Asyncore TCP server can't print the socket info - python-2.7

Question

I've tried to write an asyncore server to handle with phone and chip.
I tried to identify which connection is for chip or phone by recognizing the messages string sent by them. If the chip say " help, too much water ", server send message "too much water" to phone.
class RequestHandler(asyncore.dispatcher):
def __init__(self, sock, q, addr):
self.sock = sock
self.q = q
def handle_read(self, sock):
self.q = q
c = self.sock.recv(1024).rstrip('\n')
c2 = c.rstrip()
comment = c2.split(',')
if comment[2] == "chip": # To identify chip or phone
self.chip = self.sock
print("chip is "+str(tuple(addr)))
if commentTable[comment[0]] == 7:
self.comment = 7
self.q.put(msgTable[int(comment[1])])
else:
self.comment = commentTable[comment[0]]
else:
self.android = self.sock
print("android is"+str(tuple(addr)))
def handle_write(self):
if self.q.empty():
if self.comment == 0:
self.android.send("time,"+"pH,"+"waterlevel,"+"light"+"video")
else:
while not self.q.empty():
self.sock.send(self.q.get())
The result of the program is that server does not send the message to anyone.
server:
Binding on port = 5000
Connect with('192.168.0.121', 47082)
Connect with('192.168.0.121', 47084)
.....
phone:
$ ./client 192.168.0.121 5000
Please enter the message: state,
It didn't print the info of the phone or chip.
Sorry, I forgot to paste my code about class for server.
class server_socket(asyncore.dispatcher):
def __init__(self, host, port):
asyncore.dispatcher.__init__(self)
self.create_socket(socket.AF_INET, socket.SOCK_STREAM)
self.set_reuse_addr()
self.bind((host, port))
self.listen(5)
print("Binding on port = 5000")
def handle_accept(self):
pair = self.accept()
if pair is not None:
sock, addr = pair
print("Connect with" + str(tuple(addr)))
handler = RequestHandler(sock, queue, addr)