I have a blog and users can comment any articles. For now, when they post an URL, we can not follow the link by a clic. Because there is no tag.
I know we can display HTML by using the filter "|safe". But I don't want a user using all html tag for security reasons.
I just want to make URL like "http://google.fr" as active and cliquable.
Any idea ?
The urlize filter does exactly what you want.
Related
I'm creating a web page on Django,
I want to create next and previous post in the bottom of blog page.
is there any way to use a simple tag like {{post.title}} in HTML and refer it to view page to find the index of current post ?
This is where you should use pagination. If you are using DRF you might need this pagination.
I am building a blog in django and am using django-taggit. I'm trying to figure out how to tie the link of a tag to a search result page that shows all of the posts using that tag.
I already have the search page created, I know how to filter queries to the page to bring the correct results, and know how to link to the page itself {% url 'search' %}. But how would I pass queries to the page from the template?
For instance, if I have a post tagged "dog" I want users to be able to click on the tag "dog" and be taken to the search page that only has results for posts also tagged "dog".
The django documentation for class views does not have examples of this. And every tutorial resource so far has been focused on the filtering and displaying of the search page itself rather than linking to it with desired queries in an <a> tag instead of a <form>.
In short, how do you make an <a> link pass a query into a url, like how an <input> would to a <form> action in Django?
I found the answer. Based on this , it is
<a href="{% url 'myview' %}?q=foobar">
I originally followed this tutorial (https://django-haystack.readthedocs.org/en/latest/tutorial.html), and have so far been able to highlight my query within my returned results. However, I want to highlight this same query when visiting the next page that I load with a separate template. Is there any way to save/access this query so that I can highlight the same results within this other template?
Whenever I try and include a statement like this, I get an error, which I'm thinking is because I'm not trying to access the query properly.
{% highlight section.body with query html_tag "span" css_class "highlighted" %}
You have to send to the next page, the information that you use to highlight the results in the first page. You can use the request.session to store the data and call it in the next page, or you can send the sqs by the url to the next page.
If you want to know how to manage the search query set, and how to edit that kind of stuff, I recommend you to read the views.py forms.py and the elasticsearch_backend in the haystack folder at: "/usr/local/lib/python2.7/dist-packages/haystack"
This is the url for the documentation of Django Session: Django Session
This is the url for the documentation to pass parameters trhough url: URL dispatcher
I have a form with 6-7 fields. After user input, my webapp searches for those fields in a database and displays the results.
Now the issue is, that the URL ends up having all the form field names and their values in it.
result/?name=lorem&class=arc&course=ipsum
Now with the form having 7-8 fields the url ends up looking ugly.
Is there a Django technique to 'hide' these from the URL? Quotes around hide because I'd be okay with a completely different way to pass the objects to my database from the form as well.
Use a POST request. Here's the django docs on forms and a specific example using POST>. HTML-wise, all you need to do is change the method on the form tag.
I do not recommend to use POST requests for search. If you'll use GET it will be easer for user, he can just bookmark a link and save search or share search results with friends.
I have a question: how to get the current path of the url. Let's say, I have 3 navigation bars, about , blog and contact page. In each page, I have facebook, twitter and a manual email a friend button. When I clicked the email a friend button, and the current URL is www.example.com/about, the current URL is now already www.example.com/emailafriend. How can I get the www.example/about? Also in blog and contact. Please help me. Thanks.
How does your email a friend button work? Is it a django view that takes the current URL and emails it? If so, you don't want the "current" URL, which, as you note, is actually the email a friend URL. What you want to do is pass the URL you want to share as a URL parameter, ie:
/share?url=http://www.example.com/blog
Adding more info based on comments:
When I was referencing URL above, I was not referring to your django URL configuration. Let's take a step back.
On your About page you have a link to email a friend, right? That link is probably generated in your template, but it's the same on every page. Something like:
Email a friend
Instead of this, try this:
Email a friend
Now you need to make your email_a_friend view handle this. It can get the url via
request.get('url', '').
Some additional information:
You might want to escape the {{ request.get_full_path }} function so that it's escaped and URL safe, then you'll have to unescape it in your view. Once you get the URL back to your view, you can do as you please with it.
{{ request.get_full_path|urlencode }}
Try using Relative URLs like for example From www.example.com/about to get to www.example.com/email use /email. Using relative urls is the simplest solution .
Take a look at this.
Absolute vs relative URLs
It sounds like your want to get the referring URL (the URL that sent you to the current page). That is available to you in the request object, although it is not 100% reliable:
request.META['HTTP_REFERER']
See the documentation on HttpRequest objects for more information.