Editing an Object in Database from Django Form - django

How can you edit an existing object in a database from a form? I use this for example:
obj_ex = Model(column = value, column2 = value2)
obj_ex.save()
However this doesn't update my object in the database. I have tried to access the pk of the entry and save the values of the entry with the pk of x but I still can't update the table.
Is there a way to use an .update() type to update objects? Or is there another way to update a table?
Thank you.

Instead of:
obj_ex = Model(column=value, column2=value2)
Which creates a new instance (and later a new db record) try:
o = Model.objects.get(pk=1234) # load instance with id=1234 to memory from db
o.column = value
o.column2 = value2
o.save()

Because I had multiple entries in the table, I used an update field to updated the cells in the table. This is what I did:
o = Model.objects.filter(x=value0).values_list("id", flat=True) #where x is posted information getting the primary key (id).
Model.objects.select_related().filter(id = o).update(column = value, column2 = value2)
The update field does not need a .save() as it will update the table when it is called.
I would like to thank Udi for his answer as it did step me into the right direction.

Related

save() not updating the table in database

I have to update 2 tables in database every time user visit a page.
this is working:
order_order = OrderTable.no_objects.get(order_number=order_id)
order_order.status = 'updated status'
order_order.save()
This is not working: (related with first table through foreign key)
order_item = ItemsTable.objects.filter(order_id__order_number=order_id)
for i in range(order_item.count()):
order_item[i].qty = i + 5
order_item[i].qty_nextMonth = i + 30
order_item[i].save()
Can anyone tell what's wrong in 2nd part of code. It's not updating the database.
Each time you write order_item[i], you make a separate fetch, and you return an ItemsTable item from the database. That means that if you set the .qty = ... attribute of that object, it is simply ignored, since the next order_item[i] will trigger a new fetch. Your order_item[i].save() updates the record in the database, but with the values that have been retrieved just from a fetch from the database.
It is better to simply iterate over the queryset, and thus maintain a reference to the same ItemsTable object:
order_items = ItemsTable.objects.filter(order_id__order_number=order_id)
for i, order_item in enumerate(order_items):
order_item.qty = i + 5
order_item.qty_nextMonth = i + 30
order_item.save()
This is more efficient as well, since enumerating over a queryset forces evaluation, and hence you fetch all objects at once.
As of django-2.2, you can use .bulk_update(..) [Django-doc], to update in bulk an iterable of objects.

How to change data type of column in DynamoDb?

Initially I have inserted integer values hence schema created with column type number, later string values were also inserted in same column. Now I am facing issue while fetching values. Need tho update column type number to string.
Well, there are no columns in DynamoDB and even if you consider attributes as columns which they are not, they don't enforce specific type, except for primary key. Therefore you can't change the type of a column.
If you are asking about how to change type of a specific attribute for all items in a table, then you need to run update command on all of the items. DynamoDB unfortunately doesn't support batch update operation, therefore you need to fetch keys of all the items that you need to updated, loop through that list and update each item separately.
I recently had to do this. Here is my script that I used:
Assume that 'timestamp' is name of column you need to change from string to number. So here is solution:
import boto3
from boto3.dynamodb.conditions import Key
db_client = boto3.resource('dynamodb', region_name="eu-west-3")
table_res = db_client.Table(TABLE_NAME)
not_finished = True
ret = table_res.scan()
while not_finished:
for item in ret['Items']:
if 'timestamp' in item and isinstance(item['timestamp'], str):
new_item = item
new_item['timestamp'] = int(float(item['timestamp']))
print("fixing {}, {} -> {}".format(item['SK'], item['timestamp'], new_item['timestamp']))
table_res.put_item(Item = new_item)
if "LastEvaluatedKey" in ret:
last_key = ret['LastEvaluatedKey']
ret = table_res.scan(ExclusiveStartKey = last_key)
else:
not_finished = False
I do understand you probably don't need this anymore, but I still hope this will help somebody.

