Random letter generator game [closed] - c++

Question

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 5 years ago.
Improve this question
Warning: I am brand new to programing! I am trying to create a random letter generator game for a class project. I feel like I have a decent start to it but I am having difficulty with a few points.
The program is supposed to ask the player how many games they would like to play(1-5). The maximum number of guesses they get per game is 5 and then it is supposed to print out what the correct answer was if it was not guessed. As it is, I have it so that it will run the correct number of guesses but not games and it dosent cout<< the correct answer when all guesses are done. Any help is appreciated, thanks.
#include<iostream>;
#include<cstdlib>;
#include<ctime>;
using namespace std;
int main()
{
char alphabet [27];
int number_of_games;
char guess;
int x = 1;
srand(time(0));
int n = rand() % 26 + 1;
cout<<"Weclome to the Letter Guessing game!\n";
cout<<"You have 5 chances to guess each letter.\n \n";
cout<<"How many games do you want to play?\n";
cin >> number_of_games;
cout<<"**************************************************\n\n";
while (x <= number_of_games) //Need to get it for how many rounds, not how many guesses
{
if (number_of_games < 1)
{
cout<< "Lets play game " << number_of_games << '\n';
}
//cout << (char)(n+97); //cheat to make sure working
cout<<"Enter your guess: ";
cin >> guess;
int guessValue = int(guess);
if (guessValue > (n+97))
{
cout<<"The letter you are trying to guess is before " <<guess <<"\n";
}
else if (guessValue < (n+97))
{
cout<<"The letter you are trying to guess is after " <<guess << "\n";
}
else if( (char)(n+97))
{
cout << "The answer you were looking for was " << (char)(n+97) << "\n";
}
else
{
cout<<"Your guess is correct! \n";
break;
}
//if answer is not right after x tries, cout the correct answer
x++;
}
system("pause");
return 0;
}

Answer 1

You can use "nested loops" - an outer loop for games, and an inner loop for turns. I've used a for loop in my example.
Also, no need to convert everything to int. char is an integral type and can be used just like a number:
while (x <= number_of_games) //Need to get it for how many rounds, not how many guesses
{
// Select a new char (a-z) for each game
char n = 97 + rand() % 27;
cout << "Lets play game " << x << '\n';
// 5 guesses
for (int number_of_guesses = 0; number_of_guesses < 5; number_of_guesses++) {
cout << "Enter your guess: ";
cin >> guess;
if (guess > n)
{
cout << "The letter you are trying to guess is before " << guess << "\n";
}
else if (guess < n)
{
cout << "The letter you are trying to guess is after " << guess << "\n";
}
else
{
cout << "Your guess is correct! \n";
// Break out of the inner for loop, not the while
break;
}
}
x++;
}