XSLT – Compare node values and pass attributes if nodes are equal - xslt

Question

I am trying to do something that is probably very simple, but my very rudimentary xslt is not up to it.
Given the following XML:
<?xml version="1.0" encoding="UTF-8"?>
<MyLists>
<List1>
<Place01 ctr="PTG">Lisbon</Place01>
<Place02 ctr="SPA">Madrid</Place02>
<Place03 ctr="FRA">Paris</Place03>
<Place04 ctr="ENG">York</Place04>
</List1>
<List2>
<Item01 type="country">Italy</Item01>
<Item02 type="person">John</Item02>
<Item03 type="city">York</Item03>
<Item04 type="city" subtype="capital">Madrid</Item04>
</List2>
</MyLists>
I would like to compare the text nodes from <List1> and <List2>, and, whenever their values are the same, pass, for each element, the attributes from <List2> to the corresponding items in <List1>, in order to get:
<?xml version="1.0" encoding="UTF-8"?>
<MyLists>
<List1>
<Place01 ctr="PTG">Lisbon</Place01>
<Place02 ctr="SPA" type="city" subtype="capital">Madrid</Place02>
<Place03 ctr="FRA">Paris</Place03>
<Place04 ctr="ENG" type="city">York</Place04>
</List1>
<List2>
<Item01 type="country">Italy</Item01>
<Item02 type="person">John</Item02>
<Item03 type="city">York</Item03>
<Item04 type="city" subtype="capital">Madrid</Item04>
</List2>
</MyLists>
Ideally, I'd like to be able to copy whichever attributes these element possess, without having to specify them.
Many thanks in advance!

Answer 1

If I understand this correctly, you could do something like:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="match" match="Item" use="." />
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Place">
<xsl:copy>
<xsl:copy-of select="key('match', .)/#*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>