SyntaxError: invalid syntax when opening a file - regex

import re
fhand = open('sum.txt','r')
number = re.findall('[0-9]'+, fhand)
print number
I am getting syntax error as
number = re.findall('[0-9]'+, fhand)
^
SyntaxError: invalid syntax
Not sure what's going on. Can anybody help?

Read the file contents and declare the entire pattern inside a string literal.
Here is an example:
>>> import re
>>> fhand = open(r'D:\2\_1.txt','r')
>>> fhand
<open file 'D:\\2\\_1.txt', mode 'r' at 0x0282B230>
>>> number = re.findall('[0-9]+', fhand.read())
>>> print number
['1', '2', '3', '1', '0', '2', '0', '7', '0', '2', '2', '0', '3', '0', '5', '0', '3']
>>>

Related

why does the last character disappear?

The file contents are:
min:1,2,3,4,5,6
max:1,2,3,4,5,6
avg:1,2,3,4,5,6
Code:
def avg_calc():
total = 0
nums_inLine = line[4: -1]
num_list = []
num_list = nums_inLine.split(',')
length = len(num_list)
print(num_list)
with open('input.txt', 'r', encoding='utf-8-sig') as in_file:
content = in_file.readlines()
for line in content:
if 'min' in line:
min_calc()
elif 'max' in line:
max_calc()
elif 'avg' in line:
avg_calc()
My problem is that the '6' in the third line disappears or replaced by a whitespace. Why does it do that?
Output:
['1', '2', '3', '4', '5', '']
final goal is to cast each element in the list to an int then perform calculations to calculate the average of the numbers.

Group repeating list objects with itertools.groupby()

I have a list, where I want to group the repeating objects into a single object in the new list. Basically, convert this:
s = ['0.352125', '1', '1', '1', '1', '0', '0', '0', '0', '0', '0', '0', '0', '0.241041', '0.313429', '1', '1']
to this:
s_new = ['0.352125', '4*1','8*0', '0.241041', '0.313429','2*1']
I have tried itertools.groupby() function (python 2.7) as below:
from itertools import groupby
s_g = [list(g) for k, g in groupby(s)]
s_new = [', '.join('{}*{}'.format(sum(1 for _ in g), k) for k, g in groupby(s_g))]
As a result, I get:
s_new = ["1*['0.352125'], 1*['1', '1', '1', '1'], 1*['0', '0', '0', '0', '0', '0', '0', '0'], 1*['0.241041'], 1*['0.313429'], 1*['1', '1']"]
Apparently, this is not the list format I'm trying to get. Could someone please help me with this?
You unnecessarily applied groupby twice and there's also no reason to use str.join.
You can use the following list comprehension instead:
['%s*' % len(l) * (len(l) > 1) + k for k, g in groupby(s) for l in (list(g),)]

write a Python 3 list to .csv

I have a list that i need to write to a .csv Yes, i have done a LOT of looking around (of course i found this link which is close to the target, but misses my case) You see writerows is having all sorts of trouble with the delimiters/formatting in the .csv (the a gets separated from the 1 from the 7 etc etc)
My list looks like this:
buffer = [['a17', 'b17', 'c17', '8', 'e17', 'f17\n'], ['a24', 'b24', 'c24', '6', 'e24', 'f24\n'], ['a27', 'b27', 'c27', '9', 'e27', 'f27\n'], ['a18', 'b18', 'c18', '9', 'e18', 'f18\n'], ['a5', 'b5', 'c5', '5', 'e5', 'f5\n'], ['a20', 'b20', 'c20', '2', 'e20', 'f20\n'], ['a10', 'b10', 'c10', '1', 'e10', 'f10\n'], ['a3', 'b3', 'c3', '3', 'e3', 'f3\n'], ['a11', 'b11', 'c11', '2', 'e11', 'f11\n']]
I can see its like a list of lists so i tried for eachRow in buffer: then following on with a eachRow.split(',') but no good there either.
I just need to write to a .csv it should be easy right... what am i missing?
You can remove the \n string from your buffer like so. Also you have to add newline='' to the with statement in Python 3. See this answer for more detail.
import csv
buffer = [['a17', 'b17', 'c17', '8', 'e17', 'f17\n'],
['a24', 'b24', 'c24', '6', 'e24', 'f24\n'],
['a27', 'b27', 'c27', '9', 'e27', 'f27\n'],
['a18', 'b18', 'c18', '9', 'e18', 'f18\n'],
['a5', 'b5', 'c5', '5', 'e5', 'f5\n'],
['a20', 'b20', 'c20', '2', 'e20', 'f20\n'],
['a10', 'b10', 'c10', '1', 'e10', 'f10\n'],
['a3', 'b3', 'c3', '3', 'e3', 'f3\n'],
['a11', 'b11', 'c11', '2', 'e11', 'f11\n']]
for row_index, list in enumerate(buffer):
for column_index, string in enumerate(list):
buffer[row_index][column_index] = buffer[row_index][column_index].replace('\n', '')
with open('output.csv', 'w', newline='') as f:
writer = csv.writer(f)
writer.writerows(buffer)
import csv
with open('output.csv','w') as f:
writer = csv.writer(f)
writer.writerows(buffer)
Note that the last entry in each of your lists has a newline, so the csvwriter is correctly quoting the string so you end up with "f17\n" (in the first list as an example) which will look strangely formatted if you are not expecting a new line.

Decrypt .ini, and use values?

