I like to set the max length of text displayed in a NSTextField so that the long text should be truncated and ended with two dots (..).
The problem is that different languages have different lengths even they have same number of characters.
E.g. let myTitle1 = "Lake" // 4 English characters
let myTitle2 = "我的标题" // 4 Chinese characters
let myTitle3 = "A beautiful Lake" // 16 English characters
I like above three titles display with similar (if not exactly same) length in NSTestField like this:
"Lake"
"我的.."
"A be.."
Are there any ways to do it?
thanks
This is a little late but for anyone else looking for an answere. You should not manually truncate text, let the OS do it for you.
Align the textfield in your storyboard as you want it and set the line break to truncate tail.
Also set the textfields compression resistance to a low value else the textfield borders will get pushed instead of the text being trucated.
//MARK:- Login
#IBAction func performLogin(_ sender: Any){
//Username & Password - CHARACTER LIMIT CHECK
guard isLoginFormCharLimitValid else {
return
}
//Need to call API
print("Redy To Call API")
}
//MARK:- Username & Password - CHARACTER LIMIT CHECK
private var isLoginFormCharLimitValid: Bool {
var isLoginFormCharLimitValid: Bool = true
//Username Field Characters Length
let userNameLength = (usernameTextField.stringValue as NSString).length
if userNameLength > AppConstant.IntValues.twofiftyfive.rawValue {
//Need to show Error Message Here
errorLabel.stringValue = LoginValidationMessages.userNameFieldCharacterLimit.localized
isLoginFormCharLimitValid = false
return isLoginFormCharLimitValid
}
//Password Field Characters Length
let passwordLength = (passwordTextField.stringValue as NSString).length
if passwordLength > AppConstant.IntValues.twofiftyfive.rawValue {
//Need to show Error Message Here
errorLabel.stringValue = LoginValidationMessages.passwordFieldCharacterLimit.localized
isLoginFormCharLimitValid = false
return isLoginFormCharLimitValid
}
errorLabel.stringValue = EMPTY_STRING
return isLoginFormCharLimitValid
}
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
guard let text = textField.text else { return true }
let newLength = text.characters.count + string.characters.count - range.length
if(textField == myTitle1){
return newLength <= 4
}else if(textField == myTitle2){
return newLength <= 4
}else{
return newLength <= 16
}
return true // Bool
}
Related
The function I'm running (clearRowContents) in sheet 'Section 2' will clear contents and validation for any checked item (col H) in a list as well as the checkbox itself (col G). The remaining unchecked boxes and list items will then be sorted to clear any blank rows just created by the clearRowContents function. This functions works as tested.
However, if no item is checked (col G == false) and the "clear" button is pressed, how can I have a message pop up letting the user know that they must first check the box next to the item and then press the button to clear its contents from the list? I'm trying to figure out how to write the script for the clearItemMessage function.
Also, for script writing purposes, this sheet will be duplicated many times to create various validation menus for different topics... each sheet will be a different "chapter" in a manual with its own unique set of drop downs (in a MASTER DROPDOWN tab).
link to sheet: https://docs.google.com/spreadsheets/d/1ZdlJdhA0ZJOIwLA9dw5-y5v1FyLfRSywjmQ543EwMFQ/edit?usp=sharing
code:
function clearItemMessage(){
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var checkboxRange = ss.getRangeList("$G$11:$G$25").getValues();
if (checkboxRange == true){
clearRowContents (col);
} else (Browser.msgBox("To delete items, select the box next to the items and then press the delete button."));
}
function clearRowContents (col){ // col is the index of the column to check for checkbox being true
var col = 7; //col G
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var data = ss.getDataRange().getValues();
//Format font & size
var sheetFont = ss.getRange("A:Z");
var boxFont = ss.getRange("$G$11:$G$25");
var listFont = ss.getRange("$H$11:$H$25");
sheetFont.setFontFamily("Montserrat");
boxFont.setFontSize(8)
.setFontColor("#434343")
.setBackground("#ffffff");
listFont.setFontSize(12)
.setFontColor("#434343")
.setBackground("#ffffff");
//clear 'true' data validations
var deleteRanges = data.reduce(function(ar, e, i) {
if (e[col - 1] === true) {
return ar.concat(["H" + (i + 1), "G" + (i + 1)]);
}
return ar;
}, []);
if (deleteRanges.length > 0) {
ss.getRangeList(deleteRanges).clearContent().clearDataValidations();
}
//sort based on checkbox value
var range = ss.getRange("$G$11:$H$25");
range.sort({column: 7, ascending: false});
}
In your situation, how about modifying clearItemMessage() as follows?
