c++ cast int to double not working - c++

Question

int main(){
srand(time(0));
int numOfTimes;
int randNum;
int oneRoll = 0, twoRoll = 0, threeRoll = 0, fourRoll = 0, fiveRoll = 0, sixRoll = 0;
int onePercent, twoPercent, threePercent, fourPercent, fivePercent, sixPercent;
int count = 0;
cout << "How many times would you like to roll the dice?\n";
cin >> numOfTimes;
while (numOfTimes <= 0){
cout << "Invalid entry enter a number greater than 0\n";
cout << "How many times would you like to roll the dice?\n";
cin >> numOfTimes;
}
while (count < numOfTimes)
{
randNum = rand() % 6 + 1;
switch (randNum)
{
case 1:
oneRoll++;
break;
case 2:
twoRoll++;
break;
case 3:
threeRoll++;
break;
case 4:
fourRoll++;
break;
case 5:
fiveRoll++;
break;
case 6:
sixRoll++;
break;
default:
cout << "\n";
}
count++;
}
onePercent = (int)((oneRoll*100.0) /numOfTimes);
twoPercent = (int)((twoRoll*100.0) / numOfTimes);
cout << " # Rolled # Times % Times" << endl;
cout << "--------- -------- --------" << endl;
cout << "1 " << oneRoll << " " <<double (onePercent) << endl;
cout << "2 " << twoRoll << " " << "" << endl;
cout << "3 " << threeRoll << " " << ""<< endl;
cout << "4 " << fourRoll << " " <<"" << endl;
cout << "5 " << fiveRoll << " " <<"" << endl;
cout << "6 " << sixRoll << " " <<"" << endl;
I need it to print out the the one percent as a double. So I converted it as an int then to a double so it only prints two zeros like this (14.00) but its not converting at all its only printing 14

Answer 1

The main problem, just as Barmar mentioned in his comment, is that although you want the value to be printed to 2 decimal points, you round off the number in onePercent when you do:
onePercent = (int)((oneRoll*100.0) /numOfTimes); // Casting to "int" rounds off the number
Also, the declared data type for onePercent is int from the start:
int onePercent, twoPercent, threePercent, fourPercent, fivePercent, sixPercent; // onePercent is an "int" here
So you don't need a typecast of int, because you're casting an int to an int.
Therefore, even if you print onePercentwith 2 decimal-point precision, you will always get .00 as a result.
I would recommend taking off the (int) cast from that expression itself, and changing the initial data type of onePercent to type double. If you do not want to change the data types for the other variables declared alongside onePercent, then declare onePercent as a double on another line. That way, the precision of the value after the calculation will be maintained, and you will be able to output it to 2 decimal places.
As an aside, to specify the number of decimal places to output, the setprecision() function can be used:
cout << setprecision(2) << ... << endl; // The value passed to "setprecision" is up to you.