Save a foreign key in postgreSQL using python-django - django

I'm trying to a save a foreign key inside an object into my db using a form, but i get the error : 'Syntax isn't valid for integer', I discovered that postgreSQL save the foreign key as an id, how can i save it then?
Here it is my code.
Models.py :
class treballador(models.Model):
nom = models.CharField(max_length=150, null=False, unique=True)
cognom = models.CharField(max_length=150, null=False)
tipusDocID = models.CharField(max_length=3, choices=TIPUSDOC, null=False)
docId = models.CharField(max_length=9, null=False)
tlf_regex = RegexValidator(regex=r'^\d{9,9}$',message="Phone number must be entered in the format: '+999999999'. Up to 9 digits allowed.")
tlf = models.CharField(validators=[tlf_regex], blank=True, max_length=9) # validators should be a list
correu = models.EmailField(max_length=254)
ciutat = models.CharField(max_length=150)
dataDAlta = models.DateTimeField(auto_now_add=True)
def __unicode__(self):
return unicode(self.nom) or unicode(self.id)
class despesa(models.Model):
nomTreballador = models.ForeignKey(treballador, to_field='nom')
tipusDeGast = models.CharField(max_length=3, choices=GASTOS)
quantia = models.DecimalField(max_digits=5, decimal_places=2)
data = models.DateTimeField()
forms.py:
class desModelForm(forms.ModelForm):
data = forms.DateField(widget=DateInput(format='%d/%m/%Y'), label="Data de la despesa", input_formats=['%d/%m/%Y'])
class Meta:
model= despesa
fields= ["nomTreballador","tipusDeGast","quantia","data"]
def clean_despesa(self):
despeses = self.cleaned_data.get("tipusDeGast")
return despeses
def clean_date(self):
date = self.cleaned_data.get("data")
return date
def clean_quantia(self):
quantia = self.cleaned_data.get("quantia")
return quantia
def clean_nom(self):
nomTreballador = self.cleaned_data.get("nomTreballador")
return nomTreballador
def __init__(self, *args, **kwargs):
super(desModelForm, self).__init__(*args, **kwargs)
self.fields["nomTreballador"].queryset=treballador.objects.all().distinct()
views.py:
def home(request):
form = desModelForm(request.POST or None)
context = {
"gast_form": form
}
if form.is_valid():
desp = form.save(commit=False)
desp.save()
return render(request, "imputacioDespeses.html", context)

Your foreign key field is the problem.
Remove to_field and Django will automatically map it to ID
nomTreballador = models.ForeignKey(treballador)

Remove to_field='nom' from the nomTreballador ForeignKey field and it will insert the Treballador's primary key (an integer) instead of nom (which is a string).

Related

how to return several FileField from Queryset in Django?

I have a models with FileField for videos.
When i upload only one video i can return it with this code in the view.py:
def cours(request, id, slug):
c = Cours.objects.get(id=id, slug=slug)
p = Plan_simple.objects.get(cours=c)
return render(request, 'upload/cours.html', locals())
But when i upload two or more videos whith formset, and i change get fuction by filter it doesn't work:
def cours(request, id, slug):
c = Cours.objects.get(id=id, slug=slug)
p = Plan_simple.objects.filter(cours=c)
return render(request, 'upload/cours.html', locals())
the models.py
class Cours(models.Model):
titre = models.CharField(max_length=100)
slug = models.SlugField(max_length=100)
auteur = models.CharField(max_length=42)
comment = models.TextField(null=True)
link = models.CharField(max_length=100)
date = models.DateTimeField(default=timezone.now, verbose_name="Date de parution")
categorie = models.ForeignKey('Categorie', on_delete=models.CASCADE)
def save(self, *args, **kwargs):
self.slug = slugify(self.titre)
super(Cours, self).save(*args, **kwargs)
class Meta:
verbose_name = "cours"
db_table = "cours"
ordering = ['date']
class Plan_simple(models.Model):
partie = models.CharField(blank=True, max_length=100)
date = models.DateTimeField(default=timezone.now, verbose_name="Date de parution")
vid = models.FileField(upload_to='file/', blank=True, null = True)
cours = models.ForeignKey(Cours, related_name = "plan_simple", on_delete=models.CASCADE)
def __str__(self):
return self.partie
class Meta:
db_table = "plan_simple"
Can you help me?
Thanks
The issue is with this line. It does not request anything from the database. It only specifies a filter.
p = Plan_simple.objects.filter(cours=c)
You should change it to this...
p = Plan_simple.objects.filter(cours=c).all()

