I'm trying to convert this pattern in files
Insert 18333fig0101.png
Figure 1-1. Local version control diagram.
to
![Figure 1-1. Local version control diagram.](../figures/18333fig0101-tn.png)
This is the perl command:
perl -i -0pe 's/^Insert\s*(.*)\.png\s*\n([^\n]*)$/!\[\2](..\/figures\/\1-tn.png)/mg' */*.markdown
This works fine on Mac OS X, but it doesn't work on Windows 10.
I installed perl using pacman -S perl from MSYS2.
This is also not a \r\n issue as I checked there is no \r in the document.
Is this a known issue on Windows? Or, is there something different option needed for Windows?
When I run the same command (after changing single quotes to double quotes), I get the following error message:
Can't do inplace edit without backup.
This is documented in perldiag:
You're on a system such as MS-DOS that gets confused if you try
reading from a deleted (but still opened) file. You have to say -i.bak, or some such.
When I change the command to perl -i.bak ..., it works.
Related
I'm trying to run a sed command on a Windows machine from the command prompt (CMD.exe) but I am struggling to understand the regular expression and how to escape the string properly when running on Windows. Ideally, I want to develop a solution that works across UNIX and Windows.
sed is not available on Windows so I have installed it via the gnuWin32 project which works well.
The unix format for the command is:
sed -i '' -e 's/\\/_next/\\.\\/next/g' out/**.html
Through a process of trial an error I have managed to get this far:
sed -i \'\' -e \'s/\\/_next/\\.\\/next/g\' out/**.html
but I get an error:
sed: -e expression #1, char 27: unterminated address regex
So there's definitely something wrong with my regex, probably the escaping of various parts?
Any ideas how I might go about fixing this?
Update:
I'm getting the code from here where unfortunately only Linux and OSX are covered.
You need to use
sed -i "s/\\/_next/\\.\\/next/g" out/**.html
The Windows GNU sed does not require the '' empty argument after -i option, they can be safely removed.
Also, the sed command in Windows console should be used in double quotes.
For integration tests, I have output that contains full file paths. I want to have my test script replace the user-specific start of the file path (e.g. /Users/uli/) with a generic word (USER_DIR) so that I can compare the files.
The problem, of course, are the slashes in the path. I tried the solutions given here and here, but they don't work for me:
#!/bin/bash
old_path="/Users/uli/"
new_path="USERDIR"
sed -i "s#$old_path#$new_path#g" /Users/uli/Desktop/replacetarget.txt
I get the error
sed: 1: "/Users/uli/Desktop/repl ...": invalid command code u
This is the version of sed that comes with macOS 10.14.6 (it has no --version option and is installed in /usr/bin/, so no idea what exact version).
Update:
I also tried
#!/bin/bash
old_path="/Users/uli/"
old_path=${old_path//\//\\\/}
new_path="USERDIR"
regex="s/$old_path/$new_path/g"
echo $old_path
echo $regex
sed -i $regex /Users/uli/Desktop/replacetarget.txt
But I get the same error. What am I doing wrong?
BSD sed requires an argument following -i (the empty string '' indicates no backup, similar to argumentless -i in GNU sed). As a result, your script is being treated as the backup-file extention, and your input file as the script.
old_path="/Users/uli/"
new_path="USERDIR"
sed -i '' "s#$old_path#$new_path#g" /Users/uli/Desktop/replacetarget.txt
However, sed is a stream editor, based on the file editor ed, so using -i is an indication you are using the wrong tool to begin with. Just use ed.
old_path="/Users/uli/"
new_path="USERDIR"
printf 's#%s#%s#g\nwq\n' "$old_path" "$new_path" | ed /Users/uli/Desktop/replacetarget.txt
Obligatory warning: neither editor is parameterized as such; you are simpling generating the script dynamically, which means it's your responsibility to ensure that the resulting script is valid. (For example, if either parameter contains a ;, it had better be escaped to prevent (s)ed from seeing it as a command separator.)
[Editor's note: The OP has later clarified that he's running bash as part of msysgit, the Git version for Windows.]
I'm trying to get last digits from the string. I have a little script but it doesn't work and i don't know why:
#!bin/bash
TAGS="MASTER_46"
re="_(\d+)"
if [[ ${TAGS}=~$re ]]; then
echo "Find"
echo ${BASH_REMATCH}
echo ${BASH_REMATCH[1]}
fi
The output:
Find
{empty}
{empty}
I am using bash
$ bash --version
GNU bash, version 3.1.20(4)-release
There are several problems:
bash doesn't support \d. Use [0-9].
Whitespace is needed around the operator: $TAGS =~ $re, otherwise bash parses it as [[ -n "$TAGS=~$re" ]].
Path to the shell is /bin/bash, not bin/bash.
Update, based on the OP's clarification re environment and his own findings:
tl;dr:
msysgit (as of version 1.9.5) comes with a bash executable that is compiled without support for =~, the regex-matching operator
A limited workaround is to use utilities such as grep, sed, and awk instead.
