Django: add ManyToMany between two apps I cannot modify - django

I have two apps:
trains provides the Train model, and
railroad the Rail model.
Since I totally love trains, I want to ensure that Train can only drive over the compatible Rail, therefore I implement a TrainRailCompatibility. However, I cannot modify neither Train nor Rail model to add a field ManyToMany(through=TrainRailCompatibility) (I am not a maintainer of those apps). I would still like to be able to do in my project something like my_train.compatible_rails.all() or filter(foo__trains__compatible_rails__in=[...]).
Is there a way / what would be the best way to achieve it?

You couls simply add this class to your desired App
class TrailRailCompatibility(models.Model):
train = models.ForeignKey('app1.Train')
rail = models.ForeignKey('app2.Rail')
and now the TrailRailCompatibility - class will be available on both of the referenced models via
from app1.models import Train
from app2.models import Rail
Trail.trailrailcompatibility_set.all()
Rail.trailrailcompatibility_set.all()

Looks like it is management issue because you can't do something in a proper way. Workaround is ugly and slower because it uses subquery instead of join.
class Compatibility(models.Model):
train = models.ForeignKey('trains.Train', related_name='compatibilities')
rail = models.ForeignKey('railroad.Rail', related_name='compatibilities')
class Meta:
unique_together = ('train', 'rail')
def get_trains(rails):
return Train.objects.filter(compatibilities__rail__in=rails)
def get_rails(train):
return Rail.objects.filter(compatibilities__train_id=train.id)

I don't think this can be done without adding the ManyToMany fields on the Train and Rail models. You could create a regular TrainRailCompatibility model with foreign keys to Train and Rail and set unique_together = ('train', 'rail') and then add entries manually. You just won't be able to access them from the Train and Rail models.

Related

Should I use ArrayField or ManyToManyField for tags

I am trying to add tags to a model for a postgres db in django and I found two solutions:
using foreign keys:
class Post(models.Model):
tags = models.ManyToManyField('tags')
...
class Tag(models.Model):
name = models.CharField(max_length=140)
using array field:
from django.contrib.postgres.fields import ArrayField
class Post(models.Model):
tags = ArrayField(models.CharField(max_length=140))
...
assuming that I don't care about supporting other database-backends in my code, what is a recommended solution ?
If you use an Array field,
The size of each row in your DB is going to be a bit large thus Postgres is going to be using more toast tables
Every time you get the row, unless you specifically use defer the field or otherwise exclude it from the query via only, or values or something, you paying the cost of loading all those values every time you iterate across that row. If that's what you need then so be it.
Filtering based on values in that array, while possible isn't going to be as nice and the Django ORM doesn't make it as obvious as it does for M2M tables.
If you use M2M field,
You can filter more easily on those related values
Those fields are postponed by default, you can use prefetch_related if you need them and then get fancy if you want only a subset of those values loaded.
Total storage in the DB is going to be slightly higher with M2M because of keys, and extra id fields.
The cost of the joins in this case is completely negligible because of keys.
With that being said, the above answer doesn't belong to me. A while ago, I had stumbled upon this dilemma when I was learning Django. I had found the answer here in this question, Django Postgres ArrayField vs One-to-Many relationship.
Hope you get what you were looking for.
If you want the class tags to be monitored ( For eg : how many tags, how many of a particular tag etd ) , the go for the first option as you can add more fields to the model and will add richness to the app.
On the other hand, if you just want it to be a array list just for sake of displaying or minimal processing, go for that option.
But if you wish to save time and add richness to the app, you can use this
https://github.com/alex/django-taggit
It is as simple as this to initialise :
from django.db import models
from taggit.managers import TaggableManager
class Food(models.Model):
# ... fields here
tags = TaggableManager()
and can be used in the following way :
>>> apple = Food.objects.create(name="apple")
>>> apple.tags.add("red", "green", "delicious")
>>> apple.tags.all()
[<Tag: red>, <Tag: green>, <Tag: delicious>]