Modified script:
function clearItemMessage(){
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var checkboxes = ss.getRange("$G$11:$G$25").getValues();
if (checkboxes.filter(([g]) => g === true).length > 0){ // or if (checkboxes.some(([g]) => g === true)) {
clearRowContents();
} else {
Browser.msgBox("To delete items, select the box next to the items and then press the delete button.");
}
}
From your question, I understood your clearRowContents works. So I proposed to modify clearItemMessage.
In your clearRowContents, var col = 7 is used. So I think that function clearRowContents (col){ can be modified to function clearRowContents (){.
Reference:
filter()
I am using .indexOf() to parse an array in a separate sheet via url and find a string in a header to return a numerical value or -1. Issue is I need to find the string match that is non case sensitive. ie var targetEmail = targetHeader.indexOf("Email"); would need to match "email", "user email", User email", etc. Normally I would use a regex but can't find a way to do this in Apps Script. Please any help would be very much appreciated.
sample code below:
var userHeader = USER.getRange(1, 1, 1, USER.getLastColumn()).getValues()[0];
var targetHeader = importSheet.getRange(1, 1, 1, importSheet.getLastColumn()).getValues()[0];
var ui = SpreadsheetApp.getUi();
var targetEmail = targetHeader.indexOf("Email");
if(targetEmail == -1)
ui.alert("Can not find Email column. Please rename column in source sheet.");
Using Javascript RegExp, you can use the following
let targetEmail = targetHeader.findIndex(h => /email/gi.test(h));
if(targetEmail == -1)
ui.alert("Can not find Email column. Please rename column in source sheet.");
Note: findIndex, let and the function shorthand will only work if your script is using the new V8 runtime.
I personally prefer to name the column I want using Google Sheets named ranges, and then use getNamedRanges(), so I'll be able to find the column number by its range name, regardless of the column heading text. If columns are inserted or deleted, the named range still points to the column you're looking for.
You could solve for this by
(1) joining the array into a string
targetHeader.join()
(2) and then changing the string to lowercase
toLowerCase()
and then looking for "email" (lower case).
var targetHeader = importSheet.getRange(1, 1, 1, importSheet.getLastColumn()).getValues()[0];
targetHeader = targetHeader.join().toLowerCase();
var targetEmail = targetHeader.indexOf('email');
Edit:
To find the column number with the word 'email' in it:
var importSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Sheet101');
var targetHeader = importSheet.getRange(1, 1, 1, importSheet.getLastColumn()).getValues()[0];
var flag = false;
for (var c = 0; c < targetHeader.length; c++) {
var cellValue = targetHeader[c].toLowerCase();
if (cellValue.indexOf('email') > -1) {
flag = true;
break;
}
}
if (!flag) {
// ui alert that email not found
} else {
var columnWithEmalInHeader = c + 1;
// column with value 'email' found. Column number is c+1
// first time match of 'email' will pop-up here. All subsequent amounts will be ignored.
}
I want an input to follow the following format:
[00-23]:[00-59]
We use angular 2.4 so we don't have the pattern directive available and I cannot use external libraries (primeNG).
So I'm trying to make a directive for that:
#HostListener('keyup', ['$event']) onKeyUp(event) {
var newVal = this.el.nativeElement.value.replace(/\D/g, '');
var rawValue = newVal;
// show default format for empty value
if(newVal.length === 0) {
newVal = '00:00';
}
// don't show colon for empty groups at the end
else if(newVal.length === 1) {
newVal = newVal.replace(/^(\d{1})/, '00:0$1');
} else {
newVal = newVal.replace(/^(\d{2})(\d{2})/, '$1:$2');
}
// set the new value
this.el.nativeElement.value = newVal;
}
This works for the first 2 digits I enter.
Starting string:
00:00
Pressing numpad 1:
00:01
pressing numpad 2:
00:12
But on the third digit I get:
00:123
Instead of 01:23 and 00:1234 instead of 12:34
Backspace works as expected.
Is there a solution to this problem using only a directive?
