My dataset consists a variable named as "REPORTING_ENTITY" in the form of string. Now, from that variable i want create a new dataset which consist a observations with keywords as ('Bank','Loan','Cooperative','SBI','Insurance') from "REPORTING_ENTITY" also want that strings get deleted from original dataset. I did something like:
data class.sample;
set work.sample;
where REPORTING_ENTITY contains ('Bank','Loan','Cooperative','SBI','Insurance');
run;
This will create a new dataset with mentioned keywords but it will not get deleted from orignal dataset..
One way to do this is to overwrite the input dataset while simultaneously creating a new output dataset:
data class.sample
work.sample;
set work.sample;
if REPORTING_ENTITY in ('Bank','Loan','Cooperative','SBI','Insurance')
then output class.sample;
else output work.sample;
run;
Related
I have a dataset containing information by an account number. I'm trying to add a new variable, called product_type, populated with the same value for every record. It is within a SAS macro.
data CC_database;
set cc_base_v2 (keep=accnum date product_type);
product_type="CC";
where date>=%sysevalf("&start_date."d) and file_date<=%sysevalf("&end_date."d);
run;
However, I keep getting the error "The variable product_type has in the DROP, KEEP, or RENAME list has never been referenced" and the output dataset only shows a blank column called product_type. What is happening here?
You are using the KEEP= dataset option on the input dataset. So the error is saying PRODUCT_TYPE does not exist in the dataset CC_BASE_V2.
If you want to control what variables are written by the data step just use a KEEP statement.
keep accnum date product_type;
In your case you could use the KEEP= dataset option but only list the variables taht are coming from CC_BASE_V2.
data CC_database;
set cc_base_v2(keep=accnum date file_date);
where date>= "&start_date."d and file_date<="&end_date."d;
product_type="CC";
drop file_date;
run;
I am very new to SAS, and for whatever reason am finding a lot of difficulty deciphering what this code block (below) does. I've googled and search stackoverflow to no avail. I'd appreciate any input, thanks!
set dataset;
id=cat("L",_n_);
run;
Probably there must be a data statement as well.
data newdataset;
set dataset;
id = cat("L", _n_);
run;
This above code creates a new dataset named newdataset from the existing dataset named dataset.
Also creating a new column called id, and id is creating by concatenating a constant character value "L" with the automatic variable _n_ using the CAT function. The automatic variable _n_ represents the number of times the DATA step has iterated.
I have two datasets in SAS. The first looks like this (let's say it is called data 1 (I'm only concerned with two columns of it)
...and the second dataset (let's say it is called data 2) looks like this:
...and I am trying to extract the second column of the first dataset and insert it into the second dataset, to achieve something that looks like this:
Basic Problem Description:
I am trying to extract two columns from a dataset in SAS and add them as rows to a second dataset. The variable names in the first dataset are in a column of their own (entitled 'variable name') and in the second dataset each variable is a column header (a variable in itself) with corresponding data. The images I provided are overly simplistic, as the actual data itself is very long.
Basically, I am trying to find functions in SAS which allow me to do this.
What I have tried
-I have tried to extract the first two columns as a table using proc sql, converted them to a data frame using a data step, sorted them, then used proc transpose to try to convert them from long to wide, then tried to use some sort of append function to tack them on to the second dataset, but append did not work.
-I have tried to merge the two sets, but the merge does not seem to work after using proc transpose.
-I have also tried transposing the second dataset and then merging them, which worked (for some reason) but then I was not able to transpose the data back (so that I can analyze it, which is my purpose in doing all of this).
What functions would I use to go about this process?
Apologies for not providing replicable data, I am more searching for recommendations for functions rather than a detailed hard solution.
To force PROC TRANSPOSE to use a variable as the source for the new variable names use the ID statement. So if you have this first dataset:
data tall;
input fruit $ count ##;
cards;
APPLE 1 PEACH 2 PEAR 2
;
You can use this code to convert it.
proc transpose data=tall out=wide;
id fruit;
var count;
run;
Then if you have another dataset that already has the variables APPLE, PEACH, PEAR etc then just set the two together.
data want;
set wide have ;
run;
I am working with multiple waves of survey data. I have finished defining formats and labels for the first wave of data.
The second wave of data will be different, but the codes, labels, formats, and variable names will all be the same. I do not want to define all these attributes again...it seems like there should be a way to export the PROC CONTENTS information for one dataset and import it into another dataset. Is there a way to do this?
The closest thing I've found is PROC CPORT but I am totally confused by it and cannot get it to run.
(Just to be clear I'll ask the question another way as well...)
When you run PROC CONTENTS, SAS tells you what format, labels, etc. it is using for each variable in the dataset.
I have a second dataset with the exact same variable names. I would like to use the variable attributes from the first dataset on the variables in the second dataset. Is there any way to do this?
Thanks!
So you have a MODEL dataset and a HAVE dataset, both with data in them. You want to create WANT dataset which has data from HAVE, with attributes of MODEL (formats, labels, and variable lengths). You can do this like:
data WANT ;
if 0 then set MODEL ;
set HAVE ;
run ;
This works because when the DATA step compiles, SAS builds the Program Data Vector (PDV) which defines variable attributes. Even though the SET MODEL never executes (because 0 is not true), all of the variables in MODEL are created in the PDV when the step compiles.
Importantly, note that if there are corresponding variables with different lengths, the length from MODEL will determine the length of the variable in WANT. So if HAVE has a variable that is longer than the same-named variable in MODEL, it may be truncated. Options VARLENCHK determines whether or not SAS throws a warning/error if this happens.
That assumes there are no formats/labels on the HAVE dataset. If there is a variable in HAVE that has a format/label, and the corresponding variable in MODEL does not have a format/label, the format/label from HAVE will be applied to WANT.
Sample code below.
data model;
set sashelp.class;
length FavoriteColor $3;
FavoriteColor="Red";
dob=today();
label
dob='BirthDate'
;
format
dob mmddyy10.
;
run;
data have;
set sashelp.class;
length FavoriteColor $10;
dob=today()-1;
FavoriteColor="Orange";
label
Name="HaveLabel"
dob="HaveLabel"
;
format
Name $1.
dob comma.
;
run;
options varlenchk=warn;
data want;
if 0 then set model;
set have;
run;
I'd create an empty dataset based on the existing one, and then use proc append to append the contents to it.
Create some sample data for the second round of data:
data new_data;
age = 10;
run;
Create an empty dataset based on the original data:
proc sql noprint;
create table want like sashelp.class;
quit;
Append the data into the empty dataset, retaining the details from the original:
proc append base=want data=new_data force nowarn;
run;
Note that I've used the force and nowarn options on proc append. This will ensure the data is appended even if differences are found between the two datasets being used. This is expected if you have, for example, format differences. It will also hide things like if columns exist in the new table that aren't in the old table etc. So be careful that this is doing what you want it to. If the behaviour is undesirable, consider using a datastep to append instead (and list the want dataset first).
Welcome to the stack.
If you want to copy the properties of the table without the data within it, you could use PROC SQL or data step with zero rows read in.
This examples copies all information about the SASHELP.CLASS dataset into a brand new dataset. All formats, attributes, labels, the whole thing is copies over. If you want to only copy some of the columns, specify them in select clause instead of asterix.
PROC SQL outobs=0;
CREATE TABLE WANT as SELECT * FROM SASHELP.CLASS;
QUIT;
Regards,
Vasilij
Im looking do a probt for a column of values in sas not just one and to give two tailed p values.
I have the following code Id like to amend
data all_ssr;
x=.551447;
df=25;
p=(1-probt(abs(x),df))*2;
put p=;
run;
however I would like x to be a column of values within another file. I have tried work.ttest which is just a file of ttest values.
Many thanks
You need to use a set statement to access data from another SAS dataset.
data all_ssr;
set work.ttest; /*Dataset containing column of values*/
df=25;
p=(1-probt(abs(x),df))*2;
run;
Removing the put statement avoids clogging up the log.