Repeated fields in django models

I need to make a model that has 15 similar fields (let's call them field_01, field_02, field_03, etc.). I also need these fields to be easily available (e.g. to be able to do things like obj.field_01). Because I wanted to get something off the ground really quickly, I just created them the stupid way:
class M (models.Model):
....
field_01 = models.NullBooleanField()
field_02 = models.NullBooleanField()
....
I searched online for a better way to do this. Some people say use setattr, but as far as I could tell from reading and trying some stuff out, this adds attributes to an instance of a class, not the class itself, which means that when I try to attach a model form to this model, it will not see the fields added with setattr. Then I tried overriding the __new__ function, which would allow me to add properties to a class before an instance of that class is created. But I wasn't able to figure out how to do this exactly.
So, what's a way to generate these fields without breaking South and model forms and without copy-paste?
It's hard to say definitively without a concrete example of what your doing, but generally, if you find yourself repeating a field, then it's a clear sign for a one-to-many or many-to-many relationship, instead:
One-to-Many
class Field(models.Model):
m = models.ForeignKey(M, related_name='fields')
field = models.NullBooleanField()
Many-to-Many
class Field(models.Model):
field = models.NullBooleanField()
class M(models.Model):
fields = models.ManyToManyField(Field)
Django models have an add_to_class method you could (ab)use for monkey-patching models the way you would like to do.
for i in range(1, 10):
M.add_to_class('field_%s' % s, NullBooleanField())
It sounds like you are looking to have an EAV style database. You should try a library instead of rolling your own. To that end, Django EAV looks pretty awesome. https://github.com/mvpdev/django-eav
To read more about pros and cons of a bunch of libraries to accomplish this check out: https://stackoverflow.com/a/7934577/884453

Reverse foreign key sets for a model view

Wih the following model setup:
class Cat(models.Model):
claw = models.CharField(max_length=20)
name = models.CharField(max_length=20)
class Fur(models.Model):
type = models.CharField(max_length=20)
cat = models.ForeignKey(Cat)
class Meta:
db_table=u'cat_view'
managed=False
Fur has a foreign key to Cat. CatView is a subset view of Cat that is being managed manually. Is there a way to make use of django's useful reverse set methods with this setup?
Additionally, I could just use Fur.objects.filter(cat_id=cat_view.id, ...) which would be the same functionality as cat_view.fur_set.filter(...), however I could not do reverse lookups such as CatView.objects.filter(fur__type="shaggy").
EDIT:
Added example models file, changed image for clarity, added minor complexity to question.
Firstly, neither of those ORM calls you give will work: fur_set is an attribute of a cat instance, not of the Cat.objects Manager.
Secondly, Django has no specific support for database views at all, so your question about using this particular bit of functionality with a view is a bit strange. You could define CatView as a separate (unmanaged) model, although you'd need to be careful about updating and saving. Then you can get the same effect as the reverse relation by querying the Fur object directly:
Fur.objects.filter(cat=my_cat_view.id)

Data arrays in Django model

I am just starting out with Django and would like to know the best way to deal with the following data. I have DataSets which are comprised of many x,y coordinate pairs which I wish to plot. It is my understanding that Django doesn't support numeric arrays directly in it's models so what is the best way to deal with these? Right now all I can think of is something like I have below:
class DataSet(models.Model):
set_name = models.CharField(max_length=100)
class DataPoint(models.Model):
x = models.FloatField()
y = models.FloatField()
dataset = models.ForeignKey(DataSet)
This seems a bit odd and without having any experience with databases or django I am not sure how to proceed. I am using postgresql right now which I believe does support array entries but I am not sure if I am prepared to make a custom field in Django.
Short of a custom field your idea of defining DataPoint and DataSet models seems to be the way to go. You should consider changing the relationship between the two to a many to many field if there is the possibility of a data point occurring in more than one data set.
It would also help to write (with tests) a thin business layer combining the two to minimize the need to think in terms of how the models are stored in the database.
You can use the Many-to-many model relationship.
From django docs:
from django.db import models
class Topping(models.Model):
# ...
pass
class Pizza(models.Model):
# ...
toppings = models.ManyToManyField(Topping)
More info:
https://docs.djangoproject.com/en/2.1/topics/db/models/#many-to-many-relationships
Example:
https://docs.djangoproject.com/en/2.1/topics/db/examples/many_to_many/

