Error when Deleting Node from BST - c++

This genuinely has me stumped. I have a binary search tree of citys that is ordered by the city name. A city also contains the population and GPS coordinates. I want to be able to remove nodes from the tree by City name or city coordinates. I have the delete by name working fine but the GPS coordinates does not work.
When I remove a node by GPS I get a stack-overflow when I try to print the binary tree. Below is some of my code. I cannot understand how it will work fine if I delete by name but not if I delete by coordinates as I am using the same delete method.
The exact error I get is "Unhandled exception at 0x013214D6 in EXE: 0xC00000FD: Stack overflow (parameters: 0x00000001, 0x00152FFC)." This occurs in my print function after I delete by coordinates but not if I delete by name.
bool BinaryTree::DeleteByName(string city)
{
if (GetRoot() != NULL)
{
return (DeleteByName(GetRoot(), city));
}
return false;
}
TreeNode* BinaryTree::DeleteByName(TreeNode *node, string city)
{
if (node == NULL)
{
return node;
}
else if (city < node->Data.name)
{
node->Left = DeleteByName(node->Left, city);
}
else if (city > node->Data.name)
{
node->Right = DeleteByName(node->Right, city);
}
else
{
if (node->Left == NULL && node->Right == NULL)
{
delete node;
node = NULL;
}
else if (node->Left == NULL)
{
TreeNode* temp = node;
node = node->Right;
delete temp;
}
else if (node->Right == NULL)
{
TreeNode* temp = node;
node = node->Left;
delete temp;
}
else
{
cout << "Else";
TreeNode* temp = MinPtr(node->Right);
node->Data = temp->Data;
node->Right = DeleteByName(node->Right, temp->Data.name);
}
}
return node;
}
bool BinaryTree::DeleteByCoord(pair<double, double> coords)
{
if (GetRoot() == NULL)
{
return false;
}
else
{
return DeleteByCoord(GetRoot(), coords);
}
}
bool BinaryTree::DeleteByCoord(TreeNode* node, pair<double, double> coords)
{
bool result;
if (node == NULL)
{
return false;
}
else
{
if (node->Data.coordinates.first == coords.first && node->Data.coordinates.second == coords.second)
{
return (DeleteByName(node, node->Data.name));
}
result = DeleteByCoord(node->Left, coords);
if (result == true)
{
return result;
}
return DeleteByCoord(node->Right, coords);
}
}
void BinaryTree::Insert(City city)
{
TreeNode* temp = new TreeNode(city);
if (GetRoot() == NULL)
{
root = temp;
}
else
{
Insert(temp, GetRoot());
}
}
void BinaryTree::Insert(TreeNode* toAdd, TreeNode* addHere)
{
if (toAdd->Data < addHere->Data)
{
if (addHere->Left != NULL)
{
Insert(toAdd, addHere->Left);
}
else
{
addHere->Left = toAdd;
}
}
else if (toAdd->Data > addHere->Data)
{
if (addHere->Right != NULL)
{
Insert(toAdd, addHere->Right);
}
else
{
addHere->Right = toAdd;
}
}
}
void BinaryTree::InOrderTraversal(TreeNode* node)
{
if (node != NULL)
{
InOrderTraversal(node->Left);
cout << node->Data << endl;
InOrderTraversal(node->Right);
}
}
void BinaryTree::InOrderTraversal()
{
InOrderTraversal(GetRoot());
}
TreeNode* BinaryTree::GetRoot()
{
return root;
}
TreeNode* BinaryTree::MinPtr(TreeNode* node)
{
while (node->Left != NULL)
{
node = node->Left;
}
return node;
}

When you delete the node you also need to update parent pointer that points to deleted node. Pay attention here:
when you call DeleteByName directly it searches required node and returns NULL pointer which automatically set to parent node pointer:
else if (city < node->Data.name)
{
node->Left = DeleteByName(node->Left, city);
}
else if (city > node->Data.name)
{
node->Right = DeleteByName(node->Right, city);
}
but when you call DeleteByName from coordinates method you do not reset parent's Left/Right pointers:
if (node->Data.coordinates.first == coords.first && node->Data.coordinates.second == coords.second)
{
return (DeleteByName(node, node->Data.name));
}
in its turn as DeleteByName already receives required node, it does not perform recursive call and does not reset parent's pointers either:
else
{
if (node->Left == NULL && node->Right == NULL)
{
delete node;
node = NULL;
}
//... same here
}
NOTE: There are many more problems in your code. Some that strike the eye:
DeleteByName returns pointer, but DeleteByCoord returns bool, you use pointer as a boolean type in DeleteByCoord
Avoid to compare doubles directly, the comparison result can be wrong. See the question and explanation for the details.

