Printing int **x in GDB - c++

Question

I have an array (called board) of pointers which point to array.
I want to print it in normal way (which is pretty hard in GDB).
int col = 64, row = 2;
int **board = new int*[col];
for(int i = 0; i < col; i++)
board[i] = new int[row];
I have tried following commands:
p *array#len (the problem is it prints in hexadecimal values not as integer)
x/100w array (It scrolls so much down that i cannot even see the values)
*(T (*)[N])p (where p is array, T is type of array and N is size of it) [It just does not print accurate]

Answer 1

I want to print it in normal way
Your best bet is to write a print_board routine, which you can then call from GDB.
(which is pretty hard in GDB).
That's because you made it hard.
The problem is that your board, rather than being contiguous in memory (as is customary and would be trivial to print in GDB), is instead spread out in 64 separate chunks of 2 values each.
Since you are using C++, you'll be better off using a vector of vectors:
vector<vector<int>> board;
board.resize(col);
for (int i = 0; i < col; i++) {
board[i].resize(row);
}
(gdb) print board
$1 = std::vector of length 64, capacity 64 =
{std::vector of length 2, capacity 2 = {0, 0},
std::vector of length 2, capacity 2 = {0, 0},
...
P.S. When asking questions, it helps to show actual code. Your question has the wrong type for board, and mixes board with array.
Update:
How can I do that (use print_board from GDB)?
Here is an example. Suppose your source looks like this:
1 #include <stdio.h>
2
3 int main()
4 {
5 int col = 16, row = 2;
6 int **board = new int*[col];
7
8 for (int i = 0; i < col; i++) {
9 board[i] = new int[row];
10 }
11
12 // Initialize elements to something interesting, so we can see them
13 // printed.
14 for (int i = 0; i < col; i++)
15 for (int j = 0; j < row; j++)
16 board[i][j] = 100*i + j;
17
18 return 0;
19 }
20
21 void print_board(int **board, int col, int row)
22 {
23 for (int j = 0; j < row; j++) {
24 for (int i = 0; i < col; i++) {
25 printf("\t%d", board[i][j]);
26 }
27 printf("\n");
28 }
29 }
Then, using GDB:
gdb -q ./a.out
(gdb) break 18
(gdb) run
Breakpoint 2, main () at t.cc:18
18 return 0;
(gdb) call print_board(board, col, row)
0 100 200 300 400 500 600 700 800 900 1000 1100 1200 1300 1400 1500
1 101 201 301 401 501 601 701 801 901 1001 1101 1201 1301 1401 1501
voilà