Creation of dynamic model fields in django

This is a problem concerning django.
I have a model say "Automobiles". This will have some basic fields like "Color","Vehicle Owner Name", "Vehicle Cost".
I want to provide a form where the user can add extra fields depending on the automobile that he is adding. For example, if the user is adding a "Car", he will extra fields in the form, dynamically at run time, like "Car Milage", "Cal Manufacturer".
Suppose if the user wants to add a "Truck", he will add "Load that can be carried", "Permit" etc.
How do I achieve this in django?
There are two questions here:
How to provide a form where the user can add new fields at run time?
How to add the fields to the database so that it can be retrieved/queried later?
There are a few approaches:
key/value model (easy, well supported)
JSON data in a TextField (easy, flexible, can't search/index easily)
Dynamic model definition (not so easy, many hidden problems)
It sounds like you want the last one, but I'm not sure it's the best for you. Django is very easy to change/update, if system admins want extra fields, just add them for them and use south to migrate. I don't like generic key/value database schemas, the whole point of a powerful framework like Django is that you can easily write and rewrite custom schemas without resorting to generic approaches.
If you must allow site users/administrators to directly define their data, I'm sure others will show you how to do the first two approaches above. The third approach is what you were asking for, and a bit more crazy, I'll show you how to do. I don't recommend using it in almost all cases, but sometimes it's appropriate.
Dynamic models
Once you know what to do, this is relatively straightforward. You'll need:
1 or 2 models to store the names and types of the fields
(optional) An abstract model to define common functionality for your (subclassed) dynamic models
A function to build (or rebuild) the dynamic model when needed
Code to build or update the database tables when fields are added/removed/renamed
1. Storing the model definition
This is up to you. I imagine you'll have a model CustomCarModel and CustomField to let the user/admin define and store the names and types of the fields you want. You don't have to mirror Django fields directly, you can make your own types that the user may understand better.
Use a forms.ModelForm with inline formsets to let the user build their custom class.
2. Abstract model
Again, this is straightforward, just create a base model with the common fields/methods for all your dynamic models. Make this model abstract.
3. Build a dynamic model
Define a function that takes the required information (maybe an instance of your class from #1) and produces a model class. This is a basic example:
from django.db.models.loading import cache
from django.db import models
def get_custom_car_model(car_model_definition):
""" Create a custom (dynamic) model class based on the given definition.
"""
# What's the name of your app?
_app_label = 'myapp'
# you need to come up with a unique table name
_db_table = 'dynamic_car_%d' % car_model_definition.pk
# you need to come up with a unique model name (used in model caching)
_model_name = "DynamicCar%d" % car_model_definition.pk
# Remove any exist model definition from Django's cache
try:
del cache.app_models[_app_label][_model_name.lower()]
except KeyError:
pass
# We'll build the class attributes here
attrs = {}
# Store a link to the definition for convenience
attrs['car_model_definition'] = car_model_definition
# Create the relevant meta information
class Meta:
app_label = _app_label
db_table = _db_table
managed = False
verbose_name = 'Dynamic Car %s' % car_model_definition
verbose_name_plural = 'Dynamic Cars for %s' % car_model_definition
ordering = ('my_field',)
attrs['__module__'] = 'path.to.your.apps.module'
attrs['Meta'] = Meta
# All of that was just getting the class ready, here is the magic
# Build your model by adding django database Field subclasses to the attrs dict
# What this looks like depends on how you store the users's definitions
# For now, I'll just make them all CharFields
for field in car_model_definition.fields.all():
attrs[field.name] = models.CharField(max_length=50, db_index=True)
# Create the new model class
model_class = type(_model_name, (CustomCarModelBase,), attrs)
return model_class
4. Code to update the database tables
The code above will generate a dynamic model for you, but won't create the database tables. I recommend using South for table manipulation. Here are a couple of functions, which you can connect to pre/post-save signals:
import logging
from south.db import db
from django.db import connection
def create_db_table(model_class):
""" Takes a Django model class and create a database table, if necessary.
"""
table_name = model_class._meta.db_table
if (connection.introspection.table_name_converter(table_name)
not in connection.introspection.table_names()):
fields = [(f.name, f) for f in model_class._meta.fields]
db.create_table(table_name, fields)
logging.debug("Creating table '%s'" % table_name)
def add_necessary_db_columns(model_class):
""" Creates new table or relevant columns as necessary based on the model_class.
No columns or data are renamed or removed.
XXX: May need tweaking if db_column != field.name
"""
# Create table if missing
create_db_table(model_class)
# Add field columns if missing
table_name = model_class._meta.db_table
fields = [(f.column, f) for f in model_class._meta.fields]
db_column_names = [row[0] for row in connection.introspection.get_table_description(connection.cursor(), table_name)]
for column_name, field in fields:
if column_name not in db_column_names:
logging.debug("Adding field '%s' to table '%s'" % (column_name, table_name))
db.add_column(table_name, column_name, field)
And there you have it! You can call get_custom_car_model() to deliver a django model, which you can use to do normal django queries:
