I am trying to write a script (python 2.7) that will use a regex to identify specific files in a folder and move them to another folder. When I run the script, however, the source folder is moved to the target folder instead of just the files within it.
import os, shutil, re
src = "C:\\Users\\****\\Desktop\\test1\\"
#src = os.path.join('C:', os.sep, 'Users','****','Desktop','test1\\')
dst = "C:\\Users\\****\\Desktop\\test2\\"
#dst = os.path.join('C:', os.sep, 'Users','****','Desktop','test2')
files = os.listdir(src)
#regexCtask = "CTASK"
print files
#regex =re.compile(r'(?<=CTASK:)')
files.sort()
#print src, dst
regex = re.compile('CTASK*')
for f in files:
if regex.match(f):
filescr= os.path.join(src, files)
shutil.move(filesrc,dst)
#shutil.move(src,dst)
So basically there are files in "test1" folder that I want to move to "test2", but not all the files, just the ones that contain "CTASK" at the beginning.
The **** in the path is to protect my work username.
Sorry if it is messy, I am still trying a few things out.
You need to assign path to exact file (f) to filescr variable on each loop iteration, but not path to files (files - is a list!)
Try below code
import os
from os import path
import shutil
src = "C:\\Users\\****\\Desktop\\test1\\"
dst = "C:\\Users\\****\\Desktop\\test2\\"
files = [i for i in os.listdir(src) if i.startswith("CTASK") and path.isfile(path.join(src, i))]
for f in files:
shutil.copy(path.join(src, f), dst)
I wanted to move following folders : 1.1,1.2,1.45,1.7 to folder with name '1'
I Have posted solution below:
import shutil
import os
src_path = '/home/user/Documents/folder1'
dest_path='/home/user/Documents/folder2/'
source = os.listdir(src_path)
for folder in source :
#folder = '1.1 -anything'
newf = folder.split('.')[0]
#newf is name of new folder where you want to move
#change Folder name as per yourrequirement
destination = dest_path+newf
if not os.path.exists(destination):
os.makedirs(destination)
shutil.move(src_path+'/'+folder,destination) #change move to copy if you want to copy insted of moving
print 'done moving'
Related
The code below searches within a directory for any PDFs and for each one it finds it moves into the corresponding folder which has '_folder' appended.
Could it be expressed in simpler terms? It's practically unreadable. Also if it can't find the folder, it destroys the PDF!
import os
import shutil
for root, dirs, files in os.walk(folder_path_variable):
for file1 in files:
if file1.endswith('.pdf') and not file1.startswith('.'):
filenamepath = os.path.join(root, file1)
name_of_file = file1.split('-')[0]
folderDest = filenamepath.split('/')[:9]
folderDest = '/'.join(folderDest)
folderDest = folderDest + '/' + name_of_file + '_folder'
shutil.move(filenamepath2, folderDest)
Really I want to traverse the same directory after constructing the variable name_of_file and if that variable is in a folder name, it performs the move. However I came across issues trying to nest another for loop...
I would try something like this:
for root, dirs, files in os.walk(folder_path_variable):
for filename in files:
if filename.endswith('.pdf') and not filename.startswith('.'):
filepath = os.path.join(root, filename)
filename_prefix = filename.split('-')[0]
dest_dir = os.path.join(root, filename_prefix + '_folder')
if not os.path.isdir(dest_dir):
os.mkdir(dest_dir)
os.rename(filepath, os.path.join(dest_dir, filename))
The answer by John Zwinck is correct, except it contains a bug where if the destination folder already exists, a folder within that folder is created and the pdf is moved to that location. I have fixed this by adding a 'break' statement within the inner for loop (for filename in files).
The code below now executes correctly. Looks for folder named as the pdf's first few characters (taking the prefix split at '-') with '_folder' at the tail, if it exists the pdf is moved into it. If it doesn't, one is created with the prefix name and '_folder' and pdf is moved into it.
for root, dirs, files in os.walk(folder_path_variable):
for filename in files:
if filename.endswith('.pdf') and not filename.startswith('.'):
filepath = os.path.join(root, filename)
filename_prefix = filename.split('-')[0]
dest_dir = os.path.join(root, filename_prefix + '_folder')
if not os.path.isdir(dest_dir):
os.mkdir(dest_dir)
os.rename(filepath, os.path.join(dest_dir, filename))
break
I quite new in Python programming and i try to rename 100 files with ".jpg" extention, located in specific folder using pyhthon.
I need that the files will be renamed by running order start from number 1. This is the code i start writing:
import os,glob,fnmatch
os.chdir(r"G:\desktop\Project\test")
for files in glob.glob("*.jpg"):
print files
When i run it, i get:
>>>
er3.jpg
IMG-20160209-ssdeWA0000.jpg
IMG-20160209-WA0000.jpg
sd4.jpg
tyu2.jpg
uj7.jpg
we3.jpg
yh7.jpg
>>>
so the code, till now is OK.
