What are "steps" in RegexBuddy? - regex

RegexBuddy on the tab "Debug" shows how regular expressions are executed step by step. But what exactly that steps mean? What operations are behind every step?

The steps count is basically how many times the current position in the input was changed, which is a very good indicator of performance.
The "current position" may be at any character or between characters (including before and after the entire input).
Simplifying it, regex engines process the input by moving the current position along the input and evaluating whether the regex matches at that position. They also keep track of the position in the regex the match is up to.
I don't want to turn this answer into a regex tutorial, but... regex engines always consume as much of the input as possible while still matching. To give a simple example, given the input "12345" and the regex .*1.*, the regex engine will first apply .* consuming all input leaving the position at the end of the input, fail to match a 1, then back track by "uncomsuming" one character at a time until it finds a 1, then continue. You can see that this would take 9 steps just to process the initial .*.
By contrast, if the regex was [^1]*1.*, the regex will match the "1" in just one step.

In RegexBuddy's debugger, a step is when the regex engine matches something, or fails to match something. Steps that match a character are indicated by all the characters matched by the regex so far which will usually be one character more than the previous step. Steps that match a position, like a word boundary, are indicated by the characters matched so far plus "ok". Steps that failed to match something are indicated by the characters matched so far plus "backtrack".
If you click on any of the matched characters in the debugger, RegexBuddy selects the token in the regular expression that matched those characters and highlights all the characters in the debugger matched by that token. If you click on an "ok" or "backtrack" indicator, RegexBuddy selects the token in the regex that matched or failed to match.
Moving the cursor with the keyboard has the same effect as clicking. Pressing the End key on the keyboard moves the cursor to the end of a step. Then pressing Arrow Up or Down moves the cursor to the previous or next step while keeping the cursor at the end of that step. By moving the cursor this way, you can easily follow how the regex engine steps through your regular expression and which characters is matches and backtracks along the way.
For more details, see these two pages in RegexBuddy's help file:
https://www.regexbuddy.com/manual.html#debug
https://www.regexbuddy.com/manual.html#benchmark

Related

Regular expression to delete all words between two specific words

I'm normally ok with regex but I'm struggling with this.
I have a simple file with two words that start and end a set of data. The data between the words changes but - start and status are always in the same place.
Example :
start
Everything in between
status
I'm trying to work out how to delete (replace) everything between and including start and status
I'm sure I had it working with this at one time
(?i)^start.+?status
set(#replaceAll,$replace regular expression(#textTest,"(?i)^start.+?status"," "),"Global")
but its just not working anymore.
You could use the regular expression
\bstart\b.+?\bstatus\b
which does not require "status" to be on the same line as "start". Two flags should be set:
case indifference (/i)
single-line mode, which allows . to match a newline (/s)
Demo
The regex reads, "match 'start' with a word break fore and aft (to avoid matching 'starting' or 'jumpstart', for example), then match one or more characters lazily, then match 'status' with wordbreaks". The middle match must be lazy so that the regex engine will stop at the next (rather than last) instance of 'status'.
If the regex engine being used does not support single-line mode, or something comparable, one can replace .+ with [\s\S]+.
So my original expression works and so dose Cary's
The files have changed since I last used the expression. They contain some white-space in the form of newlines that needed to be removed first
set(#cleanup,$replace(#text2,$new line," "),"Global")
set(#text2,$replace regular expression(#cleanup,"\\bstart\\b.*?\\bstatus\\b",""),"Global")
set(#cleanup,$replace regular expression(#cleanup,"(?i)^start.+?status:",""),"Global")
Sorry about that but thanks to all who looked and helped :)

How do I regex search in x and y for a, and only include the replacement of y if a was found in x?

