I want to compare elements for each line of a matrix, from smallest to biggest.
But I don't want to print the sorted array I want to print the original position.
0 11.80 79.34 78.23
11.80 0 65.23 45.19
79.34 65.23 0 90.27
78.23 45.19 90.27 0
In this Matrix for the first line I wanna print 1, 2, 4, 3
My Code so far:
#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
int main() {
string dummy;
double myArray[4][4];
int i;
int j;
int y;
ifstream infile("dist.dat");
cout << "Open file " << "dist.dat" <<" for reading." << endl;
for (i = 0; i < 4; i++) {
for (j = 0; j < 4; j++) {
infile >> myArray[i][j];
if (!infile) {
cout << "***There was a problem trying to read element [" << i << "][" << j << "]" << endl;
return 0;
}
}
}
infile.close();
cout << "Here's the array from the file" << endl;
cout << fixed << setprecision(2);
for (i = 0; i < 4; i++) {
for (j = 0; j < 4; j++) {
cout << setw(10) << myArray[i][j];
}
cout << endl;
}
cout << endl;
int x = myArray[i][j];
for (i = 0; i < 4; i++) {
for (j = 0; j < 4; j++) {
if(myArray[i][j] >= x) {
x = j;
}
else {
x = j + 1;
}
}
cout << x << endl;
}
return 0;
}
You need to maintain another matrix which has indices of every line and then apply the same operations on it that you are applying on each line of the original matrix to sort it.
Here is the code:
#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;
void swap(int &x, int &y)
{
int temp = x;
x = y;
y = temp;
}
void swap(double &x, double &y)
{
double temp = x;
x = y;
y = temp;
}
int main()
{
string dummy;
double myArray[4][4];
int i;
int j;
int y;
int k;
ifstream infile("dist.dat");
cout << "Open file " << "dist.dat" <<" for reading." << endl;
for (i = 0; i < 4; i++)
{
for (j = 0; j < 4; j++)
{
infile >> myArray[i][j];
if (!infile)
{
cout << "***There was a problem trying to read element [" << i << "][" << j << "]" << endl;
return 0;
}
}
}
infile.close();
cout << "Here's the array from the file" << endl;
cout << fixed << setprecision(2);
for (i = 0; i < 4; i++)
{
for (j = 0; j < 4; j++)
{
cout << setw(10) << myArray[i][j];
}
cout << endl;
}
cout << endl;
int sortedIndices[4][4];
for (i = 0; i < 4; i++)
{
for (j = 0; j < 4; j++)
{
sortedIndices[i][j] = j+1;
}
}
int x;
for (i = 0; i < 4; i++)
{
for (j = 0; j < 4; j++)
{
x = j;
for(k = j+1; k < 4; k++)
{
if(myArray[i][k] < myArray[i][x])
{
x = k;
}
}
swap(sortedIndices[i][j], sortedIndices[i][x]);
swap(myArray[i][j], myArray[i][x]);
}
}
for (i = 0; i < 4; i++)
{
for (j = 0; j < 4; j++)
{
cout << setw(10) << sortedIndices[i][j];
}
cout<<endl;
}
return 0;
}
Related
I'm a C++ newb. I need to insert numbers to an array and then display first the odd numbers and then the even numbers in a single array. I've managed to create two separate arrays with the odd and even numbers but now I don't know how to sort them and put them back in a single array. I need your help to understand how to do this with basic C++ knowledge, so no advanced functions. Here's my code:
#include <iostream>
using namespace std;
int main()
{
int N{ 0 }, vector[100], even[100], odd[100], unify[100], i{ 0 }, j{ 0 }, k{ 0 };
cout << "Add the dimension: " << endl;
cin >> N;
cout << "Add the elements: " << endl;
for (int i = 0; i < N; i++) {
cout << "v[" << i << "]=" << endl;
cin >> vector[i];
}
for (i = 0; i < N; i++) {
if (vector[i] % 2 == 0) {
even[j] = vector[i];
j++;
}
else if (vector[i] % 2 != 0) {
odd[k] = vector[i];
k++;
}
}
cout << "even elements are :" << endl;
for (i = 0; i < j; i++) {
cout << " " << even[i] << " ";
cout << endl;
}
cout << "Odd elements are :" << endl;
for (i = 0; i < k; i++) {
cout << " " << odd[i] << " ";
cout << endl;
}
return 0;
}
If you don't need to store the values then you can simply run through the elements and print the odd and the even values to different stringstreams, then print the streams at the end:
#include <sstream>
#include <stddef.h>
#include <iostream>
int main () {
std::stringstream oddStr;
std::stringstream evenStr;
static constexpr size_t vecSize{100};
int vec[vecSize] = {10, 5, 7, /*other elements...*/ };
for(size_t vecIndex = 0; vecIndex < vecSize; ++vecIndex) {
if(vec[vecIndex] % 2 == 0) {
evenStr << vec[vecIndex] << " ";
} else {
oddStr << vec[vecIndex] << " ";
}
}
std::cout << "Even elements are:" << evenStr.rdbuf() << std::endl;
std::cout << "Odd elements are:" << oddStr.rdbuf() << std::endl;
}
Storing and sorting the elements are always expensive.
