I am building a non profit association website and am using the Sites feature to build custom templates for their chapter sites. What I am trying to do is re-use the templates by targeting the Sites name or id or... For instance, if you look at the screenshot below, I have two sites so far I am testing and I have a model called StandardPage(Page) and a matching template standard_page.html. The main site will look slightly different than the chapter sites, but I would like to re-use the standard_page.html template for both with an if path is this, display this, if not this...
I know this isn't correct, but to illustrate what I am trying to do:
standard_page.html
{% if request.path != '/' %}
{% include 'includes/chapter/_chapter-standard-page-content.html' %}
{% else %}
{% include 'includes/ao/_ao-standard-page-content.html' %}
{% endif %}
They have over 50 chapters around the world, so you can see how important it would be to be able to re-use templates so I am not having to created each template for each model for each chapter .
Thank you.
Related
The odds are that this question will be banned, because this forum seems to me a site for "why it doesn't work"-type of questions, rather than "is it a good idea to do what I do" ones. And yet, I am very much concerned about preserving DRY-ness in my code.
I have a Django template which looks like this:
<ol id = 'task_list'>
{% for item in qs %}
{% include 'list_item.html' with item=item %}
{% endfor %}
</ol>
list_item.html:
<li>
{{item}}
</li>
The advantage (at least, for me) of this code: it positively affects DRYness when I have a ajax code which posts a request for creating new items of the list and renders them on the client side subsequently:
JS:
$.post('my_view_url', function(response)
$('#container').append(response);
Django view:
def my_view(response)
#...
return render_to_response('list_item.html',....)
This way, list_item.html helps me use the same HTML code for both initial rendering of existing elements and client-side rendering of newly created items.
The disadvantage is that {% include %} is known to be rather slow.
The question: Is this code pattern not a performance killer in case of paginated rendering of large arrays of data ?
Additional note:
AFAIK, {% block %} is faster than {% include %}. But I've got no idea how to rewrite the code pattern using block.
I have an issue. I've written a custom template tag with a function signature like this-
def has_paid_for_article(article, request):
Now, in my template tag I have a conditional statement to determine whether a user can download an article or not (this is determined by if the article is older than two years or the logged in user has paid for the article). Here's the snippet-
{% if article|is_older_than_two_years %}
<span class="amp">& </span>{% get_article_download_link article %}
{% else %}
download
{% endif %}
The aforementioned snippet works fine, however I need to call the has_paid_for_article() function inside of a conditional statement. I've tried the following ways to make this happen-
{% if article|is_older_than_two_years or article|request|has_paid_for_article %}
,
{% if article|is_older_than_two_years or [article, request]|has_paid_for_article %}
This one works outside of the conditional statement-
{% if article|is_older_than_two_years or has_paid_for_article article request %}
What would be the correct syntax here? Also, I've read other posts on the topic, I CANNOT put this logic in the view. I won't go into detail, but with the way it works, that is not an option. Thank you!
Try
{% if article|is_older_than_two_years or article|has_paid_for_article:request %}
See Writing custom template filters
I think I'm missing a basic concept here. In the stereotypical Django project, you'd have two apps responding to different urls:
http://localhost/myproj/app1/33
http://localhost/myproj/app2/newcomment.html
But what mechanisms exist to handle cases where the two apps are complementary - say one provides content, and the other provides presentation? Or maybe one is content and the other is a kind of static, side-wide content that should appear on every page.
In particular, I don't understand how both apps can use template inheritance to extend the same template. Imagine there's a base app "baseapp" with a template "base.html":
...
<div blah blah>
{% block content %}
{% endblock %}
...
App1 extends it:
{% extends "baseapp/templates/base.html" %}
{% block content %}
... here's the actual content...
