C++ 2D Array Allocating Memory to Avoid Segmentation Fault - c++

Question

I usually code in other languages (R, Python and Java), but recently started using C++. I've been solving problems on hackerrank.com, and specifically I bumped into this one:
https://www.hackerrank.com/challenges/variable-sized-arrays
Prior to this question, I had never gotten a Segmentation Fault error. I've tinkered with the code and discovered that the error only occurs when I attempt to print from the arr variable.
I wonder if someone could help me with this, and maybe provide a detailed explanation as to the precise error?
The code is as follows, but the issue is likely with int arr[100000][100000] = {-1}; and printf("%d\n", arr[iHat][jHat]); because I can printf both iHat and jHat themselves, but I am unable to use them to access integers in the arr array.
#include <iostream>
using namespace std;
int main(){
int n, q;
/*
*scan in:
*n array entries
*q quaries
*/
int arr[100000][100000] = {-1}; //initialize an array, larger than 10^5
scanf("%d %d\n", &n, &q); //n is size of array, q is # of quaries
for (int i = 0; i < n; ++i){ //loop through lines of input to populate array
int c, y = 0; //initialize to zero at the start of each line
while((c = getchar()) != '\n'){ //readline
if(c != ' '){ //pass spaces
arr[i][y] = c; //place integer into array
++y;
}
}
}
for (int i = 0; i < q; ++i){
int iHat, jHat = 0;
scanf("%d %d\n", &iHat, &jHat); //scan for coordinates
printf("%d\n", arr[iHat][jHat]); //Segmentation fault occurs here, why?
}
return 0;
}
Update
This question focused on memory management, and in particular the use of pointers. A functioning solution, resulting in no segmentation faults, is as follows:
#include <iostream>
using namespace std;
int main(){
int n, q;
/*
*scan in:
*n array entries
*q quaries
* format: %d %d
*/
scanf("%d %d\n", &n, &q);//n is size of array of arrays, q is # of quaries
int **arr = new int *[n]; //int** arr is a pointer of pointers of size n
for (int i = 0; i < n; ++i){//loop through lines of input to populate array
int k; //Always initialize variables in the narrowest scope possible!
scanf("%d", &k);//grab k, the number of ints in the line
arr[i] = new int[k];//create a 2nd dimension at entry i of size k
for (int j = 0; j < k; ++j){
scanf("%d", &arr[i][j]);//populate array
}
}
for (int i = 0; i < q; ++i){
int iHat, jHat = 0;
scanf("%d %d\n", &iHat, &jHat); //scan for query coordinates
printf("%d\n", arr[iHat][jHat]); //print results of query
}
return 0;
}

Answer 1

C++ gives you control of where you want to allocate memory. In your case, what you have found is that you allocated an array-of-array-of-int on the stack which exceeds the stack size. At some point, you access one of these elements which lies outside the bounds of the stack and also the program, which causes an access violation called a segmentation fault.
Since you mentioned being new to C++, it would help to understand these 3 areas of memory and how you would use each for your case:
Stack memory - space for temporary variables to automatically use without having to explicitly request. You will see undefined behavior if you exceed the stack size.
int main() {
int arr[100000][100000];
}
Heap memory - space for dynamically allocating space whenever explicitly requested using the operator "new". An "std::bad_alloc" exception will be thrown if the requested memory size exceeds what is available.
int main() {
int **arr = new int *[100000];
for (std::size_t i = 0; i < 100000; ++i) {
arr[i] = new int[100000];
}
}
Static memory - space allocated for static objects before main runs. You will get a compiler error if the array dimensions are too large.
int arr[100000][100000];
int main() {
...
}

Answer 2

That's 40 GB!
Even if you have that much RAM in the machine, it is surely not allocated as stack space.
If you do have that much memory you can move the arr to the global area before main. That way it will not be on the stack.
If you don't have 40+ GB available, you might have to rethink the solution. :-) Perhaps do the calculations in smaller segments?

Answer 3

Here are a few thoughts
1) You are trying to allocate 100,000 x 100,000 bytes, which equal 10,000,000,000 bytes (~10GB) on the stack. The default stack size is about 8MB on 32-bit linux. Even if the stack size is larger it won't be 10GB.
2) The name of the exercise you were working on is "Variable Sized Array" The line you entered,int arr[100000][100000] is a fixed size array. You should be using keyword new to dynamically create the array.
3) The reason for the Segmentation Fault error is because your print statement is attempting to access memory outside of the Virtual Memory space allowed for a stack size.
[Suggestion]
1) trying doing some exercises where you allocate and clean up dynamic memory using new and delete. Also in C++ allocating and deleting arrays is done differently than just a single data structure.
Cheers

Answer 4

Are you trying to do this?
#include <iostream>
using namespace std;
int main(){
int n, q;
const int length = 100;
int arr[length][length] = { -1 };
cout << "Enter length of 2d array" << endl;
cin>>n>>q;
cout << "Fill the array" << endl;
for (int i = 0; i < n; ++i) {
for(int y=0;y<q;y++){
int f;
cin >> f;
arr[i][y]=f;
}
}
int iHat;
int jHat;
cout << "Enter coordinates" << endl;
cin>>iHat>>jHat;
cout<<arr[iHat][jHat];
return 0;
}
P.S i decreased array size, becouse 100000 x 100000 this is lot of gigabytes and it says array is too large