I have data structured like this:
<url title="Stack Overflow">http://stackoverflow.com/</url>
<url>http://example.com/</url>
The title attribute is optional. I have an XSLT stylesheet including this:
<xsl:template match="url">
<xsl:value-of select="(#title | .)[1]"/>
</xsl:template>
I want to display the title if there is one and otherwise display the url. However for some reason the title is never displayed. (In every case the url is displayed.)
What am I doing wrong?
Thanks!
Try either:
<xsl:value-of select="(#title | text())[1]"/>
or:
<xsl:value-of select="(#title | .)[last()]"/>
Explanation:
The . abbreviation in your expression represents the url element itself, which precedes its attributes in document order.
Related
I want to change the order of line cac:InvoiceLine depending on this node:
cac:AdditionalItemProperty/cbc:Value
All InvoiceLines that have Item type=RC must be gruop at the end of lines, and all that have CU must be on the top.
If the mentioned values are the only ones you are concerned about, then it seems like you could just sort alphabetically by that value; see xsl:sort. You could just put this inside the xsl:for-each or xsl:apply-templates where you process your invoice lines:
<xsl:sort select="cac:AdditionalItemProperty/cbc:Value" />
On the other hand, if you only want to output only the line items with the mentioned values, you could select them separately. For example, assuming you have a template which matches your invoice lines, you'd first apply it to the 'CU' ones and then to the 'RC' ones:
<xsl:apply-templates select="cac:InvoiceLine[cac:AdditionalItemProperty/cbc:Value='CU']" />
<xsl:apply-templates select="cac:InvoiceLine[cac:AdditionalItemProperty/cbc:Value='RC']" />
I want to get the value of a specific node, specified by its id attribute. But the behaviour of my XSL parser, Saxon, is not how I expected it to work.
This is my XSL code:
<xsl:template match="synonyme">
<xsl:element name="corr">
<xsl:value-of select="#connecteur" />
<xsl:value-of select="/liste/connecteur[#id=#connecteur]/forme[1]" />
</xsl:element>
</xsl:template>
I just matched a tag named synonyme which has a connecteur attribute. My code outputs the value of