Django Admin Actions on single object - django

Question

The admin actions seem to work on several items selected in the list view of django admin interface:
In my case I would like to have a simple action button on the change (one item) view.
Is there a way to make the django admin actions available there?
I know that I can walk around this problem by going to the list view, and select one item there. But it would be more nice to have it directly available.

Answer 1

Create a template for your model in your app.
templates/admin/<yourapp>/<yourmodel>/change_form.html
With this example content to add a button when changing an existing object.
{% extends "admin/change_form.html" %}
{% block submit_buttons_bottom %}
{{ block.super }}
{% if original %} {# Only show if changing #}
<div class="submit-row">
<a href="{% url 'custom-model-action' original.pk %}">
Another action
</a>
</div>
{% endif %}
{% endblock %}
Link that action to any url and redirect back to your model change object view. More information about extending admin templates.
Update: Added complete common use case for custom action on existing object
urls.py
urlpatterns = [
url(r'^custom_model_action/(?P<object_pk>\d+)/$',
core_views.custom_model_action, name='custom-model-action')
]
views.py
from django.urls import reverse
from django.contrib import messages
from django.http import HttpResponse, HttpResponseRedirect
def custom_model_action(request, object_pk):
messages.info(request, 'Performed custom action!')
return HttpResponseRedirect(
reverse('admin:<yourapp>_<yourmodel>_change', args=[object_pk])
)

Answer 2

If you realy need per-single object, I suggest you to use this solution, eg:
class Gallery(TimeStampedModel):
title = models.CharField(max_length=200)
attachment = models.FileField(upload_to='gallery/attachment/%Y/%m/%d')
def __str__(self):
return self.title
def process_button(self):
return ('<button id="%(id)s class="btn btn-default process_btn" '
'data-value="%(value)s>Process</button>' % {'id': self.pk, 'value': self.attachment.url})
process_button.short_description = 'Action'
process_button.allow_tags = True
In your admin.py, insert process_button into list_display;
class GalleryAdmin(admin.ModelAdmin):
list_display = ['title', 'process_button', 'created']
search_fields = ['title', 'pk']
....
class Media:
js = ('path/to/yourfile.js', )
Then, inside yourfile.js, you can also process it..
$('.process_btn').click(function(){
var id = $(this).attr('id'); // single object id
var value = $(this).data('value'); // single object value
...
});
Hope it helpful..

Answer 3

Not the same as the topic starter asked, but this snippet allows to have Single Object action from on the list page with minimum amount of code
BaseAction code
class AdminActionError(Exception):
pass
class AdminObjectAction:
"""Base class for Django Admin actions for single object"""
short_description = None
exp_obj_state = {}
def __init__(self, modeladmin, request, queryset):
self.admin = modeladmin
self.request = request
self.queryset = queryset
self.__call__()
def validate_qs(self):
count = self.queryset.count()
if count != 1:
self.error("You must select one object for this action.")
if self.exp_obj_state:
if self.queryset.filter(**self.exp_obj_state).count() != 1:
self.error(f'Selected object does not meet the requirements: {self.exp_obj_state}')
def error(self, msg):
raise AdminActionError(msg)
def get_object(self):
return self.queryset.get()
def process_object_action(self, obj):
pass
def validate_obj(self, obj):
pass
def __call__(self, *args, **kwargs):
try:
self.validate_qs()
obj = self.get_object()
self.validate_obj(obj)
except AdminActionError as e:
self.admin.message_user(self.request, f"Failed: {e}", level=messages.ERROR)
else:
with transaction.atomic():
result = self.process_object_action(obj)
self.admin.message_user(self.request, f"Success: {self.short_description}, {result}")
Custom Action [minimum amount of code]
class RenewSubscriptionAction(AdminObjectAction):
short_description = 'Renew subscription'
exp_obj_state = {
'child': None,
'active_status': True,
}
def process_object_action(self, obj):
manager = RenewManager(user=obj.user, subscription=obj)
return manager.process()
AdminClass
class SomeAdmin(admin.ModelAdmin):
actions = [RenewSubscriptionAction]

Answer 4

The built-in admin actions operate on a queryset.
You can use a calable for the action you whant or to show something else:
class ProductAdmin(admin.ModelAdmin):
list_display ('name' )
readonly_fields('detail_url)
def detail_url(self, instance):
url = reverse('product_detail', kwargs={'pk': instance.slug})
response = format_html("""{0}""", product_detail)
return response
or using forms
class ProductForm(forms.Form):
name = forms.Charfield()
def form_action(self, product, user):
return Product.value(
id=product.pk,
user= user,
.....
)
#admin.register(Product)
class ProductAdmin(admin.ModelAdmin):
# render buttons and links to
def product_actions(self, obj):
return format_html(
'<a class="button" href="{}">Action1</a> '
'<a class="button" href="{}">Action 2</a>',
reverse('admin:product-action-1', args=[obj.pk]),
reverse('admin:aproduct-action-3', args=[obj.pk]),
)
for more details about using forms