This is driving me crazy. Everything looks good. I am getting this error:
Page not found (404)
Request Method: GET
Request URL: http://localhost:8000/home
Using the URLconf defined in gds.urls, Django tried these URL patterns, in this order:
^admin/
^fixiss/
The current URL, home, didn't match any of these.
Here is my root url:
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^fixiss/', include('fixiss.urls')),
]
My app url:
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.home, name="index"),
]
And the view in my app:
from django.shortcuts import render
from django.http import HttpResponse
# Create your views here.
def home(request):
return HttpResponse("Home page!")
Any help would be greatly appreciated!
Assuming your "app url" module is 'fixiss.urls' where you only have one pattern (the empty string) and you are you are including it under fixiss/, the only match should be:
http://localhost:8000/fixiss/
If you change your one pattern to:
url(r'^home$', views.home, name="index")
that view will be served under
http://localhost:8000/fixiss/home/
The actual name of the view function (home in this case) is rather irrelevant when it comes to url pattern matching. What counts is the specified regex pattern.
This is very well documented:
Django url dispatching in general
Including urls in particular
That is because no url matches home/. Your url should be http://localhost:8000/fixiss/
In the app's (fixiss) url file, the regex is empty meaning, it does not expect a string after fixiss/ in the url for it to match.
Related
On the administration page, I set the URL for the Django flat pages to "/", which is expected to be displayed as the home page at http://127.0.0.1:8000/. Doing so I encountered an error:
Request Method: GET
Request URL: http://127.0.0.1:8000/
Using the URLconf defined in core.urls, Django tried these URL patterns, in this order:
admin/
<path:url>
The empty path didn't match any of these.
But if I go to http://127.0.0.1:8000// with double slash then the home page is displayed correctly. My only urls.py file looks like this:
from django.contrib import admin
from django.urls import include, path
from django.contrib.flatpages import views
urlpatterns = [
path('admin/', admin.site.urls),
]
urlpatterns += [
path('<path:url>', views.flatpage),
]
And I took all the code completely from the official guide. How to display the django flatpage homepage at http://127.0.0.1:8000/?
In addition to the django.urls.path method Django offers the django.urls.re_path method. The path method is designed to perform matches against exact strings, whereas the re_path method is designed to perform matches against patterned strings based on regular expressions. In my case it’s enough to fix it this way:
urlpatterns += [
re_path(r'^(?P<url>.*)$', views.flatpage),
]
As a result, we get the correct processing of requests at http://127.0.0.1:8000/. More details about using path, re_path methods can be found at the link.
I am trying to call a function in my views.py by pasting a url http://127.0.0.1:8000/upload_results/UniEX_HG1_A15 in the web browser,
but the request fails and I can not see why my URL pattern does not work.
The error:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/upload_results/UniEX_HG1_A15
Using the URLconf defined in varview.urls, Django tried these URL patterns, in this order:
^$ [name='show_index']
^admin/
^upload/ [name='varview_submission']
^upload_results/(?P<project_id>[0-9A-Za-z_]+)/ [name='varview_upload_results']
^validate/(?P<project_id>[0-9A-Za-z_]+)/ [name='varview_validate']
^filterallprojects/[0-9A-Za-z_]+ [name='varview_filterallprojects']
^project/(?P<project_id>[0-9A-Za-z_]+)/wgsmetrics/ [name='varview_wgsmetrics']
^project/(?P<project_id>[0-9A-Za-z_]+)/targetgenecoverage/ [name='varview_targetgenecoverage']
^project/(?P<project_id>[0-9A-Za-z_]+)/(?P<display_option>[0-9A-Za-z_]+)/ [name='varview_project']
^media\/(?P<path>.*)$
The current path, upload_results/UniEX_HG1_A15, didn't match any of these.
And here is my urls.py:
from django.conf import settings
from django.conf.urls import url
from django.conf.urls.static import static
from django.contrib import admin
from varview import views
from varview.forms import DataUploaderForm1, DataUploaderForm2, GetProjectIdForm
urlpatterns = [
url(r'^$', views.show_index, name='show_index'),
url(r'^admin/', admin.site.urls),
url(r'^upload/', views.init_submission, name='varview_submission'),
url(r'^upload_results/(?P<project_id>[0-9A-Za-z_]+)/', views.upload_results, name='varview_upload_results'),
]
This already worked some time ago, but in the meantime I did many changes.
Latest change was to include celery (djcelery).
The index page and others still work. I already read many posts related to django-url, but could not figure it out.
Thank you for your help.
