Change namespace of child element using xsl - xslt

Question

How do I replace the namespace of child elements in an xml?
For example I have this source file:
<ns:Parent xmlns:ns="http://test.com">
<ns:Name>John</ns:Name>
<ns:Country>Japan</ns:Country>
<ns:Contact>9999999</ns:Contact>
</ns:Parent>
My output should be like this:
<ns:Parent xmlns:ns="http://test.com">
<ns1:Name xmlns:ns1="http://development.com">John</ns1:Name>
<ns:Country>Japan</ns:Country>
<ns:Contact>9999999</ns:Contact>
</ns:Parent>
So basically All the other fields aside from Name were not affected.

Answer 1

First start with the identity template, to handle copying all the nodes you don't want to change
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
Then, just add a template to match ns:Name, where you create a new node in your required namespace instead (where ns1 is defined on the xsl:stylesheet element)
<xsl:template match="ns:Name">
<ns1:Name>
<xsl:apply-templates select="#*|node()"/>
</ns1:Name>
</xsl:template>
Try this XSLT
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns:ns="http://test.com"
xmlns:ns1="http://development.com">
<xsl:output method="xml" indent="yes" />
<xsl:template match="ns:Name">
<ns1:Name>
<xsl:apply-templates select="#*|node()"/>
</ns1:Name>
</xsl:template>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>