return user id django - django

Question

I have a model field
account_handler = models.ForeignKey(User, blank=True, null=True, related_name='handling_leads', on_delete=models.SET_NULL)
Currently I'm doing something like this
def get_queryset(self):
user_id = User.objects.all()
queryset = User.objects.filter(handling_leads__account_handler=user_id).distinct()
return queryset
and I've got some results for testing purposes. Now the question is, how can I properly use this field and return a user_id? I have tried something like this
User.objects.filter(handling_leads__account_handler=self.request.user.id).distinct()
with out User.objects.all() but that was just returning an empty queryset. I'm trying to filter this so I can populate a table with user__first_name and user__last_name, I need user_id so I can redirect them to their individual page.
controler for the datatable:
app = angular.module 'statistics'
app.controller 'SalesCommissionsListCtrl', ['$scope', '$compile',
($scope, $compile) ->
$scope.init = ()->
fetchCommissionsList()
fetchCommissionsList = ()->
$('#commissionsSalesList').DataTable({
createdRow: (row, data, index) ->
$compile(row)($scope)
sDom: 'lftip',
processing: true,
serverSide:true,
searchDelay: 1000,
orderMulti: false,
pageLength: 10,
ajax: {
url: '/api/statistics/commissions/list/',
data: (data)->
data.limit = data.length;
data.offset = data.start;
data.search = data.search['value'];
if (data.order[0]['dir'] == 'asc')
data.ordering = data.columns[data.order[0]['column']].name;
else
data.ordering = '-' + data.columns[data.order[0]['column']].name;
return 0
dataFilter: (data) ->
json = jQuery.parseJSON(data);
json.recordsTotal = json.count;
json.recordsFiltered = json.count;
json.data = json.results;
return JSON.stringify(json);
}
columns: [
{
data: "username",
name: "username__first_name, username__last_name",
render: (data, type, row, meta)->
return '' + data + '';
}
]
})
]
my ModelViewSet:
from django.contrib.auth.models import User
from rest_framework import viewsets, filters, permissions
from app.restapi.pagination import StandardResultsOffsetPagination
from statistics.restapi.serializers import SalesCommissionsSerializer
from statistics.restapi.permissions import SalesCommissionsListPermissions
class SalesCommissionsViewSet(viewsets.ModelViewSet):
def get_queryset(self):
user_id = User.objects.all()
queryset = User.objects.filter(handling_leads__account_handler=user_id).distinct()
return queryset
serializer_class = SalesCommissionsSerializer
filter_backends = (filters.DjangoFilterBackend, filters.SearchFilter, filters.OrderingFilter)
filter_fields = (
'id', 'username', 'first_name', 'last_name'
)
ordering_fields = (
'id', 'username', 'first_name', 'last_name',
)
search_fields = (
'id', 'username', 'first_name', 'last_name',
)
pagination_class = StandardResultsOffsetPagination
permission_classes = [permissions.IsAuthenticated, SalesCommissionsListPermissions]
serializer:
from django.contrib.auth.models import User
from rest_framework import serializers
class SalesCommissionsSerializer(serializers.ModelSerializer):
class Meta:
model = User
fields = ('id', 'username', 'first_name', 'last_name')

Answer 1

If you want to filter for users who are 'handling leads', you can do the following:
handling_leads = User.objects.filter(handling_leads__isnull=False)
Here's a link to the documentation: https://docs.djangoproject.com/en/1.10/ref/models/querysets/#std:fieldlookup-isnull