Related

Doubly Linked List fails to add or delete valid entries

I've run it many times. I tried fixing my deleteNode() and addNode(), but it did not work. The output showed me that it failed to add some valid entries in my list, which resulted in failing to delete these valid entries. Someone please help me find the errors... I think either my isEmpty() is wrong or the addNode got messed up.
// Add nodes and makes it work in any cases: backward/forward
bool LinkedList::addNode(int id, string str) {
bool result = false;
if (id >= 0 && !(idExists(id))) {
Node *current = head;
Node *temp = new Node;
temp->data.data = str;
temp->data.id = id;
temp->forward = NULL;
temp->back = NULL;
// Kinds of adding cases
if(head == NULL) { // Check if list is empty
addHead(temp, current);
result = true;
} else {
while(temp->data.id > current->data.id && current->forward != NULL) {
current = current->forward;
}
// Backward
if(current->back == NULL) {
if(temp->data.id > current->data.id) {
if(current->forward == NULL) {
addTail(temp, current);
} else {
addMiddle(temp, current);
}
} else {
addHead(temp, current);
}
result = true;
// Forward
}else if(current->forward == NULL) {
if (temp->data.id > current->data.id) {
addTail(temp, current);
} else {
addMiddle(temp, current);
}
result = true;
}else {
if(temp->data.id > current->data.id) {
addMiddle(temp, current);
result = true;
}
}
}
}
return result;
}
void LinkedList::addHead(Node *temp, Node *current) {
if (head != NULL){
temp->forward = current;
current->back = temp;
head = temp;
} else {
head = temp;
}
}
void LinkedList::addMiddle(Node *temp, Node *current) {
temp->forward = current;
temp->back = current->back;
current->back->forward = temp;
current->back = temp;
}
void LinkedList::addTail(Node *temp, Node *current) {
current->forward = temp;
temp->back = current;
}
// Delete list
bool LinkedList::deleteNode(int id){
bool result = false;
if (idExists(id)) {
Node *current = head;
while (current->forward != NULL && current->data.id != id) {
current = current->forward;
}
if (current->data.id == id && current->forward == NULL) {
if (current->back == NULL) { // Delete head
delete current;
head = NULL;
} else { // delete tail
deleteTail(current);
}
result = true;
} else if (current->data.id == id) {
if (current->back == NULL)
deleteHead(current);
else // delete middle
deleteMiddle(current);
result = true;
}
}
return result;
}
// Helper delete functions
void LinkedList::deleteHead(Node *current) {
head = current->forward;
head->back = NULL;
delete current;
}
void LinkedList::deleteMiddle(Node *current) {
current->back->forward = current->forward;
current->forward->back = current->back;
delete current;
}
void LinkedList::deleteTail(Node *current) {
current->back->forward = NULL;
delete current;
}
bool LinkedList::getNode(int id, Data *data) {
bool didGetNode = false;
if (idExists(id)) {
Node *current = head;
while (current->forward != NULL && current->data.id != id) {
current = current->forward;
}
data->id = current->data.id;
data->data = current->data.data;
didGetNode = true;
}
return didGetNode;
}
// Check whether or not the id exists
bool LinkedList::idExists(int id){
bool exists = false;
if (head != NULL){
Node *current = head;
while (current->forward != NULL && current->data.id != id) {
current = current->forward;
}
if (current->data.id == id) {
exists = true;
}
}
return exists;
}
You probably want to be passing a pointer to a pointer (**) or a pointer to a reference (*&) in functions where you are wanting to make a change to what the address of the node is containing. I hope that this helps you visualize it.
For example:
struct Node { };
void setNull1(Node* temp)
{
temp = nullptr;
}
void setNull2(Node** temp)
{
(*temp) = nullptr;
}
void setNull3(Node*& temp)
{
temp = nullptr;
}
int main()
{
Node* tmp = new Node;
setNull1(tmp);
if (tmp == nullptr)
{
cout << "NULLPTR";
} // tmp is not nullptr
Node* tmp1 = new Node;
setNull2(&tmp1);
if (tmp1 == nullptr)
{
cout << "NULLPTR";
} // tmp1 is nullptr
Node* tmp2 = new Node;
setNull3(tmp2);
if (tmp2 == nullptr)
{
cout << "NULLPTR";
} // tmp2 is nullptr
}
You should also consider writing nullptr instead of NULL.