Basically, it would be better to sort them first.
#include <iostream>
using namespace std;
int main()
{
int numbers[5];
int mergedArrays[5];
int evenNumbers[5];
int oddNumbers[5];
for(int i=0;i<5;i++){
cin>>numbers[i];
}
int temp=numbers[0];
//bubble sort
for(int i = 0; i<5; i++)
{
for(int j = i+1; j<5; j++)
{
if(numbers[j] < numbers[i])
{
temp = numbers[i];
numbers[i] = numbers[j];
numbers[j] = temp;
}
}
}
int nEvens=0;
int nOdds=0;
for(int i = 0; i<5; i++)
{
if(numbers[i]%2==0)
{
evenNumbers[nEvens]=numbers[i];
nEvens++;
}
else if(numbers[i]%2!=0)
{
oddNumbers[nOdds]=numbers[i];
nOdds++;
}
}
int lastIndex=0;
//copy evens
for(int i = 0; i<nEvens; i++)
{
mergedArrays[i]=evenNumbers[i];
lastIndex=i;
}
//copy odds
for(int i =lastIndex; i<nOdds; i++)
{
mergedArrays[i]=oddNumbers[i];
}
return 0;
}
If you have to just output the numbers in any order, or the order given in the input then just loop over the array twice and output first the even and then the odd numbers.
If you have to output the numbers in order than there is no way around sorting them. And then you can include the even/odd test in the comparison:
std::ranges::sort(vector, [](const int &lhs, const int &rhs) {
return ((lhs % 2) < (rhs % 2)) || (lhs < rhs); });
or using a projection:
std::ranges::sort(vector, {}, [](const int &x) {
return std::pair<bool, int>{x % 2 == 0, x}; });
If you can't use std::ranges::sort then implementing your own sort is left to the reader.
I managed to find the following solution. Thanks you all for your help.