Note your URL has a trailing slash,
^upload_results/(?P<project_id>[0-9A-Za-z_]+)/
but you are trying to access a URL without the trailing slash
/upload_results/UniEX_HG1_A15
Normally, Django will redirect to the URL with the trailing slash. Perhaps your MIDDLEWARE setting is incorrect, or you have set APPEND_SLASH to False.
With my (Django v 1.17) project I am using django-subdomains.
I have no problem to call index view and when I open my url https://subdomain.domain.com I will get index.html.
My issue that I wrote a new view called example for the sub-domain but when I open the url https://subdomain.domain.com/exmaple I will get error Page not found (404).
Hete is my code:
settings.py
INSTALLED_APPS = [
'subdomain'
]
SUBDOMAIN_URLCONFS = {
'subdomain': 'subdomain.urls',
}
subdomain/urls.py
from django.conf.urls import url, include
from . import views
from django.contrib.auth import views as auth_views
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^$example', views.example, name='example'),
]
subdomain/views.py
from django.shortcuts import render
from django.template import loader
from django.http import HttpResponse
def index(request):
template = loader.get_template('subdomain/index.html')
return HttpResponse(template.render())
def example(request):
template = loader.get_template('subdomain/example.html')
return HttpResponse(template.render())
Error:
Page not found (404)
Request Method: GET
Request URL: https://subdomain.domain.com/example
Using the URLconf defined in subdomain.urls, Django tried these URL patterns, in this order:
1. ^$ [name='index']
2. ^$example [name='example']
The current path, econ, didn't match any of these.
Please advise how to fix this issue and write view for sub-domain.
This is unrelated to django-subdomains. The dollar should be at the end of the regex.
url(r'^example$', views.example, name='example'),
The dollar matches the end of the string, so if you have it at the beginning then it's not going to match.
I am going throught the Django tutorial here:
https://docs.djangoproject.com/en/1.10/intro/tutorial01/
I follow the instructions exactly. But when I try to go to http://localhost:8000/polls/, I don't see the message “Hello, world. You’re at the polls index.” as expected. Instead, I get the following error:
Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, polls/, didn't match any of these.
Here is my mysite/urls.py file. I am not sure why the first regex pattern in urlpatterns is not recognized.
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^polls/', include('polls.urls')),
url(r'^admin/', admin.site.urls),
]
You might have forgot .html extension in views.py while requesting the page.
I am trying a tutorial on Django called blog. I have the following structure:
FirstBlog|FirstBlog
settings
urls
__init__
etc
blog
templates | index.html
migrations
views.py
manage.py
The view.py has
from django.shortcuts import render
from django.shortcuts import render_to_response
from blog.models import posts
def home(request):
return render('index.html')
The urls.py has
from django.conf.urls import url
from django.conf.urls import include
from django.contrib import admin
urlpatterns = [
url(r'^blog', 'FirstBlog.blog.views.home',name='home'),
]
and I get this error:
Using the URLconf defined in FirstBlog.urls, Django tried these URL patterns, in this order: ^blog [name='home']
The current URL, , didn't match any of these.
I can't seem to get it right..
Any help would be appreciated.
Thank you,
You are requesting for / url and you have not saved any such mapping. Current mapping is for /blog . So it will work for the same url.
i.e goto the browser and request /blog
If you need it to work for / then change the urls appropriately.
within your blog app, create a urls.py file and add the following code which calls the home view.
blog/urls.py
from django.conf.urls import url
from . import views
urlpatterns = [
#url(r'^',views.home, name='home'),
]
then in your root urls file which can be found at FirstBlog/urls.py
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^blog/',include('blog.urls')), #when you visit this url, it will go into the blog application and visit the internal urls in the app
]
PS:
your templates should be in blog/templates/blog/index.html
Read this docs on templates to understand how django locates templates.
This one is to understand how urls work Urls dispatcher
You are doing this in the wrong way! Try doing that using TemplateView from class-based views, which are the current standard from django views.
Check the django documentation: https://docs.djangoproject.com/en/1.9/topics/class-based-views/
Use this at the urls.py:
from django.conf.urls import url
from django.views.generic import TemplateView
urlpatterns = [
url(r'^blog/', TemplateView.as_view(template_name="index.html")),
]
And then, create a folder called templates in the project root ( like this: https://docs.djangoproject.com/en/1.9/intro/tutorial03/#write-views-that-actually-do-something ) named index.html
Simply go to file then select Save all your project instead of save. Or use shortcut Ctrl +k s on windows. Project should be able to sync and display the code on Django interface