How do I add a search function to array? - c++

Question

I need to add a function to search in the string array and bring up the user with associated phone number. Though Im lost. Any functions created only bring up the persons name without the number. If not found, it needs to say error.
int main(int argc, char** argv)
{
int i, n, j;
string name[100];
string phone[100];
int index[100];
cout << "How many names and phone numbers do you want to enter? " << endl
<< "Entering 0 ends the program." << endl;
cin >> n;
if (n == 0)
return 0;
for (i = 0; i < n; i++) {
cout << "Please enter a name: ";
cin >> name[i];
cout << "Please enter a phone number: ";
cin >> phone[i];
}
for (i = 0; i < n; i++) {
index[i] = i;
}
for (i = 0; i < n; i++) {
for (j = i + 1; j < n; j++) {
int temp;
if (phone[index[i]] > phone[index[j]]) {
temp = index[i];
index[i] = index[j];
index[j] = temp;
}
}
}
cout << "These entries are in ascending order by phone number: " << endl;
cout << "Name"
<< " "
<< "Phone Number" << endl;
for (i = 0; i < n; i++) {
cout << name[index[i]] << " " << phone[index[i]] << endl;
}
return 0;
}

Answer 1

This code should work for you (if i understood the question)
int search(string name[], string searchedName){
for(int i=0; i<100; i++){
if(searchedName == name[i])
return i; //Returns the position of the person, which is also the index of his phone number
}
return -1; //If -1 is returned it means there is no such name an "searchedName" in the vector
}
You can call this function like this
int main(){
/* all the stuff you already have inside here */
string nameToSearch;
cout<<"Insert the name of the person you want to see the number of"<<endl;
cin>>nameToSearch;
int position = search(name, nameToSearch);
if(position == -1)
cout<<"Sorry, "<<nameToSearch<<" is not in our list"<<endl;
else
cout<<"The phone number of "<<nameToSearch<<" is "<<phone[position]<<endl;
return 0;
}
Of course this is pretty basic and you can make it better, hope it helps!