#include <iostream>
using namespace std;
int main()
{
int N{0}, vector[100], even[100], odd[100], merge[100], i{0}, j{0}, k{0}, l{0};
cout << "Add the dimension: " << endl;
cin >> N;
cout << "Add the elements: " << endl;
for (int i = 0; i < N; i++)
{
cout << "v[" << i << "]=" << endl;
cin >> vector[i];
}
for (i = 0; i < N; i++)
{
if (vector[i] % 2 == 0)
{
even[j] = vector[i];
j++;
}
else if (vector[i] % 2 != 0)
{
odd[k] = vector[i];
k++;
}
}
cout << "even elements are :" << endl;
for (i = 0; i < j; i++)
{
cout << " " << even[i] << " ";
cout << endl;
}
cout << "Odd elements are :" << endl;
for (i = 0; i < k; i++)
{
cout << " " << odd[i] << " ";
cout << endl;
}
for (i = 0; i < k; i++)
{
merge[i] = odd[i];
}
for (int; i < j + k; i++)
{
merge[i] = even[i - k];
}
for (int i = 0; i < N; i++)
{
cout << merge[i] << endl;
}
return 0;
}
You can use Bubble Sort Algorithm to sort whole input. After sorting them using if and put odd or even numbers in start of result array and and others after them. like below:
//Bubble Sort
void bubbleSort(int arr[], int n)
{
int i, j;
for (i = 0; i < n - 1; i++)
// Last i elements are already
// in place
for (j = 0; j < n - i - 1; j++)
if (arr[j] > arr[j + 1])
swap(arr[j], arr[j + 1]);
}
// Insert In array
int result[100];
if(odd[0]<even[0])
{
for (int i = 0; i < k; i++)
{result[i] = odd[i];}
for (int i = 0; i < j; i++)
{result[i+k] = even[i];}
}else
{
for (int i = 0; i < j; i++)
{result[i] = even[i];}
for (int i = 0; i < k; i++)
{result[i+k] = odd[i];}
}
I am trying to create a program that swaps the row that contains the min number with the row that contains the max number in a n x m twodimensional array (c++)
#include <iostream>
using namespace std;
int main()
{
int i, j, n, m, imin, imax, jnm, jnv;
cin >> n >> m;
int k[n][m];
int max = 0;
int min = 0;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
cout << "a[" << i << "][" << j << "]" << endl;
cin >> k[i][j];
}
}
cout << endl
<< endl;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
cout << k[i][j];
}
cout << endl;
}
cout << endl
<< endl;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
if (k[i][j] > max) {
max = k[i][j];
imax = i;
}
}
cout << endl;
}
min = max;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
if (k[i][j] < min) {
min = k[i][j];
imin = i;
}
}
cout << endl;
}
cout << endl
<< endl;
if (imax == imin) {
cout << endl
<< "Min & Max are in the same row!" << endl;
}
else {
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
if (i == imax) {
k[i][j] = k[imin][j];
}
else if (i == imin) {
k[i][j] = k[imax][j];
}
cout << k[i][j];
}
cout << endl;
}
}
return 0;
}
I know the code isn't the cleanest and most professionally written, and that isn't important, as I'm currently preparing for a coding competition where the only thing that matters is functionality of the program.
When I execute this program, it usually swaps one row but the other is still the same.
You could use function swapif you want to swap. At the moment you assignments are wrong.
So, simply write:
#include <iostream>
#include <vector>
using namespace std;
int main()
{
int i, j, n, m, imin=0, imax=0;
cin >> n >> m;
vector<vector<int>> k(n, vector<int>(m, 0));
int max = 0;
int min = 0;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
cout << "a[" << i << "][" << j << "]" << endl;
cin >> k[i][j];
}
}
cout << endl
<< endl;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
cout << k[i][j] << ' ';
}
cout << endl;
}
cout << endl
<< endl;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
if (k[i][j] > max) {
max = k[i][j];
imax = i;
}
}
cout << endl;
}
min = max;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
if (k[i][j] < min) {
min = k[i][j];
imin = i;
}
}
cout << endl;
}
cout << endl
<< endl;
if (imax == imin) {
cout << endl
<< "Min & Max are in the same row!" << endl;
}
else {
for (j = 0; j < m; j++)
swap(k[imin][j], k[imax][j]);
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
cout << k[i][j] << ' ';
}
cout << endl;
}
}
return 0;
}
And sorry, I cannot write int k[n][m]; because this is not C++ and my compiler cannot compile it. But vector can be used in the same way.
