)table
(2)computer
①what
②can i
③do?
●help
●me
●plz
this
there're many kind of delimiter
"1.", "2." .. "(1)".."(2)"..■ ○
and so on
number is only a single digit
I want to list many delimiter can split or add linebreak, but keep delimiter
number or bullet should not be deleted.
You can use regex like below:
let s = '1.apple2.cat3.green(1)table(2)computer①what②can i③do?●help●me●plz';
let regex = /(\d\.|\(\d\)|[①-⑳]|●|■|○)[a-z]+/ig;
let result = null;
while (result = regex.exec(s)) {
console.log(result[0]); // or you can push into an array, etc.
}
Related
I want to use Regex to acquire some ID's in a cellstring array, the array looks like this:
myString = '(['US04650Y1001', 'US90274P3029', 'HON WI', 'US41165F1012'])';
My pattern for regex is as follows:
pattern = '[A-Za-z0-9.^_]+';
newArr = regexp(myString, pattern,'match');
I'd like to get the ID called 'HON WI', but with my current pattern, its splitting it into two because my pattern can't deal with the whitespace properly. I would like to get the whole "HON WI", as well as my other strings, everything that's in '', these might have special characters like ^, . or _, but I don't know how to add the whitespace.
I already tried stuff like this, without success:
pattern = '[A-Za-z0-9.^_\s]+';
My new array should have, in each cell, the strings/ID's contained in myString (US04650Y1001, US90274P3029, HON WI and US41165F1012) with dimensions 1x4.
Another approach that seems to work but not entirely sure:
myString = strrep(myString,'([','');
myString = strrep(myString,'])','');
myString = regexp(myString,',','split');
myString = strrep(myString,'''','');
This seems to get me what I want, but I would like to know how can I alter the regex on my first approach.
Many thanks in advance.
You may use a mere '([^']+)' regex and use 'tokens' to get the captures:
myString = '([''US04650Y1001'', ''US90274P3029'', ''HON WI'', ''US41165F1012''])';
pattern = '''([^'']+)''';
newArr = regexp(myString, pattern,'match', 'tokens');
The newArr will look like
{
[1,1] = 'US04650Y1001'
[1,2] = 'US90274P3029'
[1,3] = 'HON WI'
[1,4] = 'US41165F1012'
}
You may option is to use lookaround assertions. The following will match any string made of alphanumeric character or underscore (\w), space (' ') or characters . or ^, that is located between quotes. This will specifically exclude the blank space next to the comma, in the separation between tokens, i.e. ', ' does not give a match.
Note that \s will match any blank space character (including tab, newline), this is why a space is preferred here:
pattern2='(?<='')[\w.^ ]+(?='')';
pattern2 =
(?<=')[\w.^ ]+(?=')
newArr = regexp(myString, pattern2,'match');
newArr'
ans =
'US04650Y1001'
'US90274P3029'
'HON WI'
'US41165F1012'
My requirement is to transform some textual message ids. Input is
a.messageid=X0001E
b.messageid=Y0001E
The task is to turn that into
a.messageid=Z00001E
b.messageid=Z00002E
In other words: fetch the first part each line (like: a.), and append a slightly different id.
My current solution:
val matcherForIds = Regex("(.*)\\.messageid=(X|Y)\\d{4,6}E")
var idCounter = 5
fun transformIds(line: String): String {
val result = matcherForIds.matchEntire(line) ?: return line
return "${result.groupValues.get(1)}.messageid=Z%05dE".format(messageCounter++)
}
This works, but find the way how I get to first match "${result.groupValues.get(1)} to be not very elegant.
Is there a nicer to read/more concise way to access that first match?
You may get the result without a separate function:
val line = s.replace("""^(.*\.messageid=)[XY]\d{4,6}E$""".toRegex()) {
"${it.groupValues[1]}Z%05dE".format(messageCounter++)
}
However, as you need to format the messageCounter into the result, you cannot just use a string replacement pattern and you cannot get rid of ${it.groupValues[1]}.
Also, note:
You may get rid of double backslashes by means of the triple-quoted string literal
There is no need adding .messageid= to the replacement if you capture that part into Group 1 (see (.*\.messageid=))
There is no need capturing X or Y since you are not using them later, thus, (X|Y) can be replaced with a more efficient character class [XY].
The ^ and $ make sure the pattern should match the entire string, else, there will be no match and the string will be returned as is, without any modification.
See the Kotlin demo online.
Maybe not really what you are looking for, but maybe it is. What if you first ensure (filter) the lines of interest and just replace what needs to be replaced instead, e.g. use the following transformation function:
val matcherForIds = Regex("(.*)\\.messageid=(X|Y)\\d{4,6}E")
val idRegex = Regex("[XY]\\d{4,6}E")
var idCounter = 5
fun transformIds(line: String) = idRegex.replace(line) {
"Z%05dE".format(idCounter++)
}
with the following filter:
"a.messageid=X0001E\nb.messageid=Y0001E"
.lineSequence()
.filter(matcherForIds::matches)
.map(::transformIds)
.forEach(::println)
In case there are also other strings that are relevant which you want to keep then the following is also possible but not as nice as the solution at the end:
"a.messageid=X0001E\nnot interested line, but required in the output!\nb.messageid=Y0001E"
.lineSequence()
.map {
when {
matcherForIds.matches(it) -> transformIds(it)
else -> it
}
}
.forEach(::println)
Alternatively (now just copying Wiktors regex, as it already contains all we need (complete match from begin of line ^ upto end of line $, etc.)):
val matcherForIds = Regex("""^(.*\.messageid=)[XY]\d{4,6}E$""")
fun transformIds(line: String) = matcherForIds.replace(line) {
"${it.groupValues[1]}Z%05dE".format(idCounter++)
}
This way you ensure that lines that completely match the desired input are replaced and the others are kept but not replaced.
