i am trying to open an text file and trying to count the numbers of characters and words in the file, i have created while " while (!infile.eof()); " to scan the whole file till the end . However only one of the function is working and other one is also printing the same answer as the first one.
#include <iostream>
#include <fstream>
#include <conio.h>
using namespace std;
int main()
{
ifstream infile;
infile.open("tomorrow.txt");
int count1_char = 0;
int count2_word = 0;
while (!infile.eof())
{
{
char ch;
infile.get(ch); //number of characters
count1_char++;
}
{
char word[30];
infile >> word; //numner of words
count2_word++;
}
}
cout << " the number of characters :" << count1_char << endl;
cout << " the number of words :" << count2_word << endl;
infile.close();
return 0;
}
the output:
the number of characters :17
the number of words :17
Press any key to continue . . .
Since words consist of characters, you cannot read characters and words separately. You should take one of two approaches:
Read words, and add their lengths to character count - this approach is very simple, but your code has no control over separators, or
Read characters, and find delimiters to decide when one word ends and another word begins - this is slightly more complex, but your program stays in full control over its input.
The advantage of the first approach is its simplicity; the advantage of the second approach is an ability to account for whitespace characters correctly.
The second approach requires you to keep a "state" that lets you distinguish if the current character is part of a new word, or a continuation of a previously found word. A simple flag is sufficient for this. You will have one loop reading characters one by one, classifying each character as a space or non-space (e.g. with std::isspace function), incrementing the character count, and doing one of three things:
If you see a space, reset "is inside a word" flag to "false"
If you see a non-space, and "is inside a word" flag is "true", do nothing
If you see a non-space, and "is inside a word" flag is "false", set it to "true", and increment word count.
Related
so I'm pretty new to C++ and I'm doing an assignment for my class. I ran into a problem when trying to check if an input is a string or a double/int. So I made a basic program to test it
#include <iostream>
#include <string>
using namespace std;
int main(int argc, char *argv[])
{
string hi;
double hello;
cin >> hello;
if (!cin)
{
//Strings go here
cin.clear();
cin >> hi;
cout << hi << endl;
}
else
{
cout << hello << endl;
}
cout << "Done!" << endl;
}
So it works for basically when inputting a letter (such as "j" or "a") or a number but when inputting "+" or "-" it waits for the next input then forces it through the string block, even if it is a number. However "*" or "/" are read as strings and don't cause that issue (I'm assuming since they aren't explicitly operators)
I assume I am probably missing something. Thank you
Edit: I am testing with single types at a time (such as 123, 1 , d, +) without mixing types, so there won't be any inputs that have a double and a string
As per user4581301's suggestion, I'll put in some examples input and outputs
Inputs:Outputs
"Hello":"Hello"
123:123
"/":"/"
"+" (Input after: 2):"2"
The problem
Your programme does not work exactly as intended, because it doesn't take into consideration potentially consumed but lost characters.
Here are different cases that work as expected:
abc: the first char read is not numeric, so it's not consumed and cin fails fast. The second reading reads every chars present as a string.
123abc456: the first 123 is read. When a is encountered, it is not consumed since it's not valid numeric. Further reading is stopped, but a numeric value could be read.
/123: the first char read is not numeric, so it's not consumed and cin fails. the second reading reads every char present as string.
-123 or +123: the first char is considered as a valid numeric char and is read, and then the remainder is read, still as a numeric value. Works as expected if you consider that a double ora an int can be signed. Depending on output formatting, the + might not appear with your output.
Here are the cases that do not work: if the first char is + or - but it is not followed by a valid numeric char. In this case the first char is consumed, but the next char makes the numeric input fail. The remaining chars are then read as string (except the first sign that was already consumed and is lost). Examples:
++123
+ 123 (the space ends the axtraction of the double that fails, the remainder is read as a string).
Online demo
The solution
The easiest solution is to read the input as a string, then try to convert the string.
For example:
size_t processed;
string hi;
double hello;
cin >> hi;
try {
hello = stod(hi,&processed);
cout<<"number:" <<hello;
if (processed<hi.size())
cout << " (followed by something)";
cout <<endl;
}
catch (...) // should be more precise in catching, but it's for the proof of concept
{
cout <<"string: "<< hi << endl;
}
Online demo
If you want to consider + and - as alphanumeric, it'd be easy to check if hi is non empty and hi[0] a digit before trying to do the conversion.
Alternatively, you could also do a regex check of the string to see if it matches a numeric format.
I am trying to skip the spaces in my code using getline();
I think I solved the spacing problem, but I'm trying to make the code check from the beginning of the word and the end of the word at the same time, so that when I type sentences like "ufo tofu" it will come back as a palindrome.
I've tried removing the spaces, but it only causes the system to return me an error.