I have a XOR function:
string encryptDecrypt(string toEncrypt) {
char key[64] = { 'F', '2', 'D', 'C', '5', '4', '0', 'D', 'B', 'F', '3', 'E', '1', '2', '9', 'F', '4', 'E', 'A', 'A', 'F', '7', '6', '7', '5', '6', '9', 'E', '3', 'C', 'F', '9', '7', '5', '2', 'B', '4', 'B', '8', '2', '6', 'D', '9', '8', 'F', 'D', '8', '3', '8', '4', '6', '0', '8', '5', 'C', '0', '3', '7', 'D', '3', '5', 'F', '7', '5' };
string output = toEncrypt;
for (int i = 0; i < toEncrypt.size(); i++)
output[i] = toEncrypt[i] ^ key[i % (sizeof(key) / sizeof(char))];
return output;
}
I encrypted my .ini :
[test]
baubau = 1
haha = 2
sometext = blabla
How i tried to decrypt and use values:
std::string Filename = "abc.ini";
std::ifstream input(Filename, std::ios::binary | ios::in); // Open the file
std::string line; // Temp variable
std::vector<std::string> lines; // Vector for holding all lines in the file
while (std::getline(input, line)) // Read lines as long as the file is
{
lines.push_back(encryptDecrypt(line));
}
// Here i should call the ini reader? but how?
CIniReader iniReader("abc.ini");
string my = encryptDecrypt(iniReader.ReadString("test", "baubau", ""));
for (auto s : lines)
{
cout << my;
cout << endl;
}
Where is my mistake? Some help would be apreciated, Many Thanks!
What you can do is:
Read the file line by line, and break apart keys and values, i.e. where you see 'key=value' break it apart into key and value.
Encrypt the value.
Base64-encode the value, in case it is no longer valid text in the encoding of the file.
Replace the line with 'key=base64-encoded-value'.
Later, when you read the encoded value for the key, which is just a simple Base64-encoded string of bytes, Base64-decode the string, and the decrypt the value.
For example, this line:
baubau = 1
Take the value '1' as a string, and encrypt it with your function. The result in this case is a printable string 'w'. However, I would treat it as arbitrary bytes.
Base64-encode the "encrypted" value. For example, the Base64-encoding of 'w' in UTF-8 (or ASCII) is "dw==".
Replace the line with:
baubau = dw==
or, if you like:
baubau = "dw=="
Later, when you read the value for baubau, you simply Base64-decode 'dw==', obtaining 'w', and then decrypt 'w' to arrive at '1'.

Creating Lists from CSV File in python 2.7 using two different read line commands

I am a newbie at Python 2.7 and used the following code to create the list of observations pulled from a csv file.
import csv
data = []
with open(datafile,'rb') as f:
for row in f:
g=row
data.append(g)
It produces the following list (after reading the first row):
['01/01/2005,01:00,0,0,0,2,0,0,2,0,0,2,0,0,2,0,0,2,0,0,2,0,0,2,0,3,E,9,3,E,9,8.0,A,7,6.0,A,7,87,A,7,1013,A,7,150,A,7,2.1,A,7,16100,A,7,77777,A,7,1.1,E,8,0.099,F,8,0.160,F,8,0,1,A,7']
But when I use the following code to read the csv file and create the list:
data = []
with open(datafile,'rb') as f:
r = csv.reader(f)
for row in f
data = [row for row in r]
I get a list that looks as follows (after reading the first row):
['01/01/2005', '01:00', '0', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '3', 'E', '9', '3', 'E', '9', '8.0', 'A', '7', '6.0', 'A', '7', '87', 'A', '7', '1013', 'A', '7', '150', 'A', '7', '2.1', 'A', '7', '16100', 'A', '7', '77777', 'A', '7', '1.1', 'E', '8', '0.099', 'F', '8', '0.160', 'F', '8', '0', '1', 'A', '7']
This also appears to be a list (with the key difference being the apostrophes around each item in the list instead of just at the beginning and the end).
Since both appear to be lists, why does the code that uses data.append not deliver a similar list?
Your first list has just one single element -- a string holding the entire line, inclusing all the commas.
>>> l1 =['01/01/2005,01:00,0,0,0,2,0,0,2,0,0,2,0,0,2,0,0,2,0,0,2,0,0,2,0,3,E,9,3,E,9,8.0,A,7,6.0,A,7,87,A,7,1013,A,7,150,A,7,2.1,A,7,16100,A,7,77777,A,7,1.1,E,8,0.099,F,8,0.160,F,8,0,1,A,7']
>>> len(l1)
1
In your second example, csv.reader splits this line into several elements and puts those into the list.
>>> l2 = ['01/01/2005', '01:00', '0', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '0', '2', '0', '3', 'E', '9', '3', 'E', '9', '8.0', 'A', '7', '6.0', 'A', '7', '87', 'A', '7', '1013', 'A', '7', '150', 'A', '7', '2.1', 'A', '7', '16100', 'A', '7', '77777', 'A', '7', '1.1', 'E', '8', '0.099', 'F', '8', '0.160', 'F', '8', '0', '1', 'A', '7']
>>> len(l2)
68
Also note that the loop in your second example is somewhat odd. I assume that this is not your actual code, since there's a syntax error in it. It should probably rather be:
r = csv.reader(f)
for row in r: # row in r, not row in f
data.append(row) # append row to data -> 2d-array of items in rows