How could I match the following where the IP address can change:
Warning: Permanently added '100.124.61.161' (RSA) to the list of known hosts.
Thanks in advance!
You can try the below code, change the string to restrict only specific texts.
if($string =~ m/Warning: Permanently added '(.*?)' \(RSA\) to the list of known hosts\./)
{
print "Match Successful, IP address: $1\n";
}
else
{
print "String did not match\n";
}
A general regex for the ipv4 (no port) would be
(?<!\d)(?:\d|[1-9]\d|1\d{2}|2[0-4]\d|25[0-5])(?:\.(?:\d|[1-9]\d|1\d{2}|2[0-4]\d|25[0-5])){3}(?!\d)
Explained
(?<! \d )
(?:
\d # 0 - 9
| [1-9] \d # 10 - 99
| 1 \d{2} # 100 - 199
| 2 [0-4] \d # 200 - 249
| 25 [0-5] # 250 - 255
)
(?:
\.
(?:
\d
| [1-9] \d
| 1 \d{2}
| 2 [0-4] \d
| 25 [0-5]
)
){3}
(?! \d )
Related
I'm validating phone number and email using this regex but I'm getting perl syntax error can anyone help me what to use here
^(?:(\d)(?!\1{2}))\d{4,15}$|([A-Za-z0-9]+#[A-za-z]+\.[A-Za-z]{2,3})
I'm validating international numbers between 4-15 and also validating continuously repeated numbers like 1111111111111, 99999999999, 77777777777 we can't use more than 3 repeated numbers also I'm validating email everything is fine but for the repeated number I've to use Perl syntax ?! that's why I'm getting error please help me to solve this
You're not using Perl; you're using RE2. While similar to Perl, it's not quite compatible.
Specifically, it can't handle the pattern you provided. That's what the message is saying. You'll need to provide something RE2 can handle.
The following is the relevant part:
^(?:(\d)(?!\1{2}))\d{4,15}$
In Perl, that checks for a string of 5-16 digits that's optionally followed by line feed, with the caveat that the first three digits can't be the same.
This is equivalent[1] and will work in RE2:
^
(?: 0 (?: 0 [1-9] | [1-9] [0-9] )
| 1 (?: 1 [02-9] | [02-9] [0-9] )
| 2 (?: 2 [0-13-9] | [0-13-9] [0-9] )
| 3 (?: 3 [0-24-9] | [0-24-9] [0-9] )
| 4 (?: 4 [0-35-9] | [0-35-9] [0-9] )
| 5 (?: 5 [0-46-9] | [0-46-9] [0-9] )
| 6 (?: 6 [0-57-9] | [0-57-9] [0-9] )
| 7 (?: 7 [0-68-9] | [0-68-9] [0-9] )
| 8 (?: 8 [0-79] | [0-79] [0-9] )
| 9 (?: 9 [0-8] | [0-8] [0-9] )
)
[0-9]{2,13}
\n?
\z
I don't know RE2, so there might a better solution.
Assuming \d was meant to match [0-9]. It actually matches a whole lot more.
This question already has answers here:
Regex for find All ip address except IP address starts with 172
(3 answers)
Closed 3 years ago.
The following regex captures IP addresses as well as DNS hostnames.
What I'd like is to add some IPs to ignore, such as 1.0.0.0 and 0.0.0.0 for example. I tried some negative lookahead without success.
[\w-]+(\.[\w-]+)+
for example :
www.google.com 255.255.255.255 1.0.0.0 stackoverflow.com 0.0.0.0
should match 3 out of 5 in that line
Any tips would be great.
edit : I tried this, which somewhat works but also filters out other values such as 1.1.1.1 for example
(?![1\.0\.0\.0]|[0\.0\.0\.0])[\w-]+(\.[\w-]+)+
To find IP's and domains while ignoring IP's 1.0.0.0 and 0.0.0.0 and
validation ov Ipv4 and domain contains at least a letter, all wrapped inside
a white space boundary is thisr :
(?<!\S)(?!0{0,2}[01](?:\.0{1,3}){3})(?:(?:0{0,2}\d|0?[1-9]\d|1\d{2}|2[0-4]\d|25[0-5])(?:\.(?:0{0,2}\d|0?[1-9]\d|1\d{2}|2[0-4]\d|25[0-5])){3}|(?=\S*[a-zA-Z])[\w-]+(?:\.[\w-]+)+)(?!\S)
https://regex101.com/r/ZPQS5K/1
Expanded
(?<! \S )
(?! # Not 0.0.0.0 or 1.0.0.0
0{0,2} [01]
(?: \. 0{1,3} ){3}
)
(?:
(?: # IP address
0{0,2} \d
| 0? [1-9] \d
| 1 \d{2}
| 2 [0-4] \d
| 25 [0-5]
)
(?:
\.