I need to search through a larger text file.
This is an example of what I'm searching through.
https://pastebin.com/JFVy2TEt
recipes.addShaped("basemetals:adamantine_arrow", <basemetals:adamantine_arrow> * 4, [[<ore:nuggetAdamantine>], [<basemetals:adamantine_rod>], [<minecraft:feather>]]);
I need to look for lines that match a specific part in the first argument.
For example the "_arrow" part in the above line.
And erase everything that doesn't match on the "_arrow" in the first argument.
And the arguments differ across all of them.
And also with different names in the place where "basemetals:adamantine" is in the above line.
And since the further arguments are all different I can't wrap my head around on how to include the end only when the first thing matches.
Edit: The end goal being to ease sort my 3k+ line text file.
basic, blacksmith, carpenter, chef, chemist, engineer, farmer, jeweler, mage, mason, scribe, tailor
I think what you're trying to do is filter your text file by removing lines that don't fit a set criteria. I've chosen the Atom text editor for this solution (because I'm running Windows OS and can't install gedit, and I want to ensure you have a working example).
To remove only lines that don't have a first argument ending in _arrow, one could do (?!recipes\.addShaped\("[^"]+_arrow")recipes.+\r?\n? and replace with nothing.
As a note: this task is made more difficult by Atom's low regex support. In a more well-supported environment, my answer would probably be ^recipes\.addShaped("[^"]+(?<!_arrow)").+\r?\n? (with multiline mode).
Also, please read "What should I do when someone answers my question?".
Regex explained:
(?! ) is a negative lookahead, which peeks at the succeeding text to ensure it doesn't contain "_arrow" at end of the first argument.
\. is an escaped literal period
[^"] is a character class that signifies a character that is not a ".
+ is a quantifier which tells the regex to match the preceding character or subexpression as many times as possible, with a minimum of one time.
. is a wildcard, representing any character
\r?\n? is used to match any kind of newline, with the ? quantifier making each character optional.
Everything else it literal characters; it represents exactly what it matches.

Regex taking too many characters

I need some help with building up my regex.
What I am trying to do is match a specific part of text with unpredictable parts in between the fixed words. An example is the sentence one gets when replying to an email:
On date at time person name has written:
The cursive parts are variable, might contains spaces or a new line might start from this point.
To get this, I built up my regex as such: On[\s\S]+?at[\s\S]+?person[\s\S]+?has written:
Basically, the [\s\S]+? is supposed to fill in any letter, number, space or break/new line as I am unable to predict what could be between the fixed words tha I am sure will always be there.
Now comes the hard part, when I would add the word "On" somewhere in the text above the sentence that I want to match, the regex now matches a much bigger text than I want. This is due to the use of [\s\S]+.
How am I able to make my regex match as less characters as possible? Using "?" before the "+" to make it lazy does not help.
Example is here with words "From - This - Point - Everything:". Cases are ignored.
Correct: https://regexr.com/3jdek.
Wrong because of added "From": https://regexr.com/3jdfc
The regex is to be used in VB.NET
A more real life, with html tags, can be found here. Here, I avoided using [\s\S]+? or (.+)?(\r)?(\n)?(.+?)
Correct: https://regexr.com/3jdd1
Wrong: https://regexr.com/3jdfu after adding certain parts of the regex in the text above. Although, in html, barely possible to occur as the user would never write the matching tag himself, I do want to make sure my regex is correctjust in case
These things are certain: I know with what the part of text starts, no matter where in respect to the entire text, I know with what the part of text ends, and there are specific fixed words that might make the regex more reliable, but they can be ommitted. Any text below the searched part is also allowed to be matched, but no text above may be matched at all
Another example where it goes wrong: https://regexr.com/3jdli. Basically, I have less to go with in this text, so the regex has less tokens to work with. Adding just the first < already makes the regex take too much.
From my own experience, most problems are avoided when making sure I do not use any [\s\S]+? before I did a (\r)?(\n)? first
[\s\S] matches all character because of union of two complementary sets, it is like . with special option /s (dot matches newlines). and regex are greedy by default so the largest match will be returned.
Following correct link, the token just after the shortest match must be geschreven, so another way to write without using lazy expansion, which is more flexible is to prepend the repeated chracter set by a negative lookahead inside loop,
so
<blockquote type="cite" [^>]+?>[^O]+?Op[^h]+?heeft(.+?(?=geschreven))geschreven:
becomes
<blockquote type="cite" [^>]+?>[^O]+?Op[^h]+?heeft((?:(?!geschreven).)+)geschreven:
(?: ) is for non capturing the group which just encapsulates the negative lookahead and the . (which can be replaced by [\s\S])
(?! ) inside is the negative lookahead which ensures current position before next character is not the beginning of end token.
Following comments it can be explicitly mentioned what should not appear in repeating sequence :
From(?:(?!this)[\s\S])+this(?:(?!point)[\s\S])+point(?:(?!everything)[\s\S])+everything:
or
From(?:(?!From|this)[\s\S])+this(?:(?!point)[\s\S])+point(?:(?!everything)[\s\S])+everything:
or
From(?:(?!From|this)[\s\S])+this(?:(?!this|point)[\s\S])+point(?:(?!everything)[\s\S])+everything:
to understand what the technic (?:(?!tokens)[\s\S])+ does.
in the first this can't appear between From and this
in the second From or this can't appear between From and this
in the third this or point can't appear between this and point
etc.

