I want to create keyboard bindings, which work at least similarly on different keyboard layouts. My problem is that the shift modifier converts keys into different keys, as detailed in the documentation: http://doc.qt.io/qt-5/qkeysequence.html#keyboard-layout-issues
Is there any way to find out the original key irrespective of the keyboard layout?
E.g. find out that . is pressed when shift+. is pressed.
See also this (currently unanswered) quesion: get shift+numerical keys in qt using qkeyevent
In Windows you can use MapVirtualKeyA and MAPVK_VK_TO_CHAR to get the unshifted key. MapVirtualKeyA needs the virtual key, which can be get using QKeyEvent::nativeVirtualKey.
Note: When pressing modifiers only QKeyEvent::key() may report a false character, the virtual key helps to distinguish these cases.
Example
void MainWindow::keyPressEvent(QKeyEvent* ke)
{
const auto vk = ke->nativeVirtualKey();
const auto unshifted_key = MapVirtualKeyA(vk, MAPVK_VK_TO_CHAR);
qDebug() << "Original key:" << (char)ke->key();
qDebug() << "Unshifted key:" << (char)unshifted_key;
if (unshifted_key > 0) {
// Printing the full key sequence just for comparison purposes
QString modifier;
if (ke->modifiers() & Qt::ShiftModifier) modifier += "Shift+";
if (ke->modifiers() & Qt::ControlModifier) modifier += "Ctrl+";
if (ke->modifiers() & Qt::AltModifier) modifier += "Alt+";
if (ke->modifiers() & Qt::MetaModifier) modifier += "Meta+";
const QKeySequence ks(modifier + QChar(ke->key()));
qDebug() << "Full key sequence:" << ks.toString();
}
}
The full source code for the example can be found in here.
Related
In my current application, I need to make QT close a window by pressing Shift + Eesc or by pressing Esc 3x.
First, I tried Shift + Esc, it went this way
if ((event->key() == Qt::Key_Escape) && (event->key() == Qt::Key_Shift))
{
cout << "test" << endl;
on_close_x_button_clicked();
}
But for some reason, it just doesn't work. I googled it and found something about a QKeySequence but I didn't find any example of how to do it properly. I tried some ways with no success like:
if ((event->key() == Qt::QKeySequence(Qt::Key_Escape + Qt::Key_Shift)))
{
cout << "teste" << endl;
on_close_x_button_clicked();
}
}
But again, no dice. Can someone point me how to proper implement this functionality?
I also could not find anything that allowed me to create an event based on pressing Escape key 3x. Can someone, please, also teach me how to do it?
I also tried using Shortcuts, and it went like this:
LinAdvancedTestWidget::LinAdvancedTestWidget(QWidget *parent,
QObject *event_filter,
SystemEvent *event, int dpi)
: AdvancedTestWidget(parent, event_filter, event) {
(void)dpi;
KeyShiftEsc = new QShortcut(this);
KeyShiftEsc->setKey(Qt::Key_Shift + Qt::Key_Escape);
connect(KeyShiftEsc, SIGNAL(activated()), this, SLOT(slotShortcutShiftEsc()));
}
void LinAdvancedTestWidget::slotShortcutShiftEsc()
{
cout << "Escape LinAdvancedTestWidget" << endl;
on_close_x_button_clicked();
}
But it again, also does not work :/
Shift is a modifier, not a key, as you seem to compare. You would need to write something like this:
if ((event->key() == Qt::Key_Escape) && (event->modifiers() & Qt::Key_Shift))
{
...
}
Also, it is better if you use the QWidget::addAction(...) method as:
QAction *action = new QAction("my action", "Shift+Esc");
myWidget->addAction(action);
You can also set multiple shortcuts on an action:
action->setShorcuts({"Shift+Esc", QKeySequence(Qt::Key_Esc, Qt::Key_Esc, Qt::Key_Esc)});
I'm trying to make my software filter a list of elements.
I think I need to put my data in a TableWidget because I have to display other information.
I also put 3 Line Edit to search respectively in each category (called leName, leSource, leDestination)
so I tried to implement my filter for the name property, for now I have :
void MyClass::on_leName_textEdited(const QString &arg1)
{
for (int i=0;ui->tableWidget->rowCount()-1;i++)
{
qDebug()<<"before if";
if(ui->tableWidget->item(0,1)->text().contains(arg1) //tried with &arg1, I have the same issue, for now
{
qDebug()<<"If validated";
ui->tableWidget->showRow(i);
}else{
qDebug()<<"If not validated"
ui->tableWidget->hideRow(i)
}
}
}
When I hit a key, my soft crashes
I get "Before if", "If (not) validated", "Before if" from qDebug
I launched with debbugger and got Segmentation fault as error
not sure what I could add as detail about my error
Maybe I did nothing in the good way, I'm no expert in Qt nor c++
If you have any idea of what I should do to correct this, I would appreciate it =)
The fact that a cell exists does not imply that it has an associated QTableWidgetItem, so you must verify that it is not null.