If you are not allowed to use std::swapyou can use instead:
for (j = 0; j < m; j++) {
int tmp = k[imin][j];
k[imin][j] = k[imax][j];
k[imax][j] = tmp;
}
For the competition you could also get the min and max values already during input and write:
#include <iostream>
#include <vector>
#include <algorithm>
#include <limits>
int main()
{
// Read matrix size
size_t rows{}, columns{};
if (std::cin >> rows >> columns) {
// Here we will store our matrix
std::vector<std::vector<int>> matrix(rows, std::vector<int>(columns, 0));
// Initilize min max values
int maxElement = std::numeric_limits<int>::min();
int minElement = std::numeric_limits<int>::max();
size_t indexMaxRow{}, indexMinRow{};
// Enter values in matrix
for (size_t row{}; row < rows; ++row) {
for (size_t column{}; column < columns; ++column) {
std::cout << "array[" << row << "][" << column << "]\n";
if (std::cin >> matrix[row][column]) {
// Already during input find the min and max values
if (matrix[row][column] > maxElement) {
maxElement = matrix[row][column];
indexMaxRow = row;
}
if (matrix[row][column] < minElement) {
minElement = matrix[row][column];
indexMinRow = row;
}
}
}
}
// Show original matrix
std::cout << "\n\n\nYou entered:\n\n";
for (const auto& row : matrix) {
for (const auto& col : row) std::cout << col << ' ';
std::cout << '\n';
}
// Swap
std::swap(matrix[indexMaxRow], matrix[indexMinRow]);
// Show swapped matrix
std::cout << "\n\n\nSwapped:\n\n";
for (const auto& row : matrix) {
for (const auto& col : row) std::cout << col << ' ';
std::cout << '\n';
}
}
else std::cerr << "\nError while reading size\n";
}
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I have written next code but 3 functions must be replaced by 1 and I don't know how to.
The program creates 3 arrays but only 1 function must calculate negative numbers of each column and find the max element in each column. Here's the code:
#include <iostream>
#include <ctime>
#include <iomanip>
using namespace std;
int n = 0;
const int m = 3, k = 3, b = 4, u = 5;
int i, j;
void calc(float** array, int i, int j );
void calc1(float** array, int i, int j);
void calc2(float** array, int i, int j);
int main()
{
float** array = new float* [m];
for (int l = 0; l < m; l++) {
array[l] = new float[k];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < k; j++) {
array[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < m; i++)
{
for (int j = 0; j < k; j++) {
cout << setprecision(2) << setw(4) << array[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(array, i, j); // FUNCTION !!!
float** arr = new float* [b];
for (int l = 0; l < b; l++) {
arr[l] = new float[b];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < b; i++) {
for (int j = 0; j < b; j++) {
arr[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < b; i++)
{
for (int j = 0; j < b; j++) {
cout << setprecision(2) << setw(4) << arr[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(arr, i, j); // FUNCTION !!!
float** ar = new float* [u];
for (int l = 0; l < u; l++) {
ar[l] = new float[u];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < u; i++) {
for (int j = 0; j < u; j++) {
ar[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < u; i++)
{
for (int j = 0; j < u; j++) {
cout << setprecision(2) << setw(4) << ar[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc2(ar, i, j); // FUNCTION !!!
}
void calc(float** array, int i, int j) {
int max = array[0][0];
for (int j = 0; j < k; j++)
{
max = array[0][0];
for (int i = 0; i < k; i++) {
if (array[i][j] > max)
max = array[i][j];
if (array[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
void calc1(float** arr, int i, int j) {
int max = arr[0][0];
for (int j = 0; j < b; j++)
{
max = arr[0][0];
for (int i = 0; i < b; i++) {
if (arr[i][j] > max)
max = arr[i][j];
if (arr[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
void calc2(float** ar, int i, int j) {
int max = ar[0][0];
for (int j = 0; j < u; j++)
{
max = ar[0][0];
for (int i = 0; i < u; i++) {
if (ar[i][j] > max)
max = ar[i][j];
if (ar[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
The parameters to calc() should be the number of rows and columns in the array. Then it should use these as the limits in the for loops.
Also, since you're calculating total negative and maximum for each column, you must reset these variables each time through the column loop.
