How to set an image in imageview swift 3? - swift3

Question

So I have an image view titled cashOrCredit and have am trying to set it's image programatically but somehow not able to.
First I set the image like this
cell.cashOrCredit.image = UIImage(named: "cash1.png")
and I get an error saying a separator of "," is needed.
Then I tried it this way
var cashImage: UIImage?
cashImage = "cash1.png"
cell.cashOrCredit.image = cashImage
But I get a THREAD 1 EXC BAD INSTRUCTION error.
I can't seem to understand what is going wrong ?
Here is the error

Answer 1

Updated for Swift 3:
use below simple code, to set the image to UIImageView;
class YourViewControllerName: UIViewController {
var mYourImageViewOutlet: UIImageView?
func addImageToUIImageView{
var yourImage: UIImage = UIImage(named: "Birthday_logo")!
mYourImageViewOutlet.image = yourImage
} // call this function where you want to set image.
}
Note: "Birthday_logo" type of image must be present in your Assets.xcassets of your project.
I attached the screenshot if you want any help please refer it.
****// used anywhere you want to add an image to UIImageView. [Here I used one function & in that function, I write a code to set image to UIImageView]****
Enjoy..!

Answer 2

Try this:
cell.cashOrCredit.image = UIImage(named: "cash1")
and check "cash1.png" image is available in Assets.xcassets or not.
If you get solution, then give upvote to my answer.

Answer 3

Delete ".png":
cell.cashOrCredit.image = UIImage(named: "cash1")
You can also set it all programmatically:
let cellImage = UIImageView(frame: CGRect(x: X, y: Y, width: WIDTH, height: HEIGHT))
cellImage.image = UIImage(named: "cash1")
cell.addSubview(cellImage)

Answer 4

Take Outlet of ImageView
#IBOutlet weak var imgProfile: UIImageView!
Go through the following code which contains will be helpful you to pick image or capture image from the camera.
func choosePicker() {
let alertController = UIAlertController(title: "Select Option", message: nil, preferredStyle: (IS_IPAD ? UIAlertControllerStyle.alert : UIAlertControllerStyle.actionSheet))
let cancelAction = UIAlertAction(title: "Cancel", style: UIAlertActionStyle.cancel, handler: { action -> Void in
})
let gallery = UIAlertAction(title: "From Gallery", style: UIAlertActionStyle.default
, handler: { action -> Void in
self.openPicker(isCamera: false)
})
let camera = UIAlertAction(title: "Take Photo", style: UIAlertActionStyle.default
, handler: { action -> Void in
self.openPicker(isCamera: true)
})
alertController.addAction(gallery)
alertController.addAction(camera)
alertController.addAction(cancelAction)
self.present(alertController, animated: true, completion: nil)
}
func openPicker(isCamera : Bool) {
let picker:UIImagePickerController?=UIImagePickerController()
if isCamera {
picker!.sourceType = UIImagePickerControllerSourceType.camera
} else {
picker!.sourceType = UIImagePickerControllerSourceType.photoLibrary
picker!.allowsEditing = true
}
picker?.delegate = self
if UIDevice.current.userInterfaceIdiom == .phone {
self.present(picker!, animated: true, completion: nil)
}
else {
picker!.modalPresentationStyle = .popover
present(picker!, animated: true, completion: nil)//4
picker!.popoverPresentationController?.sourceView = imgProfile
picker!.popoverPresentationController?.permittedArrowDirections = UIPopoverArrowDirection.up
}
}
// MARK: - UIImagePickerControllerDelegate Methods
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
if let image = info[UIImagePickerControllerOriginalImage] as? UIImage {
self.imgProfile.image = image
}
picker.dismiss(animated: true, completion: nil);
}
func imagePickerControllerDidCancel(_ picker: UIImagePickerController) {
dismiss(animated: true, completion: nil)
}
Call choosePicker method wherever you want to call.

Answer 5

Check if cashOrCredit is uiimageview.
Secondly,
cashImage = UIImage(named: "cash1.png")
If that doesnot work, try
cell?. cashOrCredit.image
check if cell is nil?
In the context of Swift code, EXC_BAD_INSTRUCTION usually means you’ve hit a compiler trap, that is, an undefined instruction inserted into the code by the compiler because of a bug detected at runtime. The most common cause of these are:
failure to unwrap an optional — This can be a forced unwrap (!) or an implicit unwrap (accessing an implicitly unwrapped optional that’s nil).
array out of bounds
a failed forced cast (as!), either because the value was a nil optional or because the value was of the wrong type