{% endblock %}
App2 adds a little banner or something:
{% extends "baseapp/templates/base.html" %}
{% block content %}
<div class="banner">Please support our site!</div>
{{ block.super }}
{% endblock %}
So what are the ways that both templates can get displayed? I can think of:
app1 could extend app2's templates. But this seems wrong: app1 is the content provider, and shouldn't be dependent on something as trivial as app2.
app2 could extend app1's templates. But this seems wrong: now the URL scheme would have to funnel every URL through app2 (if I understand correctly)
middleware?
As I said, I'm probably missing something very basic. Or I'm making some very faulty assumptions that I don't know about. (This question is my third attempt, after Embed an optional Django application in another page, if that app is present and How to capture and display information external to my webapp, but relevant to users of it? - I'm having trouble framing the issue.)
App doesn't respond to an URL, a view does. View is a function that can use models, forms and other object from any app. There isn't any problem here.
If you want to add something to template, inheritance isn't the only way. You'd better use custom context processor or custom template tag.
I think what I was actually missing here:
Apps can override templates just by including a template of the right name in the right subdirectory. The Django docs don't make this very clear, that I can see: they refer to this functionality in the context of Admin templates
When overriding a template as above, you can't extend it, but:
This snippet lets you both override a template and extend it: http://djangosnippets.org/snippets/1376/
Here's a closely related question: Django: Overriding AND extending an app template
I have created my text based game and my game pages have structure like this:
{% extends 'base.html' %}
{% block content %}
// content
{% include 'links.html' %}
{% endblock %}
Now I'm thinking about notifying players about a new message at the top of every page, so I have to update only base.html to show the information, however, I have to add data about new messages to every template before rendering. Maybe is there a quicker way to do that?
You probably want to look into Context Processors -> docs. That's how you automatically add stuff to your templates. Here's a detailed example -- it's old, but I think it still works.
Or you can just use the messages framework, which has the appropriate Context Processor implemented and should do what you need here.
I have template that displays object elements with hyperlinks to other parts of my site. I have another function that displays past versions of the same object. In this display, I don't want the hyperlinks.
I'm under the assumption that I can't dynamically switch off the hyperlinks, so I've included both versions in the same template. I use an if statement to either display the hyperlinked version or the plain text version. I prefer to keep them in the same template because if I need to change the format of one, it will be easy to apply it to the other right there.
The template extends framework.html. Framework has a breadcrumb system and it extends base.html. Base has a simple top menu system.
So here's my dilemma. When viewing the standard hyperlink data, I want to see the top menu and the breadcrumbs. But when viewing the past version plain text data, I only want the data, no menu, no breadcrumbs. I'm unsure if this is possible given my current design. I tried having framework inherit the primary template so that I could choose to call either framework (and display the breadcrumbs), or the template itself, thus skipping the breadcrumbs, but I want framework.html available for other templates as well. If framework.html extends a specific template, I lose the ability to display it in other templates.
I tried writing an if statement that would display a the top_menu block and the nav_menu block from base.html and framework.html respectively. This would overwrite their blocks and allow me to turn off those elements conditional on the if. Unfortunately, it doesn't appear to be conditional; if the block elements are in the template at all, surrounded by an if or not, I lose the menus.
I thought about using {% include %} to pick up the breadcrumbs and a split out top menu. In that case though, I'll have to include it all the time. No more inheritance. Is this the best option given my requirement?
You can put your hyperlinks inside a block that is overridden by the loading templates.
Let's say you have your framework.html like this:
{% extends "base.html" %}
<html>...<body>...
{% block hyperlinks %}
your hyperlinks here
{% endblock %}
rest of the code
</body></html>
You can then create something of a nolinks.html template and use it
{% extends "framework.html" %}
{# here you'll have everything from framework
but now we disable the breadcrumbs #}
{% block hyperlinks %}{% endblock %}
If you're getting the past data you can then use nolinks to render instead of framework.
I hope this helps.
From here: Any way to make {% extends '...' %} conditional? - Django
It can be done like this :
{% extends ajax|yesno:"ajax_base.html,main_base.html" %}
Or:
{% extends a_variable_containing_base_template_name %}
Which ever best suited for you.
Regards;