I have a lot of newlines in multiple Notepad++ files, and I'm hoping to find a RegEx/find/replace function to do the following across many files at the same time:
Join lines (separated by CR|LF) together, unless the line starts with the characters ISA. If the line starts with ISA, it should be its own first line and the rest of the lines after it should join to its line, until the next ISA.
Any help would be greatly appreciated!
Thanks,
Sydney
Replace \r\n(?!ISA) with an empty string (or perhaps a single space).
(?!...) is a negative lookahead and means not followed by ...
Related
I'm trying to removing a specific line from many files I'm working on with Notepad++.
Upon searching, I found Notepad++ Remove line with specific word in multiple files within a directory but somehow the regex provided (^.*(?:YOURSTRINGHERE).*\r\n$) from the answers doesn't work for me (screenshot: https://cdn.discordapp.com/attachments/311547963883388938/407737068475908096/unknown.png).
I read on some other questions/answers that certain regex doesn't work in newer/older Notepad++ versions. I was using Notepad++ 5.x.x then updated to the latest 7.5.4, but neither worked with the regex provided in the question above.
At the moment I can work around it by replacing that line with nothing, twice (because there are only 2 variants that I need to remove from those files) but that leaves an empty line at the end of the files. So I have to do another step further to remove that empty line.
I'm hoping someone can offer helps that allow me to remove that line and leave no empty line/space behind.
The regex you attempt to use will only match your line, if it is followed by an empty line and Windows linebreaks (CR LF) are used. This is due to \r\n$ which matches a linebreak sequence followed by the end of the line.
Instead you might want to use
^.*(?:YOURSTRINGHERE).*\R?
To match the line containing your string and optionally a following line break sequence to remove the line instead of emptying it out. This will leave you with a trailing newline, if your word is contained in the last line of a file. You can use
(\R)?.*(?:YOURSTRINGHERE).*(?(1)|\R)
To avoid this. It uses a conditional to either match the previous linebreak, or the following if there is none.
I am just finding my way around Sublime Text 3, so please be patient is this obvious to all you power users out there.
I want to change the first period . in multiple lines, and replace it with a comma , instead.
How to do that?
Example of my text:
something.here, more.words.here
somethingdifferent.ishere, and.morewords.again
I just want to change the first period in each line, not all periods, so that it will read:
Something,here, more.words.here
Somethingdifferent,ishere, and.morewords.again
There may be more sophisticated ways to do this, but one way is to turn on regular expression searching and do a search for:
^([^.]*)\.
and replace with
\1,
and then replace all. Just run it once across the entire file.
That search looks for the beginning of a line (^) and then 0 or more characters that are not periods, followed by a period. It replaces it with that first set of characters, followed by a comma. (The backslash before the period at the end of the search is essential, as the period is a special character that can take the place of any character without that escape.)
The direct question: How can I use REGEX lookarounds to find instances of \r\n that occur between a set of characters (stand in open and closing tags), "[ and ]" with arbitrary characters and line breaks inside as well?
The situation:
I have a large database exported to tab or comma delineated text files that I'm trying to import into excel. The problem is that some of the cells come from text areas that contain line breaks, and are qualified by double quotes. Importing into excel these line breaks are treated as new rows. I cannot adjust how the file is exported. I data needs to be preserved, but the exact format doesn't, so I was planning on using some placeholder for the returns or ~
Here's a generic illustration of the format of my data:
column1rowA column2rowA column3rowA column4rowA
column1rowB column2rowB "column3rowB
3Bcont
3Bcont
3Bcont
" column4rowB
column1rowC column2rowC column4rowC
column1rowD column2rowD "column3rowD
3Dcont" column4rowD
My thought has been to try to select and replace line breaks within the quotes using REGEX search and replace in Notepad++. To try and make is simpler I have tried adding a character to the double quotes to help indicate whether it is an opening or closing quote:
"[column3rowB
3Bcont
3Bcont
3Bcont
]"
I am new to REGEX. The progress I've made (which isn't much) is:
(?<="[) missing some sort of wildcard \r\n(?=.*]")
Every iteration I've tried has also included every line break between the first "[ and last ]"
I would also appreciate any other approaches that solve the underlying problem
If you can use some tool other than Notepad++, you can use this regex (see my working example on regex101):
(?!\n(([^"]*"){2})*[^"]*$)\n
It uses a negative lookahead to find line breaks only when not followed by an even number of quotes. You could replace them with <br>, spaces, or whatever is appropriate.
Breakdown:
(?! ... ) This is the negative lookahead, necessary because it's zero-width. Anything matched by it will still be available to match again.
(([^"]*"){2})* This is the other key piece. It ensures even-numbered pairs of non-quote characters followed by a quote.
[^"]*$ This is ensuring that there are no more quotes from there until the end of the string.
Caveat:
I couldn't get it to work in Notepad++ because it always recognizes $ as the end of a line, not the end of the entire string.
Great answer from Brian. I added an option that would only consider real linebreaks (i.e. \n\r), which worked for my CSV file:
(?!\n|\r(([^"]*"){2})*[^"]*$)\n|\r
I have a word list in alphabetical order.
It is ranked as a column.
I do not use any programming languages.
The list in notepad format.
I need to match every similar words and take them on same line.
I use regex but I can't achieve correct results.
First list is like:
accept
accepted
accepts
accepting
calculate
calculated
calculates
calculating
fix
fixed
A list I want:
accept accepted accepts accepting
calculate calculated calculates calculating
fix fixed
This seems to work, but you will have to do Replace All multiple times:
Find (^(.+?)\s*?.*?)\R\2 and replace with \1\t\2. . matches newline should be disabled.
How it works:
It finds some characters at the start of line ^(.+?), then any linebreak \R, and those same characters again \2.
\s*?.*? is used to skip unnecessary characters after multiple Replace All. \s*? skips the first whitespace, and .*? any remaining chars on the line.
Match is replaced with \1\t\2, where \1 is anything matched in (^(.+?)\s*?.*?), and \2 is anything matched with (.+?). \t is used to insert tab character to replace linebreak.
How it breaks:
Note that this will not work well with different words with similar prefix, like:
hand
hands
handle
handles
This will be hand hands handle handles after 2 replaces.
I can imagine doing this programatically with limited success (take first word which comes as a root and if derived word with this root follows, place it on the same line, else take the word as a new root and put it to new line). This will still fail at irregular words where root is not the same for all forms.
Without programming there is a way only with (manual) preprocessing – if there are less than 4 forms for given word in the list, you insert blank line for each missing verb form, so there are always 4 lines for each word. Then you can use regex to get each such a quadruple into one line.
I have a big paragraph which I need to split into lines such that each line must not have more than 100 characters and no words must be broken. How would I go about doing this? I guess with regular expressions is the best way but I'm not sure how.
Use Text::Wrap.
Text::Wrap::wrap() is a very simple paragraph formatter. It formats a single paragraph at a time by breaking lines at word boundaries. Indentation is controlled for the first line ($initial_tab) and all subsequent lines ($subsequent_tab) independently.
While you should use a library function if you have one, as KennyTM suggested, a simple regex to solve this can be:
.{1,100}\b
This will take 100 characters or less, and will not break words. It would break other characters though, for example the period at the end of a sentence may be parted from the last word (last word<\n>. new line).
If that's an issue, you can also try:
.{1,99}(\s|.$)
That assures the last character in every match is a white space.
All of these assume you count spaces as characters, and probably don't have newlines in your text (a single paragraph), and don't have word of over 100 characters.