I am trying to search for a specific pattern using regex, but I am having a difficult time. I have over 4,000 images, named as three different file sets, named like so...
0001234_name-of-file.jpeg
0001235_name-of-file_100.jpeg
0001236_name-of-file_200.jpeg
What I want to do is JUST search for the files like 0001234_name-of-file.jpeg
I do NOT want any of the files that have the _100 or _200 at the end before the extension.
I would go with that :
^((?!_[21]00).)*$
Which matches strings which do not contain either _100 or _200
Related
I have the following link syntax that needs to be changed:
![[afoldernamenolongerneededandwillbedeprecated/somemarkdownfilename_image1.png]]
I tried (successfully) with this regex to match:
![[].*[\/].*_image[0-9].png[]]]
Although I have a hunch it may not be what I should use. I the novice think it may be only good for matching and not replacing. All images are png's, by the way. All filenames have _image in them, prefixed by the markdown file-name.
Desired end format:
The
![]()
is a known syntax in markdown to reference images. Images will be populated in subdirectories the program/app will find.
It goes without saying I want to run find and replace recursively on some 4000 files containing image references.
I put up the unfinished substitution example here:
https://regex101.com/r/Bl8HJC/1
So to clarify more on what I need. I need the formerly present folder name gone. I don't need it anymore. Then after the slash comes the name of the image, the syntax of which is always: current filename to be proccessed by NotePad++ recursively (it can be a markdown file named Ab, Aba, Abracadabra, etc.) and this filename always serves as prefix, then comes an underscore and 'image' + a number depending on how many images are linked to the markdown file as attachments. The names of the files to go in an attachment folder will look like this:
AB_image3.png
Abracadabra_image2.png
.
.
.
Zodiac_image45.png
I am looking for the right syntax as I couldn't figure it out with the dollar sign.
Cheers,
Otto
I have modified your example to get it working here. What you needed to do is escape the square brackets so they would be interpreted literally, since they have special meaning in regex, and you needed to use a capture group to store the matching value in $1 so you could use it in the replacement.
Regular expression:
!\[\[.*\/(.*_image[0-9]{1,2}\.png)\]\]
Substitution format:
![image]\($1\)
Edit: Question was revised to state that the folder name was unwanted in the final output, so matches are delimited after the final / character in the file path.
Edit 2: Support for file numbers 1 through 99.
I'm struggling to find the right regular expression and after following the answers in other threads don't think this is a duplicate as they didn't solve my specific issue.
I have lots of files and assuming one of them contains text that looks like this:
createdby:me
one of these words should match
Would like to be able to retrieve it by matching to, for example, createdby:me and one.
The closest I've been able to get from a previous example was to use a regular expression like this.
(createdby:me|one)
This does return the file, but it also returns any other files which contain either of the terms—I'd like to return only files with both.
Is there a way to match similarly for and instead of or?
The order isn't important as the createdby:me will always proceed the search term.
Nor do I need to capture the matches.
Try this:
(?:createdby:me[\w\W]*one)|(?:one[\w\W]*createdby:me)
I want to try and ask this as concisely as possible please forgive me if I'm leaving something out. I want the expression to match all cases except where an exact filename string is present.
A backup software I'm using uses regular expressions and I want to setup an exclusion to skip all of a particular file extension type, except I have certain files I need to backup so I don't want them to match.
The files I want to exclude are we'll say for this example *.FLV
(?i).*\.flv
I want to include in my backups three files: abc123.flv, ghk432.flv, and fdw917.flv
This is where I'm having trouble, even just including one file from the three to be included to backup
(?i).*\.flv^(?!(abc123\.flv))&
The expression is being added to an Exclusion List for code42 CrashPlan backup, their support unfortunately cannot assist with complex RegEx expressions.
The closest thing I can supply as an example is their Example 3: Using An Exclude To Include:
.*/Documents/((?!(.*\.(doc|rtf)|.*/)$).)*$
http://support.code42.com/Administrator/3.6_And_4.0/Configuring/Using_Include_And_Exclude_Filters
However it excludes all files within directories named "Documents" and includes any files in those folders with doc or rtf file extensions. I'm trying to create an expression working with file extensions irregardless of folder location.
In my brain logically it seems like I need to write this as some kind of if then else statement but regex is not my forte.
Use an anchored negative look ahead with an alternation for the files you want to keep:
^(?i)(?!.*(abc123|ghk432|fdw917)\.flv).*\.flv
The negative lookahead asserts that the following input does not match its regex, and the pipe character means "or".
Try to put the negative lookahead at the position of the filename in the path:
^([^/]*/)*(?!(abc123|ghk432|fdw917)\.flv$)[^/]*\.flv$
I am trying to find a way to list all file names in a folder that matches this pattern :
20131106XXXXX.pdf
The prefix is the date, and the content and length of XXXX vary across files, and I only care about pdf files.
Anyone could advise a way to do this?
Try this
list.files(path="./yourdir",pattern="[[:digit:]]{8}.*\\.pdf")
You can use regex.
files <- dir(pattern="^[0-9]{8}.*\\.pdf")
I have a bunch of files, some examples are as follows:
/foo1/foo2/bar1.bar2.bar3.answer.jar
/foo1/bar1.bar2.answer.jar
/foo1/foo2/answer.jar
and for all of the above I would like a regex that matches 'answer'. In other words, I'm looking to get an alias for the file that is the portion of the file name after the last dot (or the file name itself if there are no dots) with the file extension (.jar can be guaranteed here to make it simpler) stripped off.
I know I can do this with a more simple regex to split the value up by dots and then get the second last one, but in this case I'm building a back-end thing that will ideally take a regex that is defined in a configuration definition for the given file type, and spit out the alias, which might be different for other file types.
Yep, I'm over-engineering. :)
Any ideas?
Following regex should work for you:
[^/.]+(?=\.jar$)
If using Javascript or a similar flavor where / is regex delimiter then you need to escape / like this:
[^\/.]+(?=\.jar$)
You can use the following regexp: (assuming that the answer part doesn't contain . or /)
[/\.]([^/\.]+)\.jar
The first capturing group is the part what you want to.