Removing a Node in a BST

I am having trouble getting my remove300 and removeNode300 function working correctly when I remove the root of the tree. (In my case 8). Everything works right(compiling wise), but when I call me inView function, which displays the numbers in the binary tree in ascending order, it takes that 8 out and just puts the highest number in 8's place.
For example:
I insert these numbers in this order, 8,4,12,2,6,10,14,20 and call me remove function to remove 8. I get this output 2,4,5,20,10,12,14. I want it to be 2,4,6,10,12,14,20.
If I can get some help on this on why this process isn't working please let me know. Also let me know if I have to add anything to this post inorder to help you.
Struct definition:
typedef float Element300;
struct TreeNode300;
typedef TreeNode300 * TreePtr300;
struct TreeNode300
{
Element300 element;
TreePtr300 left;
TreePtr300 right;
};
Remove Function:
void BST300::remove300(const Element300 element, TreePtr300 & root)
{
if(root == NULL)
{
cerr << "Error: Remove Failed!" << endl;
}
else if(element == root->element )
{
removeNode300(root);
}
else if(element < root->element)
{
remove300(element, root->left);
}
else
{
remove300(element, root->right);
}
return;
}
Remove Node function:
void BST300::removeNode300(TreePtr300 & root)
{
TreePtr300 tempPointer = NULL;
if(root->left == NULL && root->right == NULL)
{
delete root;
root = NULL;
}
else if(root->right == NULL)
{
tempPointer = root;
root = root->left;
tempPointer->left = NULL;
delete tempPointer;
}
else if(root->left == NULL)
{
tempPointer = root;
root = root->right;
tempPointer->right = NULL;
delete tempPointer;
}
else
{
findMaxNode300(root->right, tempPointer);
root->element = tempPointer->element;
delete tempPointer;
}
tempPointer = NULL;
return;
}
find Maximum value function:
void BST300::findMaxNode300(TreePtr300 & root, TreePtr300 & tempPointer)
{
if(root->right == NULL)
{
tempPointer = root;
root = root->left;
tempPointer->left = NULL;
}
else
{
findMaxNode300(root->right, tempPointer);
}
return;
}

Change pointer to pointer to reference to pointer

I have a method to insert a node into a binary tree, which uses a pointer to pointer to correctly allocate new nodes in the tree.
As I'm using C++, I think that it's possible to change this pointer to pointer to a reference to pointer, leading to cleaner and C++-ish code. But how to do this and keep the allocation correct?
bool insert(T value) {
node** buff = &root;
while ((*buff) != NULL) {
if (value == (*buff)->value) {
return false;
} else if (value < (*buff)->value) {
buff = &(*buff)->left;
} else {
buff = &(*buff)->right;
}
}
*buff = new node(value);
return true;
}
not tested, but this is the idea: you insert when you are in parent, not when you descended into null:
bool insert(T value) {
if (root == nullptr) {
root = new node(value);
return true;
}
node* buff = root;
while(buff->value != value) {
if (value < buff->value) {
if(buff->left == nullptr {
buff->left = new node(value);
return true;
}
buff = buff->left;
} else {
if (buff->right == nullptr) {
buff->right = new node(value);
return true;
}
buff = buff->right;
}
}
return false;
}
how i would write it:
// returns the node under which the insertion must be done
// or nullptr if the value already exists in the tree
// prereq: tree must be not empty
node* findParentInsertionPoint(T value) {
if (root == nullptr) {
throw std::logic_erro("");
}
node* n = root;
while(n->value != value) {
if (value < n->value) {
if(n->left == nullptr {
return buff;
}
n= n->left;
} else {
if (n->right == nullptr) {
return n;
}
n= n->right;
}
}
return nullptr;
}
// inserts a leaf as child of parent
// prereq: parent must be not null
// the corresponding child must be null;
void insertLeafAt(T value, node * parent) {
if (parent == nullptr) {
throw std::logic_error("");
}
if (value < parent->value) {
parent->left = new node(value);
} else {
parent->right = new node(value);
}
}
bool insert(T value) {
if (root == nullptr) {
root = new node(value);
return true;
}
node* parent = findParentInsertionPoint(value);
if (parent == nulptr) {
return false;
}
insertLeafAt(T value, parent);
return true;
}
You cannot reassign a reference, so due to buff = &(*buff)->left;,
you can't change node** buff = &root; to node*& buff = root; (and replacing (*buff) by buff).