Regular expression to extract whole sentences with matching word

I would like to extract sentences with the word "flung" in the whole text.
For example, in the following text, I'd like to extract the sentence "It was exactly as if a hand had clutched them in the centre and flung them aside." using regular expression.
I tried to use this .*? flung (?<sub>.*?)\., but it starts searching from the beginning of the line.
How could I solve the problem?
As she did so, a most extraordinary thing happened. The bed-clothes gathered themselves together, leapt up suddenly into a sort of peak, and then jumped headlong over the bottom rail. It was exactly as if a hand had clutched them in the centre and flung them aside. Immediately after, .........
Here you go,
[^.]* flung [^.]*\.
DEMO
OR
[^.?!]*(?<=[.?\s!])flung(?=[\s.?!])[^.?!]*[.?!]
DEMO
Simply anything between dots:
without a dote
[A-Za-z," ]+word[A-Za-z," ]+
with a dote
[A-Za-z," ]+word[A-Za-z," ]+\.
"[A-Z]\\s?\\w*\\s?(([^(\\.\\s)|(\\?\\s)|(!\\s)])|\\s)*(?:your target\\s)(([^(\\.\\s)|(\\?\\s)|(!\\s)])|\\s)*(([^(\\.\\s)|(\\?\\s)|(!\\s)])|\\s)*[\\.|\\?|!]"
A sentence starts with any capital letter, in the middle it may contain decimal or abbreviation.
(?<=^|\s)[A-Z][^!?.]*( word\s*)[^!?.]*(?=\.|\!|\?)
Before first capital letter there is a line start or a white space, then it may consist any characters without set of [!?.](*)-or may not , then contains your target word with or without white spaces after it (if it is in the end of the sentence), then may consist again any characters without set of [!?.](*)-or not, and finally ends with dot or ! or ?.

Remove everything before and after variable=int

I'm terrible at regex and need to remove everything from a large portion of text except for a certain variable declaration that occurs numerous times, id like to remove everything except for instances of mc_gross=anyint.
Generally we'd need to use "negative lookarounds" to find everything but a specified string. But these are fairly inefficient (although that's probably of little concern to you in this instance), and lookaround is not supported by all regex engines (not sure about notepad++, and even then probably depends on the version you're using).
If you're interested in learning about that approach, refer to How to negate specific word in regex?
But regardless, since you are using notepad++, I'd recommend selecting your target, then inverting the selection.
This will select each instance, allowing for optional white space either side of the '=' sign.
mc_gross\s*=\s*\d+
The following answer over on super user explains how to use bookmarks in notepad++ to achieve the "inverse selection":
https://superuser.com/questions/290247/how-to-delete-all-line-except-lines-containing-a-word-i-need
Substitute the regex they're using over there, with the one above.
You could do a regular expression replace of ^.*\b(mc_gross\s*=\s*\d+)\b.*$ with \1. That will remove everything other than the wanted text on each line. Note that on lines where the wanted text occurs two or more times, only one occurrence will be retained. In the search the ^.*\b matches from start-of-line to a word boundary before the wanted text; the \b.*$ matches everything from a word boundary after the wanted text until end of line; the round brackets capture the wanted text for the replacement text. If text such as abcmc_gross=13def should be matched and retained as mc_gross=13 then delete the \bs from the search.
To remove unwanted lines do a regular expression search for ^mc_gross\s*=\s*\d+$ from the Mark tab, tick Bookmark line and click Mark all. Then use Menu => Search => Bookmark => Remove unmarked lines.
Find what: [\s\S]*?(mc_gross=\d+|\Z)
Replace with: \1
Position the cursor at the start of the text then Replace All.
Add word boundaries \b around mc_gross=\d+ if you think it's necessary.