i'm having trouble reading from a text file in C++, so basically I want to read the text file on "cmd" using this code, however, an error pops up.
#include <iostream>
#include <fstream>
#include <string>
using namespace::std;
int main()
{
string line_;
ifstream file("Seminario.txt");
if(file.is_open()){
while(getline(file, line_)){
cout << line_ << endl;
}
file.close();
}
else{
cout << "File is not open" << endl;
cin.get();
return 0;
}
}
When I compile it, I get no errors, however, when I run a.exe, a window pops up saying:
The procedure entry point
_ZNSt7__cxx1112basic_stringlcSt11char_traitslcESalcEEC1Ev could not be located in the dynamic link library C:\Users\pc\Desktop\Progra\a.exe.
How can I fix this?
Related
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
int main() {
string txt="";
ifstream file;
file.open ("ernio.txt", ios::in);
if (file.is_open()) {
while (getline(file, txt)) {
cout << txt << endl;
}
}
else
cout << "example" << endl;
return 0;
}
It prints example instead of reading line by line from the file. What am I doing wrong?!? (the file is in the exact same place as the main.cpp) We even tried:
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
int main() {
string txt="";
ifstream file("ernio.txt");
if (file.is_open()) {
while (getline(file, txt)) {
cout << txt << endl;
}
}
else
cout << "example" << endl;
return 0;
}
Please help
The file needs to be in the directory from where the executable will be called, not in the source directory where your main.cpp resides.
When you build small programs with gcc or something similar from the command line, often the executable is in the current working directory, where the compiler will also draw the source files from.
When using a build system or an IDE, however, then usually the target of a build is different from that where the sources reside.
Premise: I'm using CLion.
As i said in title, when i try to open a file (txt) nothing will be displayed.
i can't explain it, i don't think i made an error, it's pretty easy this code:
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
FILE *leggi;
leggi = fopen("lorem.txt", "r");
char datiLetti[1000];
while(fgets(datiLetti, 1000, leggi)!=NULL){
cout << datiLetti << endl;
}
fclose(leggi);
system("PAUSE");
return EXIT_SUCCESS;
}
file "lorem.txt" is in the same directory of the project.
Thank you in advance.
EDIT1: file is lorem not lorem_ipsum, my mistake when i typed here.
You want this:
...
FILE *leggi;
leggi = fopen("lorem.txt", "r");
if (leggi == NULL)
{
cout << "Can't open file" << endl;
return 1;
}
...
---FIXED---
Installed cygwig1.dll and cygstdc++-6.dll and put cygwig in glob variables, then my file worked in the same directory of main and exe.
However, thank you guys for your time!
fopen is a C solution for open a file if you want to open a file in c++ use fstream like flowing code.
fopen is deprecated in c++11.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main() {
string line;
fstream myfile;
myfile.open("example.txt");
cerr << "Error: " << strerror(errno);
if (myfile.is_open())
{
while (getline(myfile, line))
{
cout << line << '\n';
}
myfile.close();
}
else cout << "Unable to open file";
return 0;
}
I'm trying to open a simple txt.file in c++ (visual studio), but are only triggering "else".
codes.txt is together with the main file in source files and are included. This is more or less how it looks
#include <iostream>
#include <fstream>
int main()
{
std::ifstream file("codes.txt");
if (file.is_open())
{
std::cout << "success" << std::endl;
}
else
{
std::cout << "Unable to open file" << std::endl;
}
}
The txt file did not exist in the folder of the program. Runned perfectly after it was included.
I'm trying to write a program to parse the first and sixteenth columns of a CSV file (converted into .txt). I have the CSV ("posts.txt") document in the folder with the executable. But, whenever I try to run the executable, my program delivers that it cannot open the file (or that "!infile.is_open()"). Mind giving me some assistance? I'm running in Xcode 3.2.3 on Mac OSX 10.8.3. The code is shows below.
#include <iostream>
#include <fstream>
#include <cstdlib>
#include <string.h>
using namespace std;
void answeredPostGrabber()
{
ifstream inFile("posts.txt");
string postNumber;
string answerNumber;
string throwAway;
if(inFile.is_open())
{
while(inFile.good())
{
getline(inFile,postNumber,',');
cout << postNumber << ",";
for(int y=1;y++;y<16)
{
getline(inFile,throwAway,',');
}
getline(inFile,answerNumber,',');
cout << answerNumber << endl;
ofstream edges;
edges.open("edges.txt",ios::app);
edges << postNumber << "," << answerNumber<< endl;
edges.close();
ofstream nodes;
nodes.open("nodes.txt",ios::app);
nodes << postNumber << "\n" << answerNumber << endl;
nodes.close();
getline(inFile,throwAway);
}
}else cout << "ERROR: Unable to open file." << endl;
}
int main ()
{
answeredPostGrabber();
return 0;
}
Thank you in advance!
I have the CSV ("posts.txt") document in the folder with the executable.
The file should be present in the current working directory of your process, which may or may not be the same directory where the executable lives. If in doubt, try specifying the full path in ifstream inFile(...); to see whether that changes things.
Additionally, the file needs to have the correct permissions to ensure that it's readable by the process.
I'm trying to open a file using ifstream, but no matter what solutions I find that I've tried, nothing seems to work; my program always outputs "unable to open". Below is my code in its entirety. Any help at all is appreciated!
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(int argc, char ** argv)
{
string junk;
ifstream fin;
fin.open("somefile.txt");
if(fin.is_open())
{
fin >> junk;
cout << junk;
}
else
{
cout << "unable to open" << endl;
}
fin.close();
return 0;
}
Also, the contents of somefile.txt, which is in the same directory as the created executable is the following:
SOME
FILE
As some commenters have suggested, it could easily be that the file truly doesn't exist, because you're looking for it in the wrong place. Try using an absolute path to the file rather than just assuming it's looking where you expect.
And output a more helpful error message using strerror(errno).
// ...
fin.open("C:\\path\\to\\somefile.txt");
// ...
else
{
cout << "unable to open: " << strerror(errno) << endl;
}