gdb wrong filename in shared library - c++

Question

Trying to learn fmbt ,in the c++ test it is using a shared library, the source file of the shared library is preprocessed from another file as in the following make output shows:
g++ -O0 -g -Wall -pedantic -I../../src -I/usr/include/fmbt -fPIC -c -o mycounter.o mycounter.cc
fmbt-aalc -o mycountertest.cc mycountertest.cc.aal
g++ -O0 -g -Wall -pedantic -I../../src -I/usr/include/fmbt -fPIC -c -o mycountertest.o mycountertest.cc
g++ -shared -o mycountertest.so mycounter.o mycountertest.o
When I am trying to debug the shared the library, it always go to the mycountertest.cc.aal file:
ubuntu#i-hics5mzq:~/fMBT/examples/c++-unittest$ gdb fmbt
GNU gdb (Ubuntu 7.7.1-0ubuntu5~14.04.3) 7.7.1
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Reading symbols from fmbt...done.
(gdb) break awrapper.cc:149
Breakpoint 1 at 0x585e06: file awrapper.cc, line 149.
(gdb) run test.conf
Starting program: /usr/local/bin/fmbt test.conf
[Thread debugging using libthread_db enabled]
Using host libthread_db library "/lib/x86_64-linux-gnu/libthread_db.so.1".
<fmbt_log>
<version>
0.38-1
</version>
<conf_load>
<conf_file name="test.conf"/>
<end_time time="1501727367.947618"/>
</conf_load>
<conf_execute>
<action_name name="iCreate"/>
<action_name name="iDestroy"/>
<action_name name="iIncrement"/>
<action_name name="iReset"/>
<action_name name="iCount"/>
<test_engine>
<tags enabled=""/>
<status steps="0" coverage="0.000000" scov="0.000000e+00"/>
<current_time time="1501727366.958535"/>
<suggested_action type="input" name="iCreate" time="1501727366.958600"/>
Breakpoint 1, Awrapper::execute (this=0x93b6d0, action=std::vector of length 1, capacity 1 = {...}) at awrapper.cc:149
149 int tmp=ada->adapter_execute(1,"");
(gdb) s
_gen_mycountertest::adapter_execute (this=0x94ce50, action=1, param=0x65f8b0 "") at mycountertest.cc.aal:27
27 adapter() {
why gdb is not using the generated mycountertest.cc file.
here is the mycountertest.cc content, does the special class name has something to do with it ? :
#line 3 "mycountertest.cc.aal"
#include "mycounter.h"
#include "aal.hh"
class _gen_mycountertest:public aal {
private:
#line 6 "mycountertest.cc.aal"
//variables
MyCounter* mycounter;
int value;
//action1: "iCreate"
#line 17 "mycountertest.cc.aal"
bool action1_guard(const std::string& name) {
{
return mycounter == NULL;
}
return true;//default
}

Answer 1

why gdb is not using the generated mycountertest.cc file
Because it was told not to. In particular, this line:
#line 17 "mycountertest.cc.aal"
bool action1_guard(const std::string& name) {
tells GCC to tell GDB that whatever code follows was generated from line 17 of mycountertest.cc.aal, so that's what GDB will show.
Usually that's exactly what one wants for generated code.
You can safely strip the #line directives from mycountertest.cc before compiling it, and then GDB will show you the generated source:
fmbt-aalc mycountertest.cc.aal | sed -e '/^#line/d' > mycountertest.cc