(?:
0{0,2} \d
| 0? [1-9] \d
| 1 \d{2}
| 2 [0-4] \d
| 25 [0-5]
)
){3}
| # or
(?= \S* [a-zA-Z] ) # At least a letter
[\w-]+ # Domain
(?: \. [\w-]+ )+
)
(?! \S )
I am trying to get this regex dialed-in to validate whether a URL begins with https and if a port is supplied the only valid values are 443 or 5443. This regex is pretty close but not quite there.
^(https:\/\/)([a-zA-Z\d\.]{2,})\.([a-zA-Z]{2,})(:5{0,1}443)?(.)*
How do I solve this problem?
This is a mainstream URL validator that tests if it's between whitespace boundary's.
It only allows https device and the port numbers 5443 or 443.
(?<!\S)https://(?:\S+(?::\S*)?#)?(?:(?:(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))|localhost)(?::5?443)?(?:/[^\s]*)?(?!\S)
Readable version
(?<! \S )
https ://
(?:
\S+
(?: : \S* )?
#
)?
(?:
(?:
(?:
[1-9] \d?
| 1 \d\d
| 2 [01] \d
| 22 [0-3]
)
(?:
\.
(?: 1? \d{1,2} | 2 [0-4] \d | 25 [0-5] )
){2}
(?:
\.
(?:
[1-9] \d?
| 1 \d\d
| 2 [0-4] \d
| 25 [0-4]
)
)
| (?:
(?: [a-z\u00a1-\uffff0-9]+ -? )*
[a-z\u00a1-\uffff0-9]+
)
(?:
\.
(?: [a-z\u00a1-\uffff0-9]+ -? )*
[a-z\u00a1-\uffff0-9]+
)*
(?:
\.
(?: [a-z\u00a1-\uffff]{2,} )
)
)
| localhost
)
(?: : 5? 443 )?
(?: / [^\s]* )?
(?! \S )
You should append a / after this optional port group so it doesn't allow any digits before a /. Try using this regex,
^(https:\/\/)([a-zA-Z\d\.]{2,})\.([a-zA-Z]{2,})(:5?443)?\/\S*
Notice, I've also changed (:5{0,1}443)? to (:5?443)? and changed last .* to \S* so the url doesn't capture spaces as spaces in URL is not a valid thing. Besides that, you can also get rid of so many groups in your regex, unless you need them.
Regex Demo
Edit:
As you said in comments, that you want to match following URLs too,
https://example.com
https:example.com
https:example.com:443
you need to make \/\S* part optional by placing a ? after them. The modified regex becomes this, which will match above URLs.
^https:\/\/([a-zA-Z\d\.]{2,})\.([a-zA-Z]{2,})(:5?443)?(\/\S*)?
Demo with filepath part being optional
Your RegEx seems to work okay. You may try using this RegEx and add additional boundaries, just for safety, if you wish so:
^(https:\/\/)([a-zA-Z\d\.]{2,})\.([a-zA-Z]{2,}):(5443|443)?$
I only added a $ end char so that to bound your original expression from the right. You may just simply add a few port numbers, if you may have, in this capturing group:
(5443|443)
You can also remove unnecessary boundaries, if you wish.
I have a .txt file which contains:
"'the url address i checked is: https://www.google.com/ for 2times and it's awesome!."
After parsing, the expected output should be:
['"',"'",'the','url','address','i','checked','is',':','https://www.google.com/','for','2','times','and',"it's",'awesome','!','.','"']
How do I split this list to get the output using the re module.
I came up with this pattern:
pattern = re.compile(r"\d+|[a-zA-Z]+[a-zA-Z']*|[^\w\s]")
but this is also splitting my URL.
Can any one please help?
Just pick a url regex from somewhere and make it first in the alternations.
An example only -
# (?!mailto:)(?:(?:https?|ftp)://)?(?:\S+(?::\S*)?#)?(?:(?:(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))|localhost)(?::\d{2,5})?(?:/[^\s]*)?|\d+|[a-zA-Z]+[a-zA-Z']*|[^\w\s]
(?! mailto: )
(?:
(?: https? | ftp )
://
)?