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
int main() {
string userInput;
int startInput;
int endInput;
bool isPalindrome = true;
startInput = userInput.length();
getline (cin, userInput);
cin.ignore();
for (int i = 0; i<(startInput/2); i++){
if (userInput[i] != userInput[(startInput -1) -i])
isPalindrome = false;
}
if (isPalindrome){
cout << userInput << " is a palindrome" << endl;
}
else {
cout << userInput << " is not a palindrome" << endl;
}
return 0;
}
I am trying to make the output come back as "is not a palindrome" when I submit my code to be graded.
These are the two errors that are coming back;
4: Compare output
0 / 2
Output differs. See highlights below.
Special character legend
Input
statistics
Your output
statistics is a palindrome
Expected output
statistics is not a palindrome
6: Compare output
0 / 2
Output differs. See highlights below.
Special character legend
Input
evil is alive
Your output
evil is alive is a palindrome
Expected output
evil is alive is not a palindrome
string s;
do {
getline(cin, s);
}while(s.empty());
s.erase((remove(s.begin(),s.end(),' ')),s.end());
cout<<s<<endl;
Let's say your string s is ufo tofu. It will after erasing all spaces become ufotofu. That way you can easily check if it's palindrome or not.
How does this thing work ?
Well we declare a string called s. In that string, we will store our ufo tofu input.
We use do-while loop to input our "sentence" into a string. We could use just getline(cin, s);, but if you pressed enter-key once, it would stop your program.
Next thing, we use function combination of functions remove and erase: As the beginning parameter we use function remove, which finds all the spaces in the string, pushes them to the end of the container (in our case string s), and returns beginning iterator of that "pushing", and the second parameter tells us to remove every single element of container from that beginning iterator to the end.
We just print out the string, but now without spaces!
I think this is really simple way to do it, but if it can't be useful to you, I am sorry for wasting your time reading all of this! :)
I am fairly new to programming and have to create a program which reads the prompt: "I have 8 dollars to spend." It then needs to print out with each word on a separate line, and then if any of the strings is numeric, it needs to be divided by 2. Therefore it should end up printing out as:
I
have
4
dollars
to
spend.
I have managed to do everything, except finding the numeric value and dividing it by 2. So far I have this:
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main()
{
string prompt;
string word;
cout << "Prompt: ";
getline(cin, prompt);
stringstream ss;
ss.str(prompt);
while (ss >> word)
{
cout << word << endl;
}
return 0;
}
After looking through various other posts, I cannot manage to get this to work. I'm assuming its an if/else statement within the while loop along the lines of, if numeric, set int num to num / 2 then cout << num << endl;, else cout << word << endl;, but I can't figure it out.
Thanks in advance.
You can use the stringstream class, which handles conversions between strings and other data types, to attempt to convert a given string to a number. If the attempt is successful, you know
The stringstream object allows you to treat a string as though it is a stream similar to cin or cout.
Incorporate this into your while loop, like so:
while (ss >> word)
{
int value = 0;
stringstream convert(word); //create a _stringstream_ from a string
//if *word* (and therefore *convert*) contains a numeric value,
//it can be read into an _int_
if(convert >> value) { //this will be false if the data in *convert* is not numeric
cout << value / 2 << endl;
}
else
cout << word << endl;
}
The strtol (C++11 version that works on std::string directly: std::stol) function is really good for testing whether a string holds a number, and if so, what the numeric value is.
Or you could continue using iostreams like you have been... try extracting a number (int or double variable), and if that fails, clear the error bit and read a string.
I dont have 50 rep so I cant comment, thats why I'm writing it as answer.
I think you can check it character by character, using Ascii value of each char, & if there are ascii values representing numbers between two spaces(two \n in this case as you've already seperated each word), then you have to divide the number by 2.
I've come this far without asking for help, but I've got a problem that I can't seem to fix. I like cryptology, so now that I am learning C++, I want to make programs to encrypt and decrypt strings. I read that the best way is to convert the text to ASCII and go from there, so here is a simple program I made in C++ to try and convert a char variable to ASCII:
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
int main()
{
char strString[1000];
cout<<"Enter you message:"<<endl;
cin>>strString[1000];
string strEncrypt;
int a = 0;
while (strString != '\0')
{
int b = (int)strString[a];
strEncrypt.at(a) = b; //This is where I'm getting an error.
a++;
}
cout<<"Encrypted message:"<<endl;
cout<<strEncrypt<<endl;
}
So, I've tried all 3 things I know to do to troubleshoot (Google, check for missing simicolons, and make sure I'm doing == not =, but this is just something I don't know how to do, not something I'm forgetting (I hope). So, any help would great!
You don't have to change the characters to ASCII they already are. Chars are basically the same as integers in memory.