To solve this problem fundamentally, install a separate Unix emulation environment such as MSYS or Cygwin, and use git.exe (the core of msysgit) from there.
choroba's answer has great pointers, but let me add that, since you get the following error message:
conditional binary operator expected syntax error near =~
the implication is either that
your bash version is too old to support =~, the regex-matching operator.
your bash version was compiled without regex support
Given that =~ was introduced in bash 3.0 (see http://tiswww.case.edu/php/chet/bash/NEWS) and you're running 3.1.x, it must be the latter, which indeed turned out to be true:
The OP runs msysgit, the official Git version for Windows that comes with bash and a set of Unix utilities.
As it turns out, as of version 1.9.5, the bash executable that comes with msysgit is built without regex support, presumably due to technical difficulties - see https://groups.google.com/forum/#!topic/msysgit/yPh85MPDyfE.
Incredibly, the "Known Issues" section of the release notes does not mention this limitation.
Your best bet is to:
Install MSYS to use as your Unix emulation environment - its bash does come with =~ support (note that msysgit was originally forked from MSYS).
Alternatively, to get better Unix emulation and more tools at the expense of a larger installation footprint and possibly performance, install Cygwin instead.
In MSYS, use only git.exe from msysgit, via the Windows %PATH%.
To that end, be sure to install msysgit with the Run Git from the Windows Command Prompt option - see https://stackoverflow.com/a/5890222/45375
Alternatively, add C:\Program Files\Git\cmd (assumes the default path on 32-bit Windows, on 64-bit Windows it's C:\Program Files (x86)\Git\cmd) manually to your Windows %PATH%, OR extend $PATH in your MSYS ~/.profile file (e.g., PATH="$PATH:/c/program files/git/cmd").
You could hack your msysgit installation, but it hardly seems worth it and I don't know what the side effects are;
If you really wanted to try, do the following: Copy the following files from an MSYS installation's bin directory to msysgit's bin directory: bash.exe, sh.exe, msys-termcap-0.dll - in other words: replace msysgit's bash altogether.
I am trying to search string and replace string in a file. I used the below code:
sed -e 's/{"AP_SESSION_ID"\1\"787"}/{"AP_SESSION_ID"\1\"800"}/g' FILE|tee FILE
but it is not working and the output is like this:
sed: number in \[0-9] invalid
My environment is CYGWIN.
sample file is:
DP_SESSION_ID is a sting for values
DP_SESSION_ID is aplicat
"DP_S42SETTACC_TYPE"\1\"02"
"DP_SAP_CLIENT"\1\"460"
"DP_SAP_COMM_CONNECTION"\1\"JAVA_COMM_TOOL_ANALYZER"
"DP_SAP_CONNECTION"\1\"JAVA_TOOL_ANALYZER"
"DP_SAP_TOOLBI_CONNECTION"\1\"JAVA_TOOLBI_ANALYZER"
"DP_SESSION_ID"\1\"808"
I want search this "DP_SESSION_ID"\1\" sting and replace corresponding number like 808 in file prenatally(windows env), and i wand sing line command in windows bat command or perl command i don't want scrip or program
even i have installed cygwin tool in my server so unix also ok but single line command
server: windows 2008,cygwin x
using tool : datastage server jobs
perl -pi -e 's{" "DP_SESSION_ID"\1\"808 '"}{' "DP_SESSION_ID"\1\"900 '"'"}g' " file name
this code is not working
Please give good solution
You need to "escape" the backslashes by using two in a row:
sed -e 's/{"AP_SESSION_ID"\\1\\"787"}/{"AP_SESSION_ID"\\1\\"800"}/g' FILE|tee FILE
Otherwise the \1 is treated as a backreference, and you have no subgroups (parenthesized expressions) to reference.
Apart from back-slashes, IMO you also need to escape the quotes.
sed -e 's/{\"AP_SESSION_ID\"\\1\\\"787\"}/{\"AP_SESSION_ID\"\\1\\\"800\"}/g' FILE|tee FILE
I insatlled perl on my machine and on giving follows command
perl -e 'print("#INC\n");'
I get this output
/usr/local/lib/perl5/site_perl/5.18.1/x86_64-linux /usr/local/lib/perl5/site_perl/5.18.1
/usr/local/lib/perl5/5.18.1/x86_64-linux /usr/local/lib/perl5/5.18.1 .
But the MACHINE that is working properly gives follows output for the
same command
/usr/local/lib64/perl5 /usr/local/share/perl5/usr/lib64/perl5/vendor_perl
/usr/share/perl5/vendor_perl/usr/lib64/perl5 /usr/share/perl5 .
YOU CAN SEE THE DIFF INT PATH for lib & lib64
How can i correct the above ??
please help
Perl comes pre-installed on every Linux machine - maybe the machine that is working properly uses the stock perl. You can identify the location of the perl executable issuing which perl in the command line.
Also, you can check the perl version by running perl -v - if the perl on the machine that is working is older, it might be the OS perl.
Regarding the ways to manipulate the lib path, have a look at the tutorial that Gabor Szabo wrote regarding How to change #INC to find Perl modules in non-standard locations