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C++11: Correct std::array initialization?
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Why can't simple initialize (with braces) 2D std::array? [duplicate]
(1 answer)
Closed 5 years ago.
I am early in c++. I want to define an 3d std::array in c++. when i define bellow array:
std::array<std::array<std::array<double,3>,4>, 4> DownSide = {
{{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35}},
{{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35}},
{{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35}},
{{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35},{0,0.51,0.35}}
};
I see this error:
error: too many initializers for ‘std::array<std::array<std::array<double, 3ul>, 4ul>, 4ul>’
};
I googled this error find i mistak in numer brackets, but i dont know and find how must i write them.
How must i do?
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so I am having an issue with defining and declaring my constructor, normally this isnt a problem but this time I the private data is 2 sets of pre filled arrays. And I am not sure of the syntax for doing this as it doesnt seem to follow the normal way for say.
Below is the relevant parts of the code.
class Frequency_Values{
public:
Frequency_Values(unsigned short LSB_LUT_[], unsigned short MSB_LUT_[]);
Frequency_Values(const Frequency_Values& F);
Frequency_Values& operator = (const Frequency_Values& F);
~Frequency_Values(){};
private:
unsigned short MSB_LUT[410] = {1,2,3}; //not the same data, its cut down cause the actual array is large and would make it messy here
unsigned short LSB_LUT[410] = {1,2,3};
//------------------------Constructor definition-----------------------------------------
Frequency_Values::Frequency_Values(unsigned short LSB_LUT_[],unsigned short MSB_LUT_[]):LSB_LUT[](LSB_LUT_[]),MSB_LUT[](MSB_LUT_[]){}
//---------------------------------------------------------------------------------------
The way I have it gives the following errors,
Any help with this would be greatly appreciated.
Thanks, Dean.
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void f1( int a[][][3]);
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