Now to your question; . If you want to set a character in a string you can do that like this
string[index] = b;
Another thing to be careful for in your code. You are using cin to read the string from the user. This will not let you read messages that have spaces in them and will only read the first word. For example, if the user enters "Love Crypto" cin will only read "Love" and "Crypto" will be ignored. To get the entire line, use getline instead.
As for looping over characters in a string, it's better to do it as follows:
for(int i = 0; i < strString.length(); i++)
{
strString[i] = bla;
}
Again, you're code isn't actually doing anything. It is only reading a letter and then storing a "letter" in another string.
string::at() throws exception if the index passed to at() is out of range. So, if you are getting runtime error then it's expected. Because, your string strEncrypt is initialized to "" and thus the size is 0.
You may try
strEncrypt.reserve(strlen(strString));
Easiest way to actually make the code you have work is change this line strEncrypt.at(a) = b; to this strEncrypt += b; Which will add the characters to the empty string strEncrypt.
Your code doesn't make much sense though as char types are already ascii. You'll have to explain more about what kind of encrypting you are trying to do and maybe we can point you in the right direction.
EDIT: After thinking about what you're trying to do a bit more based on the code you have it seems like you want to print the numeric ascii value of characters. You can do that with just a cast like this:
string input;
cout << "Enter you message:" << endl;
// handle spaces in the message
getline(cin, input);
cout << "String chars as ascii values:" << endl;
cout << "Char: " << "ASCII Code:" << endl;
for (int i = 0; i < input.length(); ++i)
{
// casting the char to an int with (int) will print the ascii code
cout << input[i] << " " << (int)input[i] << endl;
}
On top of the fact that your input is already in ASCII, keep in mind that doing cin >> strString[1000] doesn't limit the input captured to the length of your buffer unless you specifically specify the number of characters to capture for the stream object using setw() or setting it's ios_base::width data member. So your method right now risks buffer overflows.
Secondly, the form of cin >> that you're using will not capture the entire line of input. Instead it will stop at the first white-space or any other delimiting character (or end-of-file if that is reached first). In your case, if you are entering a line like "Hello World", then the syntax you're using will only capture "Hello" and drop "World".
A much better idea would be to use the getline() function with a std::string object if you are wanting to capture a line of input to a string and remove the delimiting newline character without risking buffer overflows ... for instance:
string strString;
getline(cin, strString);
Apart from advises given, when receiving this kind of run-time errors use Cppcheck utility.
It will give you the answer: "Message: Array 'strString[1000]' index 1000 out of bounds".
I have the following for loop executing within my program and I can't see how it's design correlates with the output I'm receiving.
cout << no_of_lines << endl;
for (int count = 0; count < no_of_lines + 1; count ++)
{
getline(Device, line, '=');
cout << line << endl;
}
This is the output:
3
DeviceName
GPU
Manufacturer
Intel
GraphicalRam
128MB
And this is the file DeviceList
DeviceName=GPU
Manufacturer=Intel
GraphicalRam=128MB
In the loop, no_of_lines refers to the number of lines in the file, in this case 3. I have provided this output as verification that the loop is only executing once per line. Can anyone tell me why this loop is executing more times than is expected? I'm guessing it's because of my inclusion of = as the deliminator, and that the loop is somehow executing an additional time before incrementing, but then why does it stop on the deliminator on the last line, requiring me to add 1 to the loop limit?
This http://www.cplusplus.com/reference/string/getline/ is your friend here. The documentation says that when delem character is passed to getline, it reads up to delem char is found or end of file is reached. '\n' is not treated differently. Once it find delem char it discards it and fills line whatever it read until that point. Next time you call getline, it continues to read from where it left. so in this case, each call reads as follows.
DeviceName
GPU\nManufacturer
Intel\nGraphicalRam
128MB\n
'\n' in the above string is basically newline character. it's not really backslash followed by n (2 characters). its just single newline character '\n'. Just for understanding purposes I used it that way.
For clarity, here is the complete code(compiled and tested).
#include <iostream>
#include <string>
using namespace std;
int main()
{
int no_of_lines = 3;
string line;
cout << no_of_lines << endl;
for (int count = 0; count < no_of_lines + 1; count++)
{
getline(cin, line, '=');
cout << line << endl ;
}
return 0;
}
By now I hope its clear to you why you need to call getline 4 times.
your loop executes no_of_lines+1 times.
I assume you want the delimiter to be '='. However, when the delimiter is '=', then \n is not a delimiter. Hence line will contain \n (say, on the second getline). And so the number of lines displayed is not equal to the number of times the loop executes.
When you use = as line delimiter, \n is not used as line delimiter.
So you get strings containing newline characters.
When you output such a string, it's presented as two or more lines (due to the newlines it contains).
Cheers & hth.,
You want it to count thrice, but your loop is counting 0,1,2,3,4, i.e 5 iterations.