I am using quill editor to upload an image and the an ajax function is used to send the image to views.py.
This is the python function for uploading the image.
views.py
def upload_image(request):
if request.method == 'POST':
handle_uploaded_file(request.FILES.get('file'))
return HttpResponse("Successful")
return HttpResponse("Failed")
def handle_uploaded_file(file):
with open('upload/', 'wb+' ) as destination:
for chunk in file.chunk():
destination.write(chunk)
This is the ajax request:
function upload(file, callback) {
console.log('called');
var formData = new FormData();
formData.append('file', file);
$.ajax({
url : '{% url 'dashboard:upload_image' %} ',
type : 'POST',
data : formData,
contentType: 'multipart/form-data',
headers: { "X-CSRFToken": $.cookie("csrftoken") },
processData: false,
success: function(data) {
console.log('success');
callback(data.url)
}
});
}
Function calling upload() :
function(value) {
let fileInput = this.container.querySelector('input.ql-image[type=file]');
if (fileInput == null) {
fileInput = document.createElement('input');
fileInput.setAttribute('type', 'file');
fileInput.setAttribute('accept', 'image/*');
fileInput.classList.add('ql-image');
fileInput.addEventListener('change', () => {
if (fileInput.files != null) {
upload();
}
});
this.container.appendChild(fileInput);
}
fileInput.click();
}
}
Error in string
with open('upload/', 'wb+' ) as destination:
Wrong path. Set the file name.
Related
When i send data from ajax to view in Django I am getting none in data. What seems to be the problem. Here is mycode. Where as if i remove processData: false, contentType: false, then data is printed successfully but on file it gives error.
Ajax code
<script>
function submit_data()
{
var type = $('#type').val();
var subtype = $('#subtype').val();
var name = $('#name').val();
var price = $('#price').val();
var weight = $('#weight').val();
var details = $('#details').val();
var picture1 = $('#image1')[0].files[0];
var picture2 = $('#image2')[0].files[0];
var picture3 = $('#image3')[0].files[0];
var vedio_url = $('#vedio_link').val();
alert(picture1)
$.ajax({
url: '/add_record/',
type: 'POST',
headers: { "X-CSRFToken": '{{csrf_token}}' },
processData: false,
contentType: false,
data: {
type,
subtype,
name,
price,
weight,
details,
picture1,
picture2,
picture3,
vedio_url,
},
success: function (response) {
alert("datauploaded successfully!")
},
error: function(){
alert('error')
}
});
}
</script>
View code
def add_record(request):
print("Yes i am here")
type = request.POST.get('type')
subtype = request.POST.get('subtype')
name = request.POST.get('name')
price = request.POST.get('price')
weight = request.POST.get('weight')
details = request.POST.get('details')
picture1 = request.FILES.get('picture1')
picture2 = request.FILES.get('picture2')
picture3 = request.FILES.get('picture3')
vedi_url = request.POST.get('vedio_url')
print (picture1)
print(type)
print(request.POST)
return JsonResponse({'message':'success'},status=200)
Error:
Yes i am here
None
None
<QueryDict: {}>
its returning none, Why is that?
Ajax without files:
Your JS data element should be a dictionary, also remove processData and contentType parameters.
<!doctype html>
<html lang="en">
<head>
</head>
<body>
<input type="text" id="name"/>
<button type="button" id="send" onclick="submit_data()">Send<button/>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.js" integrity="sha512-n/4gHW3atM3QqRcbCn6ewmpxcLAHGaDjpEBu4xZd47N0W2oQ+6q7oc3PXstrJYXcbNU1OHdQ1T7pAP+gi5Yu8g==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
<script>
function submit_data()
{
var name = $('#name').val();
$.ajax({
url: '/add_record/',
type: 'POST',
headers: { "X-CSRFToken": '{{csrf_token}}' },
data: {
'name': name,
},
success: function (response) {
alert(response.data)
},
error: function(){
alert('error')
}
});
}
</script>
</body>
</html>
views:
from django.shortcuts import render
from django.http import JsonResponse
def form_record(request):
return render(request, "mytemplate.html", {})
def add_record(request):
print("Yes i am here")
name = request.POST.get('name')
print(f"Post: {request.POST}")
return JsonResponse({'data': name},status=200)
Ajax with files:
Because you are sending binary data you should to use FormData:
function submit_data()
{
var name = $('#name').val();
var formData = new FormData() // changes here
formData.append('name', name) // and here
$.ajax({
url: '/add_record/',
type: 'POST',
headers: { "X-CSRFToken": '{{csrf_token}}' },
contentType: false, // and here
enctype: 'multipart/form-data', // and here
processData: false, // and here
cache: false,
data: formData, // <-- carefully here
success: function (response) {
alert(response.data)
},
error: function(){
alert('error')
}
});
}
Result:
you can do with a lot of entries please because I have a more complex problem.