How can I obtain just one JSON object with the three models information combined?

How can I pass the foreign key values from my model to my serialised json object?
Now I have this three models,
class Fleet(models.Model):
fleet_id = models.IntegerField('Id flota', primary_key=True, unique=True)
fleet_name = models.CharField('Nombre flota', max_length=20, unique=True)
def __str__(self):
return self.fleet_name + ' ' + str(self.fleet_id)
class Device(models.Model):
dev_eui = models.CharField(max_length=16, primary_key=True, unique=True)
producer = models.CharField(max_length=20)
model = models.CharField(max_length=20)
dev_name = models.CharField(max_length=20, unique=True)
fleet_id = models.ForeignKey(Fleet, on_delete=models.CASCADE)
def __str__(self):
return self.dev_eui
class DevData(models.Model):
data_uuid = models.UUIDField(primary_key=True, default=uuid.uuid1, editable=False)
frequency = models.IntegerField()
data_1 = models.FloatField()
data_2 = models.FloatField(null=True, blank=True)
dev_eui = models.ForeignKey(Device, on_delete=models.CASCADE) #hay que saber porque añade _id
def __str__(self):
return self.dev_eui
And what I'm doing is call my view function in my JS code to obtain some data like this.
def getData(request):
ctx = {}
if request.method == 'POST':
select = int(request.POST['Select'])
data = DevData.objects.order_by('dev_eui','-data_timestamp').distinct('dev_eui')
nodes = Device.objects.all()
fleets = Fleet.objects.all()
data = loads(serializers.serialize('json', data))
nodes = loads(serializers.serialize('json', nodes))
fleets = loads(serializers.serialize('json', fleets))
ctx = {'Data':data, 'Nodes':nodes, 'Fleets':fleets}
return JsonResponse(ctx)
And inside my js file I filter it with some if else conditionals.
This works well, but I'm sure I can do it directly in my view but I don't know how. How can I obtain just one JSON object with the three models information combined?
Thank you very much!!
You can write a custom serializer like this:
from django.core.serializers.json import Serializer
class CustomSerializer(Serializer):
def end_object(self, obj):
for field in self.selected_fields:
if field == 'pk':
continue
elif field in self._current.keys():
continue
else:
try:
if '__' in field:
fields = field.split('__')
value = obj
for f in fields:
value = getattr(value, f)
if value != obj and isinstance(value, JSON_ALLOWED_OBJECTS) or value == None:
self._current[field] = value
except AttributeError:
pass
super(CustomSerializer, self).end_object(obj)
Then use it like this
serializers = CustomSerializer()
queryset = DevData.objects.all()
data = serializers.serialize(queryset, fields=('data_uuid', 'dev_eui__dev_eui', 'dev_eui__fleet_id__fleet_name'))
I have wrote an article regarding serializing nested data here. You can check that out as well.

