XSLT - Copy all nodes and add extra node in copied nodes - xslt

Question

I am looking for XSLT(1.0) code for below input and output XML.
In output XML, there can be any child node under C6 element. In below XML, i have put CN element but it could be any name.
Input XML -
<?xml version = "1.0" encoding = "UTF-8"?>
<root>
<input>
<c2>
<c3>
<c4>c4</c4>
</c3>
</c2>
</input>
<output>
<c5>
<c6>
<CN>
<T1></T1>
<T2></T2>
</CN>
</c6>
<c6>
<CN>
<T1></T1>
<T2></T2>
</CN>
</c6>
</c5>
</output>
</root>
Desired Output XML-
<root>
<output>
<c5>
<c6>
<!-- It could have any child node. Putting an example with CN child node name.-->
<CN>
<T1></T1>
<T2></T2>
<c3>
<c4>c4</c4>
<NewNode>current number of CN node which will be 1</NewNode>
<NewNode1>total number of C6 nodes which will be 2.</NewNode1>
</c3>
</CN>
</c6>
<c6>
<CN>
<T1></T1>
<T2></T2>
<c3>
<c4>c4</c4>
<NewNode>current number of CN node which will be 2</NewNode>
<NewNode1>total number of C6 nodes which will be 2.</NewNode1>
</c3>
</CN>
</c6>
</c5>
</output>
</root>
Thank you in advance.

Answer 1

Use the following stylesheet:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="c6/*">
<xsl:copy>
<xsl:variable name="v1" select="count(../preceding-sibling::*)+1"/>
<xsl:variable name="v2" select="count(../../*)"/>
<xsl:apply-templates/>
<xsl:apply-templates select="../../../../input/c2/c3">
<xsl:with-param name="v1" select="$v1"/>
<xsl:with-param name="v2" select="$v2"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
<xsl:template match="c3">
<xsl:param name="v1"/>
<xsl:param name="v2"/>
<xsl:copy>
<xsl:apply-templates/>
<NewNode><xsl:value-of select="$v1"/></NewNode>
<NewNode1><xsl:value-of select="$v2"/></NewNode1>
</xsl:copy>
</xsl:template>
<xsl:template match="input"/>
<xsl:template match="#*|node()">
<xsl:copy><xsl:apply-templates select="#*|node()"/></xsl:copy>
</xsl:template>
</xsl:stylesheet>