I'm having trouble dynamically allocating my struct - c++

Question

I created a simple program to help me understand how to Dynamically Allocate a structure. I want the program to gets 5 names and 5 accounts from the user, and display the names and the accounts. I know a pointer is like a reference variable, the only differences instead of passing the value, it passes the address of the variable. I set a breaking point for line 23 ("getline(std::cin,clientPtr[count].name);"), line 25 ("std::cin.ignore(std::numeric_limits::max(),'\n');"),
line 27 ("std::cin >>clientPtr[count].accounts;"), line 40 ("std::cout <<"Name:" << clientPtr[count].name;"), line 41 ("std::cout <<"Name:" << clientPtr[count].name;"),line 31( showInfo(&client);). When I debugged it shows that line 41 is not executing. It should display the names and the accounts of each client. In this case it's not. I'm not sure why, just a little background on me, I'm new to C++, as well with using the debugger. I'm using xcode 8.2 and the debugger I am using is lldb. I'm here to learn, so anything will help. Thanks.
#include <iostream>
#include <limits>
struct BankInfo
{
std::string name;
std::string accounts;
};
void showInfo(BankInfo*);
int main()
{
BankInfo client;
BankInfo* clientPtr=nullptr;
clientPtr = new BankInfo[5];
for(int count =0; count < 5; count++)
{
std::cout << "Enter your name:";
getline(std::cin,clientPtr[count].name);
std::cin.clear();
std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
std::cout << "Enter you account number:";
std::cin >>clientPtr[count].accounts;
}
showInfo(&client);
return 0;
}
void showInfo(BankInfo* clientPtr)
{
for(int count =5; count < 5; count++)
{
std::cout <<"Name:" << clientPtr[count].name;
std::cout <<"Account:" << clientPtr[count].accounts;
}
}

Answer 1

You are handing the wrong thing to showInfo(). You have two variables.. a single BankInfo variable and a dynamic allocated array with size 5.
You want to iterate over the latter and not the former.
Changing showInfo(&client);to showInfo(clientPtr); should do the trick perhaps?

Answer 2

So I fixed the solution I made several mistakes, but thank you for the suggestion. Here's what I did.
#include <iostream>
#include <limits>
struct BankInfo
{
std::string name;
std::string accounts;
};
void showInfo(BankInfo*);
int main()
{
BankInfo client;
BankInfo* clientPtr=nullptr;
clientPtr = new BankInfo[5]; //Allocate an array of BankInfo struct on the heap
for(int count =0; count < 5; count++)
{
std::cout << "Enter your name:";
getline(std::cin,clientPtr[count].name); // stores the value in the name member
std::cout << "Enter you account number:";
std::cin >>clientPtr[count].accounts; // stores the value in accounts member
std::cin.clear();
std::cin.ignore(std::numeric_limits<std::streamsize>::max(),'\n');
}
showInfo(clientPtr);
delete [] clientPtr;
clientPtr = nullptr;
return 0;
}
void showInfo(BankInfo* clientPtr)
{
for(int count =0; count < 5; count++)
{
std::cout <<"\nName:" << clientPtr[count].name; // dereference the pointer to the structure
std::cout <<"\nAccount:" << clientPtr[count].accounts; // dereference the pointer to the structure
}
}

Answer 3

for(int count=1 ; count<=5 ; count++)
{
//do your stuff here
}