in my case I have 6 entries when I enter an entry I have an output in the form of a table and at the end I have to make a final request which will take into account the rows that I have selected.
Excuse my English.
my js :
function submit_data(){
list_fournisseurs = selectcheck();
list_entrepot = selectcheck1();
var numdoc = $('#numdoc').val();
var reference = $('#reference').val();
var reference_doc = $('#reference_doc').val();
var date_debut = $('#date_debut').val();
var date_fin = $('#date_fin').val();
var format_fournisseur = new FormData();
var format_entrepot = new FormData();
var format_numdoc = new FormData();
var format_reference = new FormData();
var format_reference_doc = new FormData();
var format_date_debut = new FormData();
var format_date_fin = new FormData();
const format = [
format_fournisseur.append('list_fournisseurs', list_fournisseurs),
format_entrepot.append('list_entrepot', list_entrepot),
format_numdoc .append('numdoc', numdoc),
format_reference.append('reference', reference),
format_reference_doc.append('reference_doc', reference_doc),
format_date_debut.append('date_debut', date_debut),
format_date_fin.append('date_fin', date_fin),
]
$.ajax({
type : 'POST',
url : 'fournisseur_ajax',
data : {
'csrfmiddlewaretoken': csrf,
'format' : format,
},
//processData: false,
success : (res) =>{
console.log('res.data',res.data)
},
error : (err) =>{
console.log(err)
},
})
}
my view
if request.method == "POST" :
check_list_fournisseurs = request.POST.getlist("format_fournisseur[]")
print("########## voici la liste ###########",check_list_fournisseurs)
check_list_entrepot = request.POST.getlist("format_entrepot[]")
print("########## voici la liste ###########",check_list_entrepot)
print("numdoc ",num_doc)
print("item_ref",item_ref)
print("item_doc",item_doc)
print("date_depart", date_debut)
print("date_fin",date_fin)
context ={'check_list_entrepot':check_list_entrepot,"check_list_fournisseurs":check_list_fournisseurs, 'num_doc':num_doc, 'item_ref':item_ref, 'item_doc':item_doc, 'date_debut':date_debut, 'date_fin':date_fin}
return render(request,"final.html",context)
I have a flask app that is supposed to record video and be able to send that video back to my python scripts to be then put into the database.
I've tried to put it into a form but not too sure I'm doing it the right way.