how to store a field in the database after querying

views.py:
q3=KEBReading.objects.filter(datetime_reading__month=a).filter(datetime_reading__year=selected_year).values("signed")
for item in q3:
item["signed"]="signed"
print item["signed"]
q3.save()
How do I save a field into the database? I'm trying to save the field called "signed" with a value. If I do q3.save() it gives a error as it is a queryset. I'm doing a query from the database and then, based on the result, want to set a value to a field and save it.
prevdate=KEBReading.objects.filter(datetime_reading__lt=date)
i am getting all the rows from the database less than the current date. but i want only the latest record. if im entering 2012-06-03. wen i query i want the date less than this date i.e the date just previous to this. can sumbody help?
q3 = KEBReading.objects.filter(datetime_reading__month=a,
datetime_reading__year=selected_year)
for item in q3:
item.signed = True
item.save()
q3=KEBReading.objects.filter(...)
will return you a list of objects. Any instance of a Django Model is an object and all fields of the instance are attributes of that object. That means, you must use them using dot (.) notation.
like:
item.signed = "signed"
If your object is a dictionary or a class derived from dictionary, then you can use named-index like:
item["signed"] = "signed"
and in your situation, that usage is invalid (because your object's type is not dictionary based)
You can either call update query:
KEBReading.objects.filter(...).update(selected="selected")
or set new value in a loop and then save it
for item in q3:
item.signed="signed"
q3.save()
but in your situation, update query is a better approach since it executes less database calls.
Try using update query:
If signed is a booleanfield:
q3 = KEBReading.objects.filter(datetime_reading__month = a).filter(datetime_reading__year = selected_year).update(signed = True)
If it is a charfield:
q3 = KEBReading.objects.filter(datetime_reading__month = a).filter(datetime_reading__year = selected_year).update(signed = "True")
Update for comments:
If you want to fetch records based datetime_reading month, you can do it by providing month as number. For example, 2 for February:
q3 = KEBReading.objects.filter(datetime_reading__month = 2).order_by('datetime_reading')
And if you to fetch records with signed = True, you can do it by:
q3 = KEBReading.objects.filter(signed = True)
If you want to fetch only records of previous date by giving a date, you can use:
prevdate = KEBReading.objects.filter(datetime_reading = (date - datetime.timedelta(days = 1)))

How to 'bulk update' with Django?

I'd like to update a table with Django - something like this in raw SQL:
update tbl_name set name = 'foo' where name = 'bar'
My first result is something like this - but that's nasty, isn't it?
list = ModelClass.objects.filter(name = 'bar')
for obj in list:
obj.name = 'foo'
obj.save()
Is there a more elegant way?
Update:
Django 2.2 version now has a bulk_update.
Old answer:
Refer to the following django documentation section
Updating multiple objects at once
In short you should be able to use:
ModelClass.objects.filter(name='bar').update(name="foo")
You can also use F objects to do things like incrementing rows:
from django.db.models import F
Entry.objects.all().update(n_pingbacks=F('n_pingbacks') + 1)
See the documentation.
However, note that:
This won't use ModelClass.save method (so if you have some logic inside it won't be triggered).
No django signals will be emitted.
You can't perform an .update() on a sliced QuerySet, it must be on an original QuerySet so you'll need to lean on the .filter() and .exclude() methods.
Consider using django-bulk-update found here on GitHub.
Install: pip install django-bulk-update
Implement: (code taken directly from projects ReadMe file)
from bulk_update.helper import bulk_update
random_names = ['Walter', 'The Dude', 'Donny', 'Jesus']
people = Person.objects.all()
for person in people:
r = random.randrange(4)
person.name = random_names[r]
bulk_update(people) # updates all columns using the default db
Update: As Marc points out in the comments this is not suitable for updating thousands of rows at once. Though it is suitable for smaller batches 10's to 100's. The size of the batch that is right for you depends on your CPU and query complexity. This tool is more like a wheel barrow than a dump truck.
Django 2.2 version now has a bulk_update method (release notes).
https://docs.djangoproject.com/en/stable/ref/models/querysets/#bulk-update
Example:
# get a pk: record dictionary of existing records
updates = YourModel.objects.filter(...).in_bulk()
....
# do something with the updates dict
....
if hasattr(YourModel.objects, 'bulk_update') and updates:
# Use the new method
YourModel.objects.bulk_update(updates.values(), [list the fields to update], batch_size=100)
else:
# The old & slow way
with transaction.atomic():
for obj in updates.values():
obj.save(update_fields=[list the fields to update])
If you want to set the same value on a collection of rows, you can use the update() method combined with any query term to update all rows in one query:
some_list = ModelClass.objects.filter(some condition).values('id')
ModelClass.objects.filter(pk__in=some_list).update(foo=bar)
If you want to update a collection of rows with different values depending on some condition, you can in best case batch the updates according to values. Let's say you have 1000 rows where you want to set a column to one of X values, then you could prepare the batches beforehand and then only run X update-queries (each essentially having the form of the first example above) + the initial SELECT-query.
If every row requires a unique value there is no way to avoid one query per update. Perhaps look into other architectures like CQRS/Event sourcing if you need performance in this latter case.
Here is a useful content which i found in internet regarding the above question
https://www.sankalpjonna.com/learn-django/running-a-bulk-update-with-django
The inefficient way
model_qs= ModelClass.objects.filter(name = 'bar')
for obj in model_qs:
obj.name = 'foo'
obj.save()
The efficient way
ModelClass.objects.filter(name = 'bar').update(name="foo") # for single value 'foo' or add loop
Using bulk_update
update_list = []
model_qs= ModelClass.objects.filter(name = 'bar')
for model_obj in model_qs:
model_obj.name = "foo" # Or what ever the value is for simplicty im providing foo only
update_list.append(model_obj)
ModelClass.objects.bulk_update(update_list,['name'])
Using an atomic transaction
from django.db import transaction
with transaction.atomic():
model_qs = ModelClass.objects.filter(name = 'bar')
for obj in model_qs:
ModelClass.objects.filter(name = 'bar').update(name="foo")
Any Up Votes ? Thanks in advance : Thank you for keep an attention ;)
To update with same value we can simply use this
ModelClass.objects.filter(name = 'bar').update(name='foo')
To update with different values
ob_list = ModelClass.objects.filter(name = 'bar')
obj_to_be_update = []
for obj in obj_list:
obj.name = "Dear "+obj.name
obj_to_be_update.append(obj)
ModelClass.objects.bulk_update(obj_to_be_update, ['name'], batch_size=1000)
It won't trigger save signal every time instead we keep all the objects to be updated on the list and trigger update signal at once.
IT returns number of objects are updated in table.
update_counts = ModelClass.objects.filter(name='bar').update(name="foo")
You can refer this link to get more information on bulk update and create.
Bulk update and Create