How to get id from foreign key model in django

How Do I get id of to_user from the below model:
class Friend(models.Model):
status = models.CharField(max_length=10)
from_user = models.ForeignKey(AUTH_USER_MODEL, on_delete=models.CASCADE, related_name = 'from_user')
to_user = models.ForeignKey(AUTH_USER_MODEL, on_delete=models.CASCADE, related_name="to_user")
date_modified = models.DateTimeField(auto_now=True, blank=True)
date_created = models.DateTimeField(auto_now_add=True, null=True)
def create(self,request, **kwargs, ):
friend = self.create(from_user_id=request.user.id, status="Pending")
return friend
class Meta:
unique_together = (('from_user', 'to_user'),)
def __str__(self):
return self.to_user.email
my view :
def accept_friend_request(request, uidb64, status):
"""Accept button will lead to entry in database as accepted and reject button will lead to entry in database as rejected based on status flag"""
Friend.status = "pending"
try:
uid = urlsafe_base64_decode(uidb64)
friend_user = User.objects.filter(id=Friend.to_user.id)
f = Friend.objects.filter(friend_id = friend_user)
if f:
f.status=status
f.save()
f.status = "accepted"
return render(request, 'users/friend_list.html', {"uidb64": uid, "status": status})
else:
f.status = "rejected"
f.save()
return render(request, 'users/friend_list.html', {'uidb64':uid, 'status':status})
except AttributeError:
return render(request, 'blog/base.html')
I cannot retrieve the friend_user = User.objects.filter(id=Friend.to_user.id)
Thanking you in advance,
Friend is a model class, and you need an instance of such class in order to relate it to another model instance as a foreign relationship.
For example:
friend_instance = Friend.objects.get(name='Madeleaine')
...
friend_user = friend_instance.to_user.id

Forms in Django. How to initialize model field from form?

In models.py:
class Client(AbstractBaseUser):
username = models.CharField(max_length=32, unique=True)
email = models.EmailField('email address', unique=True, db_index=True)
avatar = models.ImageField('avatar', upload_to='avatars')
id = id(object)
class Order(models.Model):
class Meta():
db_table = 'order'
short_desc = models.CharField(max_length=30)
subject = models.ForeignKey(Subject, blank=True)
user_id = models.ForeignKey('Client', to_field='id', related_name='client_id', default='0', blank=True)
performer_id = models.ForeignKey('Client', to_field='id', related_name='performer_id', default='0', blank=True)
worktype = models.ForeignKey(Type, blank=True)
level = models.IntegerField(default=0, blank=True)
readiness = models.BooleanField(default=False, blank=True)
description = models.TextField(max_length=2000, blank=True)
file = models.FileField(upload_to='orderfiles', blank=True)
#maxdate = models.DateField(blank=True)
addate = models.DateField(auto_now=True, blank=True)
price = models.IntegerField(max_length=10, blank=True)
responses = models.IntegerField(blank=True)
In forms.py:
class AddOrderForm(forms.ModelForm):
short_desc = forms.CharField(widget=forms.TextInput,label="Краткое описание(послужит именем)")
subject = forms.ModelChoiceField(queryset=Subject.objects.all(), label="Предмет")
worktype = forms.ModelChoiceField(queryset=Type.objects.all(), label="Тип")
level = forms.IntegerField(widget=forms.TextInput,label="Уровень сложности (от 1 до 5)")
description = forms.CharField(widget=forms.TextInput,label="Полное описание")
#maxdate = forms.DateField(widget=forms.TextInput,label="maxdate")
price = forms.IntegerField(widget=forms.TextInput,label="Ваша цена")
responses = forms.IntegerField(widget=forms.TextInput,label="Кол-во ответов на заказ")
class Meta:
model = Order
fields = ['short_desc', 'level', 'description', 'price', 'responses', 'subject', 'worktype']
In views.py:
def addorder(request, user_id):
"""
Adding Order view
"""
if request.POST:
form = AddOrderForm(request.POST)
if form.is_valid():
form.save()
return redirect('/')
else:
return redirect('/')
auth1 = auth.get_user(request).username
return render_to_response('customer.html', { 'form': form,'username' : auth1}, context_instance=RequestContext(request))
I need the field user_id in class Order to be initialized immediately after adding order(). Where should I do it and in which way? I need something like this logic: Client adds an Order through AddOrderForm and then user_id field of just added object of class Order has to be initialized with an object of class Client, whose id equals user_id in parameters of addorder() function.
You can do that using commit=False while saving the form. This is typical way of saving the object using model form which has fewer fields.
def addorder(request, user_id):
"""
Adding Order view
"""
if request.POST:
form = AddOrderForm(request.POST)
if form.is_valid():
order = form.save(commit=false)
order.client_id = Client.objects.get(id=user_id)
order.save()
return redirect('/')
else:
return redirect('/')
auth1 = auth.get_user(request).username
return render_to_response('customer.html',
{ 'form': form,'username' : auth1},
context_instance=RequestContext(request))
Disclaimer: Handle errors e.g. Client.objects.get() may fail. Use appropriate fields to search.