#include <iostream>
#include <ctime>
#include <iomanip>
using namespace std;
const int m = 3, k = 3, b = 4, u = 5;
void calc(float** array, int rows, int cols);
int main()
{
float** array = new float* [m];
for (int l = 0; l < m; l++) {
array[l] = new float[k];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < k; j++) {
array[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < m; i++)
{
for (int j = 0; j < k; j++) {
cout << setprecision(2) << setw(4) << array[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(array, m, k); // FUNCTION !!!
float *arr = new float* [b];
for (int l = 0; l < b; l++) {
arr[l] = new float[b];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < b; i++) {
for (int j = 0; j < b; j++) {
arr[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < b; i++)
{
for (int j = 0; j < b; j++) {
cout << setprecision(2) << setw(4) << arr[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(arr, b, b); // FUNCTION !!!
float** ar = new float* [u];
for (int l = 0; l < u; l++) {
ar[l] = new float[u];
}
// заполнение массива
srand(time(0));
for (int i = 0; i < u; i++) {
for (int j = 0; j < u; j++) {
ar[i][j] = rand() % 21 - 10;
}
}
cout << "The initial array is: " << endl << endl;
for (int i = 0; i < u; i++)
{
for (int j = 0; j < u; j++) {
cout << setprecision(2) << setw(4) << ar[i][j] << " ";
}
cout << endl;
}
cout << endl << "The amount of negative elements in each column: ";
calc(ar, u, u); // FUNCTION !!!
}
void calc(float** array, int rows, int cols) {
for (int j = 0; j < cols; j++)
{
int n = 0;
int max = array[0][j];
for (int i = 1; i < rows; i++) {
if (array[i][j] > max)
max = array[i][j];
if (array[i][j] < 0) {
n += 1;
}
}
cout << endl << "IN the [" << j + 1 << "] column is " << n << " negative elements" << endl << endl; n = 0;
cout << "IN the [" << j + 1 << "] column is " << max << " maximal element" << endl;
}
}
Let the matrix have 4 verticles and 4 edge: (1,2),(1,4),(2,3),(2,4). I need to fill Adjacency (I did) and transform this Adjacency matrix to Incidence matrix. The result should be a matrix Incidence={(0111),(1010),(1101),(1010)} What is the best algorithm. I can't find a solution, all ideas are with bugs. :-( Thanks
#include "iostream"
#include "conio.h"
#include <stdlib.h>
using namespace std;
struct Rebro {
int x=0;
int y=0;
};
int main()
{
int Graph[100][100], Vertex, Edge, x, y;
int VG, EG;
int Incidence[100][100];
cout << "Enter number of vertexes:";
cin >> Vertex;
cout << "\nEnter number of edges:";
cin >> Edge;
//_________________________NULL
for (int i = 1; i <= Vertex; i++)
for (int j = 1; j <= Vertex; j++)
{
Graph[i][j] = 0;
}
//_________________________NULL
for (int i = 1; i <= Vertex; i++)
for (int j = 1; j <= Vertex; j++)
{
Incidence[i][j] = 0;
}
//_________________________INPUT
Rebro mass[100];
cout << "\nEnter edges:\n " << endl;
for (int i = 1; i <= Edge; i++)
{
cout << "e1=";
cin >> x;
cout << "e2=";
cin >> y;
cout << endl;
Graph[x][y] = 1;
Graph[y][x] = 1;
mass[i].x =x ;
mass[i].y =y ;
}
//_________________________OUTPUT
cout << "\nAdjacency matrix:\n" << endl;
for (int i = 1; i <= Vertex; i++)
{
for (int j = 1; j <= Vertex; j++)
{
cout <<" "<< Graph[i][j];
}
cout << endl;
}
cout << endl;
for (int i = 1; i <= Edge; i++) {
Incidence[i][mass[i].x] = 1;
Incidence[i][mass[i].y] = 1;
}
//_________________________OUTPUT
cout << "\nIncidence matrix:\n" << endl;
int count = 0;
for (int j = 1; j <= Vertex; j++)
{
for (int i = 1; i <= Vertex; i++)
{
cout << " " << Incidence[i][j];
}
cout << endl;
}
cout << endl;
_getch();
}