here is my js
audio: false,
video:true
};
if (navigator.mediaDevices === undefined) {
navigator.mediaDevices = {};
navigator.mediaDevices.getUserMedia = function(constraintObj) {
let getUserMedia = navigator.webkitGetUserMedia || navigator.mozGetUserMedia;
if (!getUserMedia) {
return Promise.reject(new Error('getUserMedia is not implemented in this browser'));
}
return new Promise(function(resolve, reject) {
getUserMedia.call(navigator, constraintObj, resolve, reject);
});
}
}else{
navigator.mediaDevices.enumerateDevices()
.then(devices => {
devices.forEach(device=>{
console.log(device.kind.toUpperCase(), device.label);
//, device.deviceId
})
})
.catch(err=>{
console.log(err.name, err.message);
})
}
navigator.mediaDevices.getUserMedia(constraintObj)
.then(function(mediaStreamObj) {
//connect the media stream to the first video element
let video = document.querySelector('video');
if ("srcObject" in video) {
video.srcObject = mediaStreamObj;
} else {
//old version
video.src = window.URL.createObjectURL(mediaStreamObj);
}
video.onloadedmetadata = function(ev) {
//show in the video element what is being captured by the webcam
video.play();
};
let start = document.getElementById('startbtn');
let stop = document.getElementById('btnStop');
let vidSave = document.getElementById('vid2');
let mediaRecorder = new MediaRecorder(mediaStreamObj);
let chunks = [];
start.addEventListener('click', (ev)=>{
mediaRecorder.start();
console.log(mediaRecorder.state);
})
stop.addEventListener('click', (ev)=>{
mediaRecorder.stop();
console.log(mediaRecorder.state);
});
mediaRecorder.ondataavailable = function(ev) {
chunks.push(ev.data);
}
mediaRecorder.onstop = (ev)=>{
let blob = new Blob(chunks, { 'type' : 'video/mp4;' });
for (chunk in chunks) {
console.log(chunk);
}
chunks = [];
let videoURL = window.URL.createObjectURL(blob);
vidSave.src = videoURL;
}
$.post('/video',
{share: videoURL}, function(data) {
})
})
});
and my route in my flask app
#main_bp.route('/video' , methods=['GET', 'POST'])
#login_required
def video():
form = VideoForm()
if form.validate_on_submit():
flash('Video Saved Successfully!')
vid = request.json['share']
print(jsonify(vid))
return redirect('home.html')
return render_template('video.html', form=form, name=current_user.username)```
I also have a VideoForm class as I have been using that for my login forms but I'm not really sure what way the video is coming back to me, as json, images etc.
here is the VideoForm
class VideoForm(FlaskForm):
video = FileField('img')
submit = SubmitField('Save Video')
If anyone knows how or has any tips to point me in the right direction at least that would be great!
Thanks
You can either use a form of the type "multipart/form-data" to transfer the video.
With this variant, the data can be accessed in flask as a file (werkzeug.FileStorage).
let formData = new FormData();
formData.append('video', blob, "video.mp4");
$.ajax ({
url: "/upload",
type: "POST",
data: formData,
processData: false,
contentType: false,
success: function(resp){
console.log(resp);
}
});
#app.route('/upload', methods=['POST'])
def upload():
video = request.files.get('video')
if video:
# process the file object here!
return jsonify(success=True)
return jsonify(success=False)
As a simple alternative, you can also send the data to the server in raw form.
In this case, the data fill the entire post-body and can either be loaded as a whole or from the stream (werkzeug.LimitedStream).
$.ajax ({
url: "/upload",
type: "POST",
data: blob,
contentType: "video/mp4",
processData: false,
success: function(resp){
console.log(resp);
}
});
#app.route('/upload', methods=['POST'])
def upload():
if request.headers.get('Content-Type') == 'video/mp4':
# load the full request data into memory
# rawdata = request.get_data()
# or use the stream
rawdata = request.stream.read()
# process the data here!
return jsonify(success=True)
return jsonify(success=False)
I have the following js code and it uses the signed-url api to get signed urls for uploading content to google storage via Django api.
When I use it with the following code :
xhr.open("PUT", data.signed_url);
xhr.setRequestHeader('Content-Type', file.type);
xhr.send(file);
It works fine and I am able to upload to Google Storage very large files. But obviously, when I do that, I cannot use any progress-bar features of jquery-file-upload.
Can you please suggest on how I should alter the data.submit(), where shall I put it, and how should I change the options or settings prior to submitting. Should I be overriding add or submit callback ?
