Swapping 2d array minimum row value with reverse diagonal - c++

Question

I am trying to swap minimum row value with reverse diagonal. I managed to print out every row minimum value, but my swap fails. Maybe you could give me some hints.
for (int i = 0; i < n; i++)
{
int min = mas[i][0];
for (int j = 1; j < m; j++)
{
if (mas[i][j] < min)
{
min = mas[i][j];
}
for(int k=n-1;k>0;k--){
for(int h = m-1; h>0;h--){
min = mas[i][j];
mas[i][j]=mas[k][h];
mas[k][h]=min;
}
cout << "New Matrix\n";
for(int i = 0; i < n; i++) {
for(int j = 0; j < m; j++) {
cout << mas[i][j] << " ";
}
}
}
}
system("pause");
return EXIT_SUCCESS;
}
This is my for for a minimum value and later I am adding another for to swap values.
My result:
I go printed out 3 matrices and none of them are correctly swapping value. I guess it's because of for in for cycle?
My file with with 2d array:
1 2 5 // row min 1, reverse diagonal 5
2 8 9 // row min 2, reverse diagonal 8
5 9 10 // row min 5, revese diagonal 5
What output I expect:
5 2 1 // 5 diagonal swap with min = 1
8 2 9 // 8 diagonal swap with min = 2
5 9 10 // 5 diagonal no swap because 5 is row minimum

Answer 1

If I understand correctly then the "reverse diagonal" can be present only in a square matrix. So there is no sense to enter two values n and m to deal with a square matrix.
If to consider the example of a 3 x 3 matrix shown in your question and to use loops instead of for example standard functions std::max_element and std::swap then the code that converts the matrix can look the following way as it is shown in the demonstrative program
#include <iostream>
#include <iomanip>
int main()
{
const size_t N = 3;
int a[N][N] =
{
{ 1, 2, 5 },
{ 2, 8, 9 },
{ 5, 9, 10 }
};
for (size_t i = 0; i < N; i++)
{
for (size_t j = 0; j < N; j++)
{
std::cout << std::setw(2) << a[i][j] << ' ';
}
std::cout << '\n';
}
std::cout << std::endl;
for (size_t i = 0; i < N; i++)
{
size_t min = 0;
for (size_t j = 1; j < N; j++)
{
if (a[i][j] < a[i][min]) min = j;
}
if ( min != N - i - 1 )
{
int tmp = a[i][min];
a[i][min] = a[i][N - i - 1];
a[i][N - i - 1] = tmp;
}
}
for (size_t i = 0; i < N; i++)
{
for (size_t j = 0; j < N; j++)
{
std::cout << std::setw(2) << a[i][j] << ' ';
}
std::cout << '\n';
}
std::cout << std::endl;
}
The program output is
1 2 5
2 8 9
5 9 10
5 2 1
8 2 9
5 9 10