I would try to replace everything inside this string :
[JGMORGAN - BANK2] n° 10 NEWYORK, n° 222 CAEN, MONTELLIER, VANNES / TARARTA TIs
1303222074, 1403281851 & 1307239335 et Cloture TIs 1403277567,
1410315029
Except the following numbers :
1303222074
1403281851
1307239335
1403277567
1410315029
I have built a REGEX to match them :
1[0-9]{9}
But I have not figured it out to do the opposite that is everything except all matches ...
google spreadsheet use the Re2 regex engine and doesn't support many usefull features that can help you to do that. So a basic workaround can help you:
match what you want to preserve first and capture it:
pattern: [0-9]*(?:[0-9]{0,9}[^0-9]+)*(?:([0-9]{9,})|[0-9]*\z)
replacement: $1 (with a space after)
demo
So probably something like this:
=TRIM(REGEXREPLACE("[JGMORGAN - BANK2] n° 10 NEWYORK, n° 222 CAEN, MONTELLIER, VANNES / TARARTA TIs 1303222074, 1403281851 & 1307239335 et Cloture TIs 1403277567, 1410315029"; "[0-9]*(?:[0-9]{0,9}[^0-9]+)*(?:([0-9]{9,})|[0-9]*\z)"; "$1 "))
You can also do this with dynamic native functions:
=REGEXEXTRACT(A1,rept("(\d{10}).*",counta(split(regexreplace(A1,"\d{10}","#"),"#"))-1))
basically it is first split by the desired string, to figure out how many occurrences there are of it, then repeats the regex to dynamically create that number of capture groups, thus leaving you in the end with only those values.
First of all thank you Casimir for your help. It gave me an idea that will not be possible with a built-in functions and strong regex lol.
I found out that I can make a homemade function for my own purposes (yes I'm not very "up to date").
It's not very well coded and it returns doublons. But rather than fixing it properly, I use the built in UNIQUE() function on top of if to get rid of them; it's ugly and I'm lazy but it does the job, that is, a list of all matches of on specific regex (which is: 1[0-9]{9}). Here it is:
function ti_extract(input) {
var tab_tis = new Array();
var tab_strings = new Array();
tab_tis.push(input.match(/1[0-9]{9}/)); // get the TI and insert in tab_tis
var string_modif = input.replace(tab_tis[0], " "); // modify source string (remove everything except the TI)
tab_strings.push(string_modif); // insert this new string in the table
var v = 0;
var patt = new RegExp(/1[0-9]{9}/);
var fin = patt.test(tab_strings[v]);
var first_string = tab_strings[v];
do {
first_string = tab_strings[v]; // string 0, or the string with the first removed TI
tab_tis.push(first_string.match(/1[0-9]{9}/)); // analyze the string and get the new TI to put it in the table
var string_modif2 = first_string.replace(tab_tis[v], " "); // modify the string again to remove the new TI from the old string
tab_strings.push(string_modif2);
v += 1;
}
while(v < 15)
return tab_tis;
}
I'm trying to split all the words in a string into an array in AS3. The obvious answer of course would be to simply do this:
str.split(/\s/);
The problem here is that I need to be able to tell whether the split occurred on a newline or a space. I'm trying to put the words of a string into draggable boxes, and I want the ones after a newline to go, well, on a new line.
Any idea the best way to go about this? Clearly, the above split method will get rid of the crucial newline character that will tell me what I need to know. Should I use a regex.exec with a while loop, or is there any way to use split to preserve the characters I need?
Example string :
This is an example string
with spaces as well as newlines
and needs a regex
1/ Split the string on newline, get array#1.
array#1 = [ "This is an example string","with spaces as well as
newlines","and needs a regex" ]
2/ For each element in array#1 , split based on your current regex which will break the strings
only on spaces as newlines have already been dealth with, this 2-D array is array#2
array#2 = [
["This","is","an","example","string"] ,
["with","spaces","as","well","as","newlines"],
["and","needs","a","regex"]
]
3/ Process elements of array#2 as you want.
First split you string at the newline
var lines:Array = str.split("\n");
Now you can loop on you lines and split each of these in to seperate words
for(var i:int = 0; i < lines.length; i++){
var words = str[i].split(" ");
for(var j:int = 0; j < words.length; j++){
trace("word", words[i]);
}
trace("newline");
}
I have a fixed width text file where each field is given 20 characters total. Usually only 5 characters are used and then there is trailing whitespace. I'd like to use the Split function to extract the data, rather than the Match function. Can someone help me with a regex for this? Thanks in advance.
I would do this with string manipulation, rather than regex. If you're using JavaScript:
var results = [];
for (i = 0; i < input.length; i += 20) {
results.push(input.substring(i, i + 20));
}
Or to trim the whitespace:
var results = [];
for (i = 0; i < input.length; i += 20) {
results.push(input.substring(i, i + 20).replace(/^\s+|\s+$/g, ''));
}
If you must use regex, it should just be something like .{20}.
Split on whitespaces and get the first returned element. This is under the assumption that you do not have whitespaces within the actual data.
cheers
If you must:
^(.{20})(.{20})(.{20})$ // repeat the part in parentheses for each field
You still need to trim each field to remove trailing whitespace.
It seems simpler to use substr() or your languages equivalent. Or in PHP you could use str_split($string, 20).