I feel that there is a missing support for Google Storage with Jquery-file-upload as the only example covers only obsolute Google Blobstore in the following link : https://github.com/blueimp/jQuery-File-Upload/wiki/Google-App-Engine
$("#fileupload").fileupload({
dataType: 'json',
type: 'PUT',
sequentialUploads: true,
submit: function(e, data) {
var $this = $(this);
$.each(data.files, function(index, file) {
// pack our data to get signature url
var formData = new FormData();
formData.append('filename', file.name);
formData.append('type', file.type);
formData.append('size', file.size);
// Step 3: get our signature URL
$.ajax({
url: '/api/getsignedurl/',
type: 'POST',
processData: false,
contentType: false,
dataType: 'json',
headers: {
'X-CSRFToken': Cookies.get('csrftoken'),
},
primary_data: data,
data: formData
}).done(function (data) {
// Step 5: got our url, push to GCS
const xhr = new XMLHttpRequest();
if ('withCredentials' in xhr) {
console.log("With credentials");
xhr.open("PUT", data.signed_url, true);
}
else if (typeof XDomainRequest !== 'undefined') {
console.log("With domainrequest");
xhr = new XDomainRequest();
xhr.open("PUT", data.signed_url);
}
else {
console.log("With null");
xhr = null;
}
//What shall I do to make the following work for uploading GS
this.primary_data.url = data.signed_url;
this.primary_data.headers={'Content-Type': file.type};
this.primary_data.submit();
xhr.onload = () => {
const status = xhr.status;
if (status === 200) {
} else {
alert("Failed to upload 1: " + status);
}
};
xhr.onerror = () => {
alert("Failed to upload 2");
};
//When the code below uncommented, it uploads to GS succesfully.
//xhr.setRequestHeader('Content-Type', file.type);
//xhr.send(file);
});
});
},
Also this is my cors setup for the GS Bucket.
[
{
"origin": ["*"],
"responseHeader": ["Content-Type", "Access-Control-Allow-Origin"],
"method": ["GET", "PUT", "OPTIONS"],
"maxAgeSeconds": 60
}
]
I have a fileupload HTML element in my DOM and it currently gets multiple files and calls "add" function for each file. For each file, a signed url is received from an ajax call to the related api. After the succesful ajax call to api, I want to call the data.submit() method of the parent function which is the function in fileupload method as first argument.
How may I be able to access that just after "xhr.setRequestHeader('Content-Type', file.type);" ?
The primary inspiration is from this link :http://kevindhawkins.com/blog/django-javascript-uploading-to-google-cloud-storage/
$("#fileupload").fileupload({
dataType: 'json',
sequentialUploads: true,
add: function(e, data) {
$.each(data.files, function(index, file) {
// pack our data to get signature url
var formData = new FormData();
formData.append('filename', file.name);
formData.append('type', file.type);
formData.append('size', file.size);
// Step 3: get our signature URL
$.ajax({
url: '/api/getsignedurl/',
type: 'POST',
processData: false,
contentType: false,
dataType: 'json',
headers: {
'X-CSRFToken': Cookies.get('csrftoken'),
},
context: 'hello',
data: formData,
}).done(function (data) {
// Step 5: got our url, push to GCS
const xhr = new XMLHttpRequest();
if ('withCredentials' in xhr) {
xhr.open("PUT", data.signed_url, true);
}
else if (typeof XDomainRequest !== 'undefined') {
xhr = new XDomainRequest();
xhr.open("PUT", data.signed_url);
}
else {
xhr = null;
}
xhr.onload = () => {
const status = xhr.status;
if (status === 200) {
//alert("File is uploaded");
} else {
}
};
xhr.onerror = () => {
};
xhr.setRequestHeader('Content-Type', file.type);
//data.submit();
});
});
},
If the $this = $(this) is defined prior to the $.each loop :
submit: function(e, data) {
var $this = $(this);
$.each(data.files, function(index, file) { ...
Then the following can be used to access the data in the parent function
this.primary_data.headers={'Content-Type': file.type};
this.primary_data.jqXHR = $this.fileupload('send', this.primary_data);
JS
$(function(){
var count=1;
$("#btn").click(function(){
count++;
})
})
views.py
def setparam(request):
counts=range(1,count)
eg.
Like this I want use JS's count to view.py .How can I get it ,is it possible?
You need send this to server.
I guess you ajax for your example.
JS
function send_cont(cont) {
$.ajax({
url: '{% url "your_app.views.your_view" %}',
type: "GET",
data: {
cont: cont
},
success: function (json) {
//Something
},
error: function (json) {
//Something
}
});
}
View
def your_view(request):
cont = request.GET.get('cont'))
#More code