loop control to break from current if loop - exit

Question

I am trying loop control. while loop then a for loop and inside it there are couple of if loops, if 3 of the if loop satisfies it should exit the for loop to continue with while loop else it should exit the if loop to continue rest of for loop iterations
LIMIT=100
while [ "count" -le "$LIMIT" ]
do
for i in 1 2 3 4 5
do
var a
var b
var c
var d
if [ $d -eq 1 ] && [ $a == Done ] && [ $b -eq 0 ]
then
echo "$c" | tr '\n' '\t'
echo "Successful"
break 2 # Need to exit entire for loop
elif [ $d -eq 0 ] && [ $a == Done ] && [ $b -eq 0 ]
then
break # Need to go to next iteration of for
elif [ $a == Active ]
then
echo "Active" # Need to exit entire for loop
break 2
elif [ $d -eq 1 ] && [ $a == Done ] && [ $b -gt 0 ]
then
echo "Fail" # Need to exit entire for loop
break 2
elif [ $a == Queued ]
then
echo "Queued" # Need to exit entire for loop
break 2
else
echo "Nothing"
fi
done
done
For some reason it exits everything when first if loop is true.

Answer 1

Got it, actually I was using break 2 which was exiting for as well as while as if is already being exited so using single break would let me exit for loop entirely, and to continue for next iteration for any of the if loop needed to use continue.
so the code should be
LIMIT=100
while [ "count" -le "$LIMIT" ]
do
for i in 1 2 3 4 5
do
var a
var b
var c
var d
if [ $d -eq 1 ] && [ $a == Done ] && [ $b -eq 0 ]
then
echo "$c" | tr '\n' '\t'
echo "Successful"
break # will exit entire for loop
elif [ $d -eq 0 ] && [ $a == Done ] && [ $b -eq 0 ]
then
continue # will go to next iteration of for
elif [ $a == Active ]
then
echo "Active"
break # will exit entire for loop
elif [ $d -eq 1 ] && [ $a == Done ] && [ $b -gt 0 ]
then
echo "Fail"
break # will exit entire for loop
elif [ $a == Queued ]
then
echo "Queued"
break # will exit entire for loop
else
echo "Nothing"
fi
done
done