OR generally a wrong idea:
#include "iostream"
#include "conio.h"
#include <stdlib.h>
using namespace std;
int main()
{
int Graph[100][100], Vertex, Edge, x, y;
int VG, EG;
int Incidence[100][100];
cout << "Enter number of vertexes:";
cin >> Vertex;
cout << "\nEnter number of edges:";
cin >> Edge;
//_________________________NULL
for (int i = 1; i <= Vertex; i++)
for (int j = 1; j <= Vertex; j++)
{
Graph[i][j] = 0;
}
//_________________________NULL
for (int i = 1; i <= Vertex; i++)
for (int j = 1; j <= Vertex; j++)
{
Incidence[i][j] = 0;
}
//_________________________INPUT
cout << "\nEnter edges:\n " << endl;
for (int i = 1; i <= Edge; i++)
{
cout << "e1=";
cin >> x;
cout << "e2=";
cin >> y;
cout << endl;
Graph[x][y] = 1;
Graph[y][x] = 1;
}
//_________________________OUTPUT
cout << "\nAdjacency matrix:\n" << endl;
for (int i = 1; i <= Vertex; i++)
{
for (int j = 1; j <= Vertex; j++)
{
cout <<" "<< Graph[i][j];
}
cout << endl;
}
cout << endl;
for (int i =1; i<=Edge; i++) {
for (int j=1; j<=Edge; j++) {
if (Graph[x][y]==1) {
if ((i==x)||(i==y)||(j==x)||(j==y)) {
Incidence[i][j]==1;
Incidence[j][i]==1;
}
else {
Incidence[i][j]==0;
Incidence[j][i]==0;
}
}
}
}
//_________________________OUTPUT
cout << "\nIncidence matrix:\n" << endl;
int count = 0;
for (int j = 1; j <= Vertex; j++)
{
for (int i = 1; i <= Vertex; i++)
{
cout << " " << Incidence[i][j];
}
cout << endl;
}
cout << endl;
_getch();
}
I'm printing random numbers enclosed in ascii boxes in a 6x6 grid. Having issues with printing out the grid.
Instead of having 6 columns, all my boxes and numbers are being printed out in 1 column. Been troubleshooting but cant seem to find the issue. Below is the code. Appreciate your assistance.
int main(void)
{
cout << "Magic Grid\n" << endl;
int arrayxy [6][6];
srand((unsigned)time(0));
int lowest=1111, highest=9999;
int range=(highest-lowest)+1;
// Fill array with random values
for (int i = 0; i < 6; ++i)
{
for(int j = 0; j < 6; ++j)
{
arrayxy[i][j] = lowest+int(range*rand()/(RAND_MAX + 1.0));
}
}
// Print array as grid
for (int i = 0; i < 6; ++i)
{
for(int j = 0; j < 6; ++j)
{
cout << char(218);
for (int y=0; y< 4; y++)
{
cout << char(196);
}
cout << char(191) <<endl;
cout << char(179) << arrayxy[i][j] << char(179) << endl;
cout << char(192);
for (int z=0; z< 4; z++)
{
cout << char(196);
}
cout << char(217) <<endl;
}
cout << endl;
}
cout << endl;
}
You should endl after all the columns get printed out, NOT before.
This is how I fixed your code that gives, hopefully, what you wanted to have.
For the record, I specifically changed those ASCII to * and & to make the console result more readable. You can change them back to what you want those characters to be again.
void WriteFrontLine(std::size_t count)
{
for (int i = 0; i < count; i++)
{
cout << '*';
cout << '&' << '&' << '&' << '&';
cout << '*';
}
cout << endl;
}
void WriteEndLine(std::size_t count)
{
for (int i = 0; i < count; i++)
{
cout << '*';
cout << '&' << '&' << '&' << '&';
cout << '*';
}
cout << endl;
}
int main(void)
{
cout << "Magic Grid\n" << endl;
int arrayxy[6][6];
srand((unsigned)time(0));
int lowest = 1111, highest = 9999;
int range = (highest - lowest) + 1;
// Fill array with random values
for (int i = 0; i < 6; ++i)
{
for (int j = 0; j < 6; ++j)
{
arrayxy[i][j] = lowest + int(range*rand() / (RAND_MAX + 1.0));
}
}
// Print array as grid
for (int i = 0; i < 6; ++i)
{
WriteFrontLine(6);
for (int j = 0; j < 6; ++j)
{
cout << '*' << arrayxy[i][j] << '*';
}
cout << endl;
WriteEndLine(6);
cout << endl;
}
cout << endl;
}