BST Deletion c++

I have a code for deletion of a node in BST. This code shows memory overflows for some values. i cant figure out the problem. isequal() function returns true if both char arrays have same data and compare() functions returns true or false on the basis of values in temp->name and name. It returns true if first argument have bigger values.
void delete_data(char *name)
{
bool found = false;
tree *temp;
tree *parent;
temp=root;
while(temp != NULL)
{
if(isequal(temp->file_name,name)==true)
{
found = true;
break;
}
else
{
parent = temp;
if(compare(name,temp->file_name)==true)
temp=temp->right;
else
temp = temp->left;
}
}
if(!found)
{
cout<<"Data not found"<<endl;
return;
}
if((temp->left==NULL&&temp->right!=NULL)||(temp->left!=NULL&&temp->right==NULL))
{
if(temp->left == NULL && temp->right != NULL)
{
if(parent->left == temp)
{
parent->left = temp->right;
delete temp;
}
else
{
parent->right = temp->right;
delete temp;
}
}
else
{
if(parent->left == temp)
{
parent->left = temp->left;
delete temp;
}
else
{
parent->right = temp->left;
delete temp;
}
}
return;
}
if( temp->left == NULL && temp->right == NULL)
{
if(parent->left == temp) parent->left = NULL;
else parent->right = NULL;
delete temp;
return;
}
if (temp->left != NULL && temp->right != NULL)
{
tree *chkr;
if(parent==NULL || parent->left==temp)
{
chkr=temp->right;
while(chkr->left!=NULL)
chkr=chkr->left;
if(parent!=NULL)
parent->left=temp->right;
else
root=temp->right;
chkr->left=temp->left;
temp->left=temp->right=NULL;
delete temp;
}
else if(parent->right==temp)
{
chkr=temp->left;
while(chkr->right!=NULL)
chkr=chkr->right;
parent->right=temp->left;
chkr->right=temp->right;
temp->left=temp->right=NULL;
delete temp;
}
return;
}
}
I took a quick look at it, and it seems that you only initialize parent in the non-trivial case.
If the root is the node that you want to delete, parent is uninitialized. You check if parent is something non-null only in the case where temp has 2 descendants. I would guess that this is the problem.