(?:
\S+
(?: : \S* )?
#
)?
(?:
(?:
(?:
[1-9] \d?
| 1 \d\d
| 2 [01] \d
| 22 [0-3]
)
(?:
\.
(?: 1? \d{1,2} | 2 [0-4] \d | 25 [0-5] )
){2}
(?:
\.
(?:
[1-9] \d?
| 1 \d\d
| 2 [0-4] \d
| 25 [0-4]
)
)
| (?:
(?: [a-z\u00a1-\uffff0-9]+ -? )*
[a-z\u00a1-\uffff0-9]+
)
(?:
\.
(?: [a-z\u00a1-\uffff0-9]+ -? )*
[a-z\u00a1-\uffff0-9]+
)*
(?:
\.
(?: [a-z\u00a1-\uffff]{2,} )
)
)
| localhost
)
(?: : \d{2,5} )?
(?: / [^\s]* )?
| \d+
| [a-zA-Z]+ [a-zA-Z']*
| [^\w\s]
Outputs:
['"',"'",'the','url','address','i','checked','is',':','https://www.google.com/','for','2','times','and',"it's",'awesome','!','.','"']
I have some internet traffic data to analyze. I need to analyze only those packets that are within a certain IP range. So, I need to write a if statement. I suppose I need a regular expression for the test condition. My knowledge of regexp is a little weak. Can someone tell me how would I construct a regular expression for that condition. An example range may be like
Group A
56.286.75.0/19
57.256.106.0/21
64.131.14.0/22
Group B
58.176.44.0/21
58.177.92.0/19
The if statement would be like
if("IP in A" || "IP in B") {
do something
}
else { do something else }
so i would need to make the equivalent regexp for "IP in A" and "IP in B" conditions.
I don't think that regexps provide much advantage for this problem.
Instead, use the Net::Netmask module. The "match" method should do what you want.
I have to echo the disagreement with using a regex to check IP addresses...however, here is a way to pull IPs out of text:
qr{
(?<!\d) # No digit having come immediately before
(?: [1-9] \d? # any one or two-digit number
| 1 \d \d # OR any three-digit number starting with 1
| 2 (?: [0-4] \d # OR 200 - 249
| 5 [0-6] # OR 250 - 256
)
)
(?: \. # followed by a dot
(?: [1-9] \d? # 1-256 reprise...
| 1 \d \d
| 2 (?: [0-4 \d
| 5 [0-6]
)
)
){3} # that group exactly 3 times
(?!\d) # no digit following immediately after
}x
;
But given that general pattern, we can construct an IP parser. But for the given "ranges", I wouldn't do anything less than the following:
A => qr{
(?<! \d )
(?: 56\.186\. 75
| 57\.256\.106
| 64\.131\. 14
)
\.
(?: [1-9] \d?
| 1 \d \d
| 2 (?: [0-4] \d
| 5 [0-6]
)
)
(?! \d )
}x
B => qr{
(?<! \d )
58 \.
(?: 176\.44
| 177\.92
)
\.
(?: [1-9] \d?
| 1 \d \d
| 2 (?: [0-4] \d
| 5 [0-6]
)
)
(?! \d )
}x
I'm doing something like:
use NetAddr::IP;
my #group_a = map NetAddr::IP->new($_), #group_a_masks;
...
my $addr = NetAddr::IP->new( $ip_addr_in );
if ( grep $_->contains( $addr ), #group_a ) {
print "group a";
}
I chose NetAddr::IP over Net::Netmask for IPv6 support.
Martin is right, use Net::Netmask. If you really want to use a regex though...
$prefix = "192.168.1.0/25";
$ip1 = "192.168.1.1";
$ip2 = "192.168.1.129";
$prefix =~ s/([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)\/([0-9]+)/$mask=(2**32-1)<<(32-$5); $1<<24|$2<<16|$3<<8|$4/e;
$ip1 =~ s/([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)/$1<<24|$2<<16|$3<<8|$4/e;
$ip2 =~ s/([0-9]+)\.([0-9]+)\.([0-9]+)\.([0-9]+)/$1<<24|$2<<16|$3<<8|$4/e;
if (($prefix & $mask) == ($ip1 & $mask)) {
print "ip1 matches\n";
}
if (($prefix & $mask) == ($ip2 & $mask)) {
print "ip2 matches\n";
}