QTableWidgetItem * item = ui->tableWidget->item(0, 1);
if(item && item->text().contains(arg1))
{
qDebug() << "If validated";
ui->tableWidget->showRow(i);
}else{
qDebug() << "If not validated"
ui->tableWidget->hideRow(i)
}
I'm using Qt 5.11.
I need to catch shift + 3 on one key press. But this combination generates special character ^ because I'm using Turkish Q Keyboard. So I can't catch it without press shift + 3 again.
I tried shift modifiers and multiple key press solutions but not working.
I want to override ^. Is there any possible ways to do it?
Try the following it could work. Although according to the documentation, nativeVirtualKey could return 0 even if there is valid information. So not sure if it will work all the time. I tested it with a german, english and arabic keyboard.
Update (tested it with turkish keyboard layout)
void keyPressEvent(QKeyEvent *ev)
{
if ((ev->nativeVirtualKey() == Qt::Key_3 || ev->key() == Qt::Key_3) && ev->modifiers() == Qt::ShiftModifier)
{
//Do something
}
}
For turkish layout, ^ caret (a dead key), in addition to the above, you can catch the dead key press by overriding the nativeEvent function and calling the keyEvent function manually
bool nativeEvent(const QByteArray & eventType, void * message, long * result)
{
MSG *msg = reinterpret_cast<MSG*>(message);
if (msg->message == WM_DEADCHAR)
{
QKeyEvent *key = new QKeyEvent(QEvent::KeyPress, Qt::Key_3, Qt::ShiftModifier);
}
}
One minor issue, the keyEvent will be called even if ^ is pressed in another language, not necessarily only with Shift+3, so this is an unexpected behaviour, but maybe for your case you can tell the user that both shift+3 or ^ are the shortcut for your specific function
I have a program that captures a single key press and then outputs the key that is being pressed. The problem is, I am not able to return the value of the key being pressed and cannot get the arrow keys to output anything at all. Here's my code:
myApp.h
class someClass: public QDialog
{
Q_OBJECT
public:
...<snip>...
private:
...<snip>...
protected:
void keyPressEvent(QKeyEvent *e);
};
myApp.cpp
MyApp::MyApp(QWidget *parent) :
QDialog(parent),
ui(new Ui::myApp)
{
QWidget::grabKeyboard();
ui->setupUi(this);
}
void someClass::keyPressEvent(QKeyEvent *e)
{
qDebug() << "You typed " + e->key();
}
There are two issues here. First, when I type any key, I get output like the following in the Debug pane:
gw492_32\include/QtCore/qstring.h
w492_32\include/QtCore/qstring.h
492_32\include/QtCore/qstring.h
92_32\include/QtCore/qstring.h
I typed abcd to get the above. Shouldn't key() give me the integer value of the key pressed?
The second issue is that when I hit one of the arrow keys, I get nothing in the debug pane except for a blank line. Again, shouldn't I be seeing the integer value for the Up arrow? (values for keys listed here). How would I then output the ASCII value for the key?
Any help is appreciated.
The output definitely looks like unwanted pointer arithmetic is happening. And it's undefined behavior.
"You typed " + e->key()
advances the pointer to "You typed " by e->key() and makes it point to another location, which is in this case occupied by the string you're getting as output.
If you want to print it properly, do any of the following:
qDebug() << "You typed " << e->key();
qDebug() << "You typed " + QString::number(e->key());
qDebug() << QString("You typed %1").arg(e->key());
I am trying to understand how to handle various events with Qt and have found an issue I cannot understand with key modifiers e.g. Ctrl Shift Alt etc. I have made a default Qt GUI Application in Qt Creator extending QMainWindow and have found that the following example does not produce understandable results.
void MainWindow::keyPressEvent(QKeyEvent *event)
{
qDebug() << "Modifier " << event->modifiers().testFlag(Qt::ControlModifier);
qDebug() << "Key " << event->key();
qDebug() << "Brute force " << (event->key() == Qt::Key_Control);
}
Using the modifiers() function on the event never is true while the brute force method returns the correct value.
What have I done wrong?
Try using this to check for shift:
if(event->modifiers() & Qt::ShiftModifier){...}
this to check for control:
if(event->modifiers() & Qt::ControlModifier){...}
and so on. That works well for me.
EDIT:
To get the modifiers of a wheel event, you need to check the QWheelEvent object passed to your wheelEvent() method:
void MainWindow::wheelEvent( QWheelEvent *wheelEvent )
{
if( wheelEvent->modifiers() & Qt::ShiftModifier )
{
// do something awesome
}
else if( wheelEvent->modifiers() & Qt::ControlModifier )
{
// do something even awesomer!
}
}
According to the documentation, QKeyEvent::modifiers cannot always be trusted. Try to use QApplication::keyboardModifiers() static function instead.
From Qt 5 Doc. – Qt::KeyboardModifiers QKeyEvent::modifiers() const:
Warning: This function cannot always be trusted. The user can confuse it by pressing both Shift keys simultaneously and releasing one of them, for example.