In the last rejex try replace(/^(\d{0,2})(\d{0,2})/g, '$1:$2'). Hope this will help.
I'm trying to make it so an NSTextField will only accept numbers and periods like 12.4 and 3.6 in a Mac app.
I feel like I'm getting pretty close after reviewing other SO questions, but I can't quite get it. The below code works except that it won't allow . characters. It returns true and doesn't beep at me when I type a . but it won't let the character appear in the field.
class decimalFormatter: NumberFormatter {
override func isPartialStringValid(_ partialString: String, newEditingString newString: AutoreleasingUnsafeMutablePointer<NSString?>?, errorDescription error: AutoreleasingUnsafeMutablePointer<NSString?>?) -> Bool {
//Allows the text to be deleted
if partialString.isEmpty {
return true
}
//Check for #.# numbers
let charSet = NSCharacterSet(charactersIn: "1234567890.").inverted
if partialString.rangeOfCharacter(from: charSet) != nil{
NSBeep()
return false
}else{
return true
}
}
}
Any idea what I'm doing wrong?
I found a simpler way to do it. Inside controlTextDidChange I just did this:
let charSet = NSCharacterSet(charactersIn: "1234567890.").inverted
let chars = fieldDuration.stringValue.components(separatedBy: charSet)
fieldDuration.stringValue = chars.joined()
It works great!
#Clifton Labrum solution is really great but it doesn't reduce the field to Decimal (#.#), you can stil put some inputs as 1.2.4 which would lead to an error when trying tu cast it to Float.
Here is a draft of an extension that worked fine for me ( In Swift 4 )
public override func controlTextDidChange(_ obj: Notification) {
if let textfield = obj.object as? NSTextField,
textfield == self.quantityTextField {
var stringValue = textfield.stringValue
// First step : Only '1234567890.' - #Clifton Labrum solution
let charSet = NSCharacterSet(charactersIn: "1234567890.").inverted
let chars = stringValue.components(separatedBy: charSet)
stringValue = chars.joined()
// Second step : only one '.'
let comma = NSCharacterSet(charactersIn: ".")
let chuncks = stringValue.components(separatedBy: comma as CharacterSet)
switch chuncks.count {
case 0:
stringValue = ""
case 1:
stringValue = "\(chuncks[0])"
default:
stringValue = "\(chuncks[0]).\(chuncks[1])"
}
// replace string
textfield.stringValue = stringValue
}
}
This prevent multiple occurences of . , even if I know that's not the best algorithmic way to do this. For instance 1.2.4 becomes 1.2 when pasted, and by keyboard you can't add another .
I'm trying to write part of an add-on for Google Docs that eliminates newlines within selected text using replaceText. The obvious text.replaceText("\n",""); gives the error Invalid argument: searchPattern. I get the same error with text.replaceText("\r","");. The following attempts do nothing: text.replaceText("/\n/","");, text.replaceText("/\r/","");. I don't know why Google App Script does not allow for the recognition of newlines in regex.
I am aware that there is an add-on that does this already, but I want to incorporate this function into my add-on.
This error occurs even with the basic
DocumentApp.getActiveDocument().getBody().textReplace("\n","");
My full function:
function removeLineBreaks() {
var selection = DocumentApp.getActiveDocument().getSelection();
if (selection) {
var elements = selection.getRangeElements();
for (var i = 0; i < elements.length; i++) {
var element = elements[i];
// Only deal with text elements
if (element.getElement().editAsText) {
var text = element.getElement().editAsText();
if (element.isPartial()) {
text.replaceText("\n","");
}
// Deal with fully selected text
else {
text.replaceText("\n","");
}
}
}
}
// No text selected
else {
DocumentApp.getUi().alert('No text selected. Please select some text and try again.');
}
}
It seems that in replaceText, to remove soft returns entered with Shift-ENTER, you can use \v:
.replaceText("\\v+", "")
If you want to remove all "other" control characters (C0, DEL and C1 control codes), you may use
.replaceText("\\p{Cc}+", "")
Note that the \v pattern is a construct supported by JavaScript regex engine, and is considered to match a vertical tab character (≡ \013) by the RE2 regex library used in most Google products.