CarModel = get_custom_car_model(my_definition)
CarModel.objects.all()
Problems
Your models are hidden from Django until the code creating them is run. You can however run get_custom_car_model for every instance of your definitions in the class_prepared signal for your definition model.
ForeignKeys/ManyToManyFields may not work (I haven't tried)
You will want to use Django's model cache so you don't have to run queries and create the model every time you want to use this. I've left this out above for simplicity
You can get your dynamic models into the admin, but you'll need to dynamically create the admin class as well, and register/reregister/unregister appropriately using signals.
Overview
If you're fine with the added complication and problems, enjoy! One it's running, it works exactly as expected thanks to Django and Python's flexibility. You can feed your model into Django's ModelForm to let the user edit their instances, and perform queries using the database's fields directly. If there is anything you don't understand in the above, you're probably best off not taking this approach (I've intentionally not explained what some of the concepts are for beginners). Keep it Simple!
I really don't think many people need this, but I have used it myself, where we had lots of data in the tables and really, really needed to let the users customise the columns, which changed rarely.
Database
Consider your database design once more.
You should think in terms of how those objects that you want to represent relate to each other in the real world and then try to generalize those relations as much as you can, (so instead of saying each truck has a permit, you say each vehicle has an attribute which can be either a permit, load amount or whatever).
So lets try it:
If you say you have a vehicle and each vehicle can have many user specified attributes consider the following models:
class Attribute(models.Model):
type = models.CharField()
value = models.CharField()
class Vehicle(models.Model):
attribute = models.ManyToMany(Attribute)
As noted before, this is a general idea which enables you to add as much attributes to each vehicle as you want.
If you want specific set of attributes to be available to the user you can use choices in the Attribute.type field.
ATTRIBUTE_CHOICES = (
(1, 'Permit'),
(2, 'Manufacturer'),
)
class Attribute(models.Model):
type = models.CharField(max_length=1, choices=ATTRIBUTE_CHOICES)
value = models.CharField()
Now, perhaps you would want each vehicle sort to have it's own set of available attributes. This can be done by adding yet another model and set foreign key relations from both Vehicle and Attribute models to it.
class VehicleType(models.Model):
name = models.CharField()
class Attribute(models.Model):
vehicle_type = models.ForeigngKey(VehicleType)
type = models.CharField()
value = models.CharField()
class Vehicle(models.Model):
vehicle_type = models.ForeigngKey(VehicleType)
attribute = models.ManyToMany(Attribute)
This way you have a clear picture of how each attribute relates to some vehicle.
Forms
Basically, with this database design, you would require two forms for adding objects into the database. Specifically a model form for a vehicle and a model formset for attributes. You could use jQuery to dynamically add more items on the Attribute formset.
Note
You could also separate Attribute class to AttributeType and AttributeValue so you don't have redundant attribute types stored in your database or if you want to limit the attribute choices for the user but keep the ability to add more types with Django admin site.
To be totally cool, you could use autocomplete on your form to suggest existing attribute types to the user.
Hint: learn more about database normalization.
Other solutions
As suggested in the previous answer by Stuart Marsh
On the other hand you could hard code your models for each vehicle type so that each vehicle type is represented by the subclass of the base vehicle and each subclass can have its own specific attributes but that solutions is not very flexible (if you require flexibility).
You could also keep JSON representation of additional object attributes in one database field but I am not sure this would be helpfull when querying attributes.
Here is my simple test in django shell- I just typed in and it seems work fine-
In [25]: attributes = {
"__module__": "lekhoni.models",
"name": models.CharField(max_length=100),
"address": models.CharField(max_length=100),
}
In [26]: Person = type('Person', (models.Model,), attributes)
In [27]: Person
Out[27]: class 'lekhoni.models.Person'
In [28]: p1= Person()
In [29]: p1.name= 'manir'
In [30]: p1.save()
In [31]: Person.objects.a
Person.objects.aggregate Person.objects.all Person.objects.annotate
In [32]: Person.objects.all()
Out[33]: [Person: Person object]
It seems very simple- not sure why it should not be a considered an option- Reflection is very common is other languages like C# or Java- Anyway I am very new to django things-
Are you talking about in a front end interface, or in the Django admin?
You can't create real fields on the fly like that without a lot of work under the hood. Each model and field in Django has an associated table and column in the database. To add new fields usually requires either raw sql, or migrations using South.
From a front end interface, you could create pseudo fields, and store them in a json format in a single model field.
For example, create an other_data text field in the model. Then allow users to create fields, and store them like {'userfield':'userdata','mileage':54}
But I think if you're using a finite class like vehicles, you would create a base model with the basic vehicle characteristics, and then create models that inherits from the base model for each of the vehicle types.
class base_vehicle(models.Model):
color = models.CharField()
owner_name = models.CharField()
cost = models.DecimalField()
class car(base_vehicle):
mileage = models.IntegerField(default=0)
etc