Django AutoField not returning new primary_key

We've got a small problem with a Django project we're working on and our postgresql database.
The project we're working on is a site/db conversion from a PHP site to a django site. So we used inspect db to generate the models from the current PHP backend.
It gave us this and we added the primary_key and unique equals True:
class Company(models.Model):
companyid = models.IntegerField(primary_key=True,unique=True)
...
...
That didn't seem to be working when we finally got to saving a new Company entry. It would return a not-null constraint error, so we migrated to an AutoField like below:
class Company(models.Model):
companyid = models.AutoField(primary_key=True)
...
...
This saves the Company entry fine but the problem is when we do
result = form.save()
We can't do
result.pk or result.companyid
to get the newly given Primary Key in the database (yet we can see that it has been given a proper companyid in the database.
We are at a loss for what is happening. Any ideas or answers would be greatly appreciated, thanks!
I just ran into the same thing, but during a django upgrade of a project with a lot of history. What a pain...
Anyway, the problem seems to result from the way django's postgresql backend gets the primary key for a newly created object: it uses pg_get_serial_sequence to resolve the sequence for a table's primary key. In my case, the id column wasn't created with a serial type, but rather with an integer, which means that my sequence isn't properly connected to the table.column.
The following is based on a table with the create statement, you'll have to adjust your table names, columns and sequence names according to your situation:
CREATE TABLE "mike_test" (
"id" integer NOT NULL PRIMARY KEY,
"somefield" varchar(30) NOT NULL UNIQUE
);
The solution if you're using postgresql 8.3 or later is pretty easy:
ALTER SEQUENCE mike_test_id_seq OWNED BY mike_test.id;
If you're using 8.1 though, things are a little muckier. I recreated my column with the following (simplest) case:
ALTER TABLE mike_test ADD COLUMN temp_id serial NOT NULL;
UPDATE mike_test SET temp_id = id;
ALTER TABLE mike_test DROP COLUMN id;
ALTER TABLE mike_test ADD COLUMN id serial NOT NULL PRIMARY KEY;
UPDATE mike_test SET id = temp_id;
ALTER TABLE mike_test DROP COLUMN temp_id;
SELECT setval('mike_test_id_seq', (SELECT MAX(id) FROM mike_test));
If your column is involved in any other constraints, you'll have even more fun with it.