The Google Apps Script function replaceText() still doesn't accept escape characters, but I was able to get around this by using getText(), then the generic JavaScript replace(), then setText():
var doc = DocumentApp.getActiveDocument();
var body = doc.getBody();
var bodyText = body.getText();
//DocumentApp.getUi().alert( "Does document contain \\t? " + /\t/.test( bodyText ) ); // \n true, \r false, \t true
bodyText = bodyText.replace( /\n/g, "" );
bodyText = bodyText.replace( /\t/g, "" );
body.setText( bodyText );
This worked within a Doc. Not sure if the same is possible within a Sheet (and, even if it were, you'd probably have to run this once cell at a time).
here is my pragmatic solution to eliminate newlines in Google Docs, or, more exact, to eliminate newlines from Gmail message.getPlainBody().
It looks that Google uses '\r\n\r\n' as a plain EOL and '\r\n' as a manuell Linefeed (Shift-Enter). The code should be self explainable.
It might help to get alone with the newline problem in Docs.
A solution possibly not very elegant, but works like a charm :-)
function GetEmails2Doc() {
var doc = DocumentApp.getActiveDocument();
var body = doc.getBody();
var pc = 0; // Paragraph Counter
var label = GmailApp.getUserLabelByName("_Send2Sheet");
var threads = label.getThreads();
var i = threads.length;
// LOOP Messages within a THREAT
for (i=threads.length-1; i>=0; i--) {
for (var j = 0; j < messages.length; j++) {
var message = messages[j];
/* Here I do some ...
body.insertParagraph(pc++, Utilities.formatDate(message.getDate(), "GMT",
"dd.MM.yyyy (HH:mm)")).setHeading(DocumentApp.ParagraphHeading.HEADING4)
str = message.getFrom() + ' to: ' + message.getTo();
if (message.getCc().length >0) str = str + ", Cc: " + message.getCc();
if (message.getBcc().length >0) str = str + ", Bcc: " + message.getBcc();
body.insertParagraph(pc++,str);
*/
// Body !!
var str = processBody(message.getPlainBody()).split("pEOL");
Logger.log(str.length + " EOLs");
for (var k=0; k<str.length; k++) body.insertParagraph(pc++,str[k]);
}
}
}
function processBody(tx) {
var s = tx.split(/\r\n\r\n/g);
// it looks like message.getPlainBody() [of mail] uses \r\n\r\n as EOL
// so, I first substitute the 'EOL's with the string pattern "pEOL"
// to be replaced with body.insertParagraph in the main function
tx = '';
for (k=0; k<s.length; k++) tx = tx + s[k] + "pEOL";
// then replace all remaining simple \r\n with a blank
s = tx.split(/\r\n/g);
tx = '';
for (k=0; k<s.length; k++) tx = tx + s[k] + " ";
return tx;
}
I have now found out through much trial and error -- and some much needed help from Wiktor Stribiżew (see other answer) -- that there is a solution to this, but it relies on the fact that Google Script does not recognise \n or \r in regex searches. The solution is as follows:
function removeLineBreaks() {
var selection = DocumentApp.getActiveDocument()
.getSelection();
if (selection) {
var elements = selection.getRangeElements();
for (var i = 0; i < elements.length; i++) {
var element = elements[i];
// Only deal with text elements
if (element.getElement()
.editAsText) {
var text = element.getElement()
.editAsText();
if (element.isPartial()) {
var start = element.getStartOffset();
var finish = element.getEndOffsetInclusive();
var oldText = text.getText()
.slice(start, finish);
if (oldText.match(/\r/)) {
var number = oldText.match(/\r/g)
.length;
for (var j = 0; j < number; j++) {
var location = oldText.search(/\r/);
text.deleteText(start + location, start + location);
text.insertText(start + location, ' ');
var oldText = oldText.replace(/\r/, ' ');
}
}
}
// Deal with fully selected text
else {
text.replaceText("\\v+", " ");
}
}
}
}
// No text selected
else {
DocumentApp.getUi()
.alert('No text selected. Please select some text and try again.');
}
}
Explanation
Google Docs allows searching for vertical tabs (\v), which match newlines.
Partial text is a whole other problem. The solution to dealing with partially selected text above finds the location of newlines by extracting a text string from the text element and searching in that string. It then uses these locations to delete the relevant characters. This is repeated until the number of newlines in the selected text has been reached.
This Stack Overflow answer removes, specifically, "\n". It may help, it helped me indeed.