How can I Terminate Vector Input Using if statement in C++ - c++

Question

Does anybody have a simple solution to terminate a for loop that inputs values for a vector when a specific value is placed into the vector, but does not store that specified value into the vector?
I have created a random number generator that creates "n" unique values for a vector of size "n". However, when I run my code, the word "done" pops up and the program crashes.
Here is the code:
int main()
{
int i = 0;
vector<int> playerIndex;
vector<int> randGenNum;
vector<string> players;
vector<string> team1;
vector<string> team2;
vector<string> team3;
vector<string> team4;
cout << "Welcome to the Team Selector. \n" << endl;
cout << "A random team of two will be generated for you all." << endl;
cout << "When you are finished entering player names, enter the word \"done\". " << endl;
cout << "Enter the name of the players: \n" << endl;
for(string name; cin >> name;){
players.push_back(name);
if(name == "done"){
players.erase(players.end() - 1);
break;
}else{
playerIndex.push_back(i);
i++;
}
}
cout << "\n";
cout << "Player names: \n";
for(int a=0; a < players.size(); a++){
cout << a + 1 << " - " << players[a] << endl;
}
srand(time(0));
int b =0;
int randNum;
while(b < players.size()){
randNum = 1 +(rand()%players.size());
if(find(randGenNum.begin(), randGenNum.end(), randNum)!= randGenNum.end()){
while(find(randGenNum.begin(), randGenNum.end(), randNum)!= randGenNum.end()){
randNum = 1 +(rand()%players.size());
}
randGenNum.push_back(randNum);
b++;
}else{
randGenNum.push_back(randNum);
b++;
}
}
cout << "\n" <<"This is a test" << endl;
for (int c=0; c < players.size(); c++){
cout << "Generated #: " << randGenNum[c] << endl;
}
int totalPlayers = players.size();
int firstPlayer = randGenNum[0];
int secondPlayer = randGenNum[1];
int thirdPlayer = randGenNum[2];
int fourthPlayer = randGenNum[3];
int fifthPlayer = randGenNum[4];
cout << "\n";
cout << "Team 1 is: " << players[firstPlayer] << " and "<< players[secondPlayer] << "\n" << endl;
cout << "Team 2 is: " << players[thirdPlayer] << " and " << players[fourthPlayer] << "\n" << endl;
return 0;
}

Answer 1

Problem
players.end() - 1 is not a valid iterator.
Solutions 1:
Check the item before adding it to the vector.
for(string name; cin >> name;) {
if(name != "done")
{
players.push_back(name);
playerIndex.push_back(i);
i++;
}
}
Solutions 2:
Use std::vector::pop_back().
for(string name; cin >> name;){
players.push_back(name);
if(name == "done"){
players.pop_back();
break;
}else{
playerIndex.push_back(i);
i++;
}
}