Django ValueError when trying to save ManyToMany Values from a Form

I get the error "" needs to have a value for field "dataset" before this many-to-many relationship can be used." when trying to assign values to a ManyToMany field in my views. I've looked at many related questions here on SO that say I must save my Dataset object first. I think I am doing that...what is going wrong?? My database already contains four Subject items.
models.py
class Subject(TimeStampedModel):
subject_type = models.CharField(max_length=128, blank=False)
def __unicode__(self):
return self.subject_type
class Dataset(TimeStampedModel):
dataset_id = models.CharField(max_length=256)
dataset_doi = models.CharField(max_length=15)
dataset_name = models.CharField(max_length=256, blank=False)
dataset_description = models.TextField(blank=False)
lab = models.CharField(max_length=256, blank=False)
biological_sample = models.CharField(max_length=256, blank=False)
subject_type = models.ManyToManyField('Subject', related_name='datasets', blank=True)
date_collected = models.DateField(blank=True)
collection_facility = models.ManyToManyField('CollectionFacility', related_name='datasets', blank=True)
processing_notes = models.TextField(blank=True)
release_date = models.DateField()
release_asap = models.BooleanField()
pdb_code = models.CharField(max_length=256, blank=True)
publication_link = models.URLField(blank=True)
def create_name(self):
self.dataset_name = "%s %s" % (self.biological_sample, self.lab)
def save(self, *args, **kwargs):
self.dataset_id = self.id
def __unicode__(self):
return "%s : %s" % (self.dataset_name, self.dataset_id)
forms.py RegistrationForm:
class RegistrationForm(forms.Form):
subject_type = forms.ModelMultipleChoiceField(
label="Subject",
queryset = Subject.objects.all(),
widget=forms.CheckboxSelectMultiple(),
required = True,
)
views.py
def create_registration(form):
dataset = Dataset()
dataset.DOI = "preUpload"
dataset.lab = form.cleaned_data['lab']
dataset.biological_sample = form.cleaned_data['sample']
dataset.resource_type = form.cleaned_data['dataset_type']
dataset.dataset_description = form.cleaned_data['dataset_description']
dataset.date_collected = form.cleaned_data['date_collected']
dataset.release_date = form.cleaned_data['release_date']
dataset.release_asap = form.cleaned_data['release_asap']
if form.cleaned_data['pdb_code']:
dataset.pdb_code = form.cleaned_data['pdb_code']
if form.cleaned_data['publication_link']:
dataset.publication_link = form.cleaned_data['publication_link']
dataset.create_name()
dataset.save() # I don't think this save is working?
subjects = form.cleaned_data['subject_type']
dataset.subject_type = [x for x in subjects]
for facility in form.cleaned_data['facility']
dataset.collection_facility.add(facility)
dataset.save()
return dataset
def registration_submit(request):
registration_form = RegistrationForm(request.POST)
if registration_form.is_valid():
registration = create_registration(registration_form)
.......
You forgot to call the original save() in the overriden Dataset.save() method.
def save(self, *args, **kwargs):
self.dataset_id = self.id
super(Dataset, self).save(*args, **kwargs)