Trying to do some normalization and keep getting error - c++

Question

I keep getting the error "error: invalid conversion from ‘int*’ to ‘int’ [-fpermissive] " and I do not know why;
I am doing this for homework and we have yet to discuss pointers so using them is out of the question.
here is my code (PS I am new to programming)
#include <iostream>
#include <cmath>
using namespace std;
double normalize (int , int);
double normalize (double,double);
int n=0;
int i=0;
const double SIZE=5;
double mean=0;
double meanDivide;
int main()
{
char dataType;
int norm[5];
int value =1;
cout<<"Which data type do you want (i, d): ";
cin>>dataType;
if (dataType =='i')
{
while(value<5)
{
cout<<"Enter value "<<value << ": ";
cin>> norm[n];
value++;
}
}
else if (dataType=='d')
{
cout<<"Enter value "<<value << ": ";
cin>> norm[n];
value++;
}
cout<<"The mean is: "<<normalize(norm,5)/* The error comes from here and
I do not know what to do or why */
<<endl;
cout<<"The normalized values: "<<endl;
int j=0;
cout<<"norm[1] = "<<norm[j]<<endl;
j++;
cout<<"norm[2] = "<<norm[j]<<endl;
j++;
cout<<"norm[3] = "<<norm[j]<<endl;
j++;
cout<<"norm[4] = "<<norm[j]<<endl;
j++;
cout<<"norm[5] = "<<norm[j]<<endl;
return 0;
}
double normalize(int norm[],int SIZE)
{
while(i<6)
{
meanDivide +=norm[i];
i++;
}
i=0;
while (i<n)
{
norm[i] -=meanDivide;
i++;
}
mean = meanDivide / 5;
return mean;
}
double normalize (double norm[],double SIZE)
{
while(i<6)
{
meanDivide +=norm[i];
i++;
}
i=0;
while (i<n)
{
norm[i] -=meanDivide;
i++;
}
mean = meanDivide / 5;
return mean;
}
This is the output I should be getting.
//For integers:
Which data type do you want (i, d): i
Enter value 1: 0
Enter value 2: 3
Enter value 3: 4
Enter value 4: 8
Enter value 5: 12
The mean is: 5.4
The normalized values:
norm[1] = -5
norm[2] = -2
norm[3] = -1
norm[4] = 2
norm[5] = 6
//For doubles:
Which data type do you want (i, d): d
Enter value 1: 5.5
Enter value 2: 1.23
Enter value 3: 2.02
Enter value 4: 9.99
Enter value 5: 6.32
The mean is: 5.012
The normalized values:
norm[1] = 0.488
norm[2] = -3.782
norm[3] = -2.992
norm[4] = 4.978
norm[5] = 1.308

Answer 1

You are declaring your methods like this :
double normalize (int , int);
double normalize(double*, double);
Yet you are trying to implement them like :
double normalize(int norm[], int SIZE) {/*...*/}
double normalize(double norm[], double SIZE) {/*...*/}
Notice that the argument types are not the same, int, int is not the same as int[], int. This means that your implementation is actually defining a whole new function, unrelated to the ones you declared at the top of your example. When you call your normalize function, only the initial declaration is found, and it tries to match int norm[5] to int which it fails. To fix this, make sure the declaration is correct. Change the declarations to this :
double normalize(int[], int);
double normalize(double[], double);
This will fix the error you are asking about in this question, but your example still has other problems. Some of them are identified in the comments.

Answer 2

You declare prototypes for non-pointer parameters:
double normalize (int , int);
double normalize (double,double);
You call with pointer arguments:
cout<<"The mean is: "<<normalize(norm,5)
The C++ compiler at that point does not care about the implementation with pointer arguments below. Try matching implementation to prototypes.
Also
a) you increment value but use n as index:
cin>> norm[n];
value++;
b) you ignore SIZE
c) SIZE should be unsigned int in both cases
d) your example is not minimal (https://stackoverflow.com/help/mcve)
You might find this generally useful:
https://ericlippert.com/2014/03/05/how-to-debug-small-programs/