Deleting in Binary Tree sulotion

After a few questions and some nice answers and friendly helpers here. I got the sulotion to my porblem with the deleting in the binary tree, i got suggested that, i can not just delet the largest number in the tree cause its may not the last or it has childrens 1 ,2 or none, so i made the code down below, i used a lot commenting hope that can help you people help me. What i actually dont know now, is how do i call this RemoveLargest() function in my public and then later in main, even though i dont know if the code will run properly.
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
template<class T>
class BinaryTree
{
struct Node
{
T data;
Node* lChildptr;
Node* rChildptr;
Node(T dataNew)
{
data = dataNew;
lChildptr = NULL;
rChildptr = NULL;
}
};
private:
Node* root;
void Insert(T newData, Node* &theRoot) //Insert elements into the tree start.
{
if(theRoot == NULL)
{
theRoot = new Node(newData);
return;
}
if(newData < theRoot->data)
Insert(newData, theRoot->lChildptr);
else
Insert(newData, theRoot->rChildptr);
} //end.
void PrintTree(Node* theRoot) //print me the tree /start
{
if(theRoot != NULL)
{
PrintTree(theRoot->lChildptr);
cout<< theRoot->data<<" \n";
PrintTree(theRoot->rChildptr);
}
} //end.
T Largest( Node* theRoot) // show me largest number /start.
{
if ( root == NULL )
{
cout<<"There is no tree";
return -1;
}
if (theRoot->rChildptr != NULL)
{
return Largest(theRoot->rChildptr);
}
T value = theRoot->data;
return value;
} //end.
void RemoveLargest(Node* theRoot) //remove the largest priority number from tree /start.
{
Node* current; //the current tree?
Node* parent; //the parent of the current node?
current=theRoot;
// 3 cases :
// 1. We're removing a leaf node
// 2. We're removing a node with a single child
// 3. we're removing a node with 2 children
//Node with single child.
if((current->lChildptr == NULL && current->rChildptr != NULL)||(current->lChildptr != NULL && current->rChildptr == NULL))
{
if(current->lChildptr == NULL && current->rChildptr != NULL)
{
if(parent->lChildptr==current)
{
parent->lChildptr = current->rChildptr;
delete current;
}
else
{
parent->rChildptr = current->rChildptr;
delete current;
}
}
else //left child ok, no right child
{
if(parent->lChildptr==current)
{
parent->lChildptr = current->lChildptr;
delete current;
}
else
{
parent->rChildptr = current->lChildptr;
delete current;
}
}
return;
}
//We found a leaf(a node with not a single child)
if(current->lChildptr == NULL && current->rChildptr == NULL)
{
if (parent->lChildptr == current)
parent->lChildptr = NULL;
else
parent->rChildptr = NULL;
delete current;
return;
}
//Node with 2 children
// replace node with smallest value in right subtree
if (current->lChildptr != NULL && current->rChildptr != NULL)
{
Node* checkr;
checkr = current->rChildptr;
if((checkr->lChildptr == NULL)&&(checkr->rChildptr == NULL))
{
current=checkr;
delete checkr;
current->rChildptr = NULL;
}
else //right child has children
{
//if the node's right child has a left child
//Move all the way down left to locate smallest element
if ((current->rChildptr)->lChildptr != NULL)
{
Node* lcurr;
Node* lcurrp;
lcurrp = current->rChildptr;
lcurr = (current->rChildptr)->lChildptr;
while(lcurr->lChildptr != NULL)
{
lcurrp = lcurr;
lcurr = lcurr->lChildptr;
}
current->data = lcurr->data;
delete lcurr;
lcurrp->lChildptr = NULL;
}
else
{
Node* temp;
temp = current->rChildptr;
current->data = temp ->data;
current->rChildptr = temp->rChildptr;
delete temp;
}
}
return;
}
};
public:
BinaryTree()
{
root = NULL;
}
void AddItem(T newData)
{
Insert(newData, root);
}
void PrintTree()
{
PrintTree(root);
}
T Largest()
{
return Largest(root);
}
void RemoveLargest()
{
RemoveLargest();
}
};
int main()
{
BinaryTree<int> *myBT = new BinaryTree<int>();
myBT->AddItem(5);
myBT->AddItem(1);
myBT->AddItem(4);
myBT->AddItem(2);
myBT->AddItem(3);
//for(int i = 0; i < 10; i++) //randommal tolti fel/fill with random
//myBT->AddItem(rand() % 100);
cout << "BinaryTree:" << endl; //kilistazaa a fat/ list my tree
myBT->PrintTree();
cout << "Largest element: " << myBT->Largest() << endl; //visszaadja a legnagyobb elemet/shows the largest number
myBT->RemoveLargest(); //suposed to delet the largest number
myBT->PrintTree(); //shows list again
}
edited the code, now its running, its creating the tree, shows the largest, but after i call my remove function still crashing... =/
Like I said before, I think you're making things overly complicated. You have to think of what it means that your node is the largest one, in the context of a binary search tree and the relationship between the keys in its nodes.
If a node is the largest one in the tree it cannot possibly have a right child pointer, because the right child would have to have a larger key. And then, if you know that it has at most a left child, you just replace your node with its possibly null left child, and you're done.
T ExtractLargest(Node*& n){
if (!n)
return -1;
if (n->rChildptr)
return ExtractLargest(n->rChildptr);
T result = n->data;
Node *d = n;
n = n->lChildptr;
delete d;
return result;
}