Get the numbers after ":" and count them with the help of powershell - regex

Question

Could someone please help me with extracting and counting the numbers from a text file with PowerShell?
Example: c:\temp\1.txt is some text with semicolon and numbers after them. I need to sum all of these numbers.
blablabl:5 dzfdsfdsfsdfsf:10
sdfsdfsdfdffs:8sdfsfsfdsfdsf:111
5+10+8+111...
What I've tried so far:
$LogText = "C:\temp\1.txt"
[regex]$Regex = "\. (\d+):[1]"
$Matches = $Regex.Matches($LogText)
$Matches | ForEach-Object {
Write-Host $Matches
}
#$array = #()
#$array = new-object collections.arraylist
$array = while ($Matches.Success) {
Write-Host $array[i++]
}
# -------------------------------------------------------------------
$text = Get-Content "C:\temp\1.txt"
[regex]$Regex = "\d"
$Matches = $Regex.Matches($text)
# -------------------------------------------------------------------
$pos = $text.IndexOf(":")
$rightPart = $text.Substring($pos+1)
Write-Host $rightPart

Answer 1

Use Select-String to extract the matches from the file and Measure-Object to do the calculation.
Select-String -Path 'C:\temp\1.txt' -Pattern '(?<=:)\d+' -AllMatches |
Select-Object -Expand Matches |
Select-Object -Expand Value |
Measure-Object -Sum |
Select-Object -Expand Sum
(?<=:) is a positive lookbehind assertion to match the colon preceding the number without making it part of the match.

Answer 2

Try it like that:
$txt=
#"
blablabl:5 dzfdsfdsfsdfsf:10
sdfsdfsdfdffs:8sdfsfsfdsfdsf:111
"#
[regex]$Regex = '\d+'
$sum=0;
$Regex.Matches($txt) | ForEach-Object {
$val = [int]$_.Value
$val
$sum+=$val
}
$sum