For example my folder is:
and i need that all the files name will be:
1,2,3,4 - with running order names. Is it possible with python 2.7?
If you simply want to rename all files as 1.jpg, 2.jpg etc. you can do this:
import os
import glob
os.chdir(r"G:\desktop\Project\test")
for index, oldfile in enumerate(glob.glob("*.jpg"), start=1):
newfile = '{}.jpg'.format(index)
os.rename (oldfile,newfile)
enumerate() is used to get get the index of each file from the list returned by glob(), so that it can be used to create the new filename. Note that it allows you to specify the start index, so I've started from 1, rather than Python Standard, zero
If you want this list of files to be sortable properly, you'll want the filename to be padded with zero's as well (001.jpg, etc.). In which case simply replace newfile = '{}.jpg'.format(index)' with newfile = '{:03}.jpg'.format(index).
See the the docs for more on str.format()
To rename all the JPG files from a particular folder First, get the list of all the files contain in the folder.
os.listdir will give you list all the files in images path.
use enumerate to get the index numbers to get the new name for
images.
import os
images_path = r"D:\shots_images"
image_list = os.listdir(images_path)
for i, image in enumerate(image_list):
ext = os.path.splitext(image)[1]
if ext == '.jpg':
src = images_path + '/' + image
dst = images_path + '/' + str(i) + '.jpg'
os.rename(src, dst)
import os
from os import path
os.chdir("//Users//User1//Desktop//newd//pics")
for file in os.listdir():
name,ext=path.splitext(file)
if ext == '.jpeg':
dst= '{}.jpg'.format(name)
os.rename(file,dst)
import os
myDir = "C:\\temp\\a"
for root, dirs, files in os.walk(myDir):
for file in files:
# fname = os.path.join(root, file) # this works fine, yeah!
fname = os.path.join(myDir, file)
print ("%r" % (fname))
src = os.path.isfile(fname)
if src == False:
print ("%r :Fail" % (fname))
f = open(fname,"r")
f.close()
I expected the two versions of fname to be the same, but I've found out the hard way that the above code doesn't work. I just want to know why, that's all.
The problem is that os.walk(myDir) walks all the subdirectories, recursively! When walk descends into a subdirectory, root will be that directory, while myDir is still the root directory the search started in.
Let's say you have a file C:\temp\a\b\c\foo.txt. When os.walk descends into c, myDir is still C:\temp\a and root is C:\temp\a\b\c. Then os.path.join(root, file) will yield C:\temp\a\b\c\foo.txt, while os.path.join(myDir, file) gives C:\temp\a\foo.txt.
You might want to rename your myDir variable to root, and root to current, respectively, so it's less confusing.
I am trying to set up a program to put my minecraft server world into a zip and place it into another directory on another drive (/media/500gb/MinecraftWorldBackups)
But I keep getting this error
Although the folder doesn't contain a folder or file called 'h'
What do I need to do to fix this I believe it is due to file and folder?
#!/usr/bin/env python
import time, zipfile
while True:
FileName = 'MinecraftBackup_' + str(int(time.time()))
Path = '/home/bertie/Desktop/FeedTheBeastServer/world/'
print(FileName)
Zip = zipfile.ZipFile('/media/500gb/MinecraftWorldBackups/'+FileName+'.zip','w')
for each in Path:
print(each)
try: Zip.write(Path + each)
except IOError: None
Zip.Close()
print('Done')
time.sleep(60)
I've got a python script that deletes an entire directory and its subfolders, and I'd like to print out the number of files and folders removed. Currently, I have found some code from a different question posed 2010, but the answer I receive back is 16... If I right-click on the the folder it states that theres 152 files, 72 folders...
The code I currently have for checking the directory;
import os, getpass
user = getpass.getuser()
copyof = 'Copy of ' + user
directory = "C:/Documents and Settings/" + user
print len([item for item in os.listdir(directory)])
How can I extend this to show the same number of files and folders that there actually are?
To perform recursive search you may use os.walk.
os.walk(top, topdown=True, onerror=None, followlinks=False)
Generate the file names in a directory tree by walking the tree either top-down or bottom-up. For each directory in the tree rooted at
directory top (including top itself), it yields a 3-tuple (dirpath,
dirnames, filenames).
Sample usage:
import os
dir_count = 0
file_count = 0
for _, dirs, files in os.walk(dir_to_list_recursively):
dir_count += len(dirs)
file_count += len(files)
I was able to solve this issue by using the following code by octoback (copied directly);
import os
cpt = sum([len(files) for r, d, files in os.walk("G:\CS\PYTHONPROJECTS")])