How to get local time c++ - c++

Question

I need to get the current time (hour,minutes and seconds) and add 30 minutes. In final i need to save the result to an integer variable.
How it's possible to do?
My code at the moment:
int main()
{
time_t currentTime;
struct tm *localTime;
time( &currentTime );
localTime = localtime( &currentTime );
int Hour = localTime->tm_hour;
int Min = localTime->tm_min;
int Sec = localTime->tm_sec;
std::cout << "Execute at: " << Hour << ":" << Min << ":" << Sec << std::endl;
return 0;
}
Thanks

Answer 1

you can do the following to get time 30 minutes ahead of local time:
time_t currentTime;
struct tm *localTime;
time( &currentTime );
currentTime += 1*30*60;
localTime= localtime(&utc);
The localTime structure now has 30 minutes ahead of current local time.You can get the values in integers as you were doing before.
int Hour = localTime->tm_hour;
int Min = localTime->tm_min;
int Sec = localTime->tm_sec;
In case you need string out of it,you can do
std::string strAheadTime = asctime(localTime);

Answer 2

You can achieve the same like this -
#include <iostream>
#include <ctime>
int main()
{
time_t currentTime;
struct tm *localTime;
time( &currentTime ); // Get the current time
localTime = localtime( &currentTime ); // Convert the current time to the local time
int Hour = localTime->tm_hour;
int Min = localTime->tm_min;
int Sec = localTime->tm_sec;
std::cout << "The current time is : " << Hour << ":" << Min << ":" << Sec << std::endl;
//increase local time by 30 minutes and adjust minutes and hour.
int IncMin = Min + 30;
if(IncMin >= 60){
int res = IncMin/60;
int newMin = IncMin % 60;
Hour += res;
if(Hour > 23){
Hour = 00;
}
std::cout << "The updated time is : " << Hour << ":" << newMin << ":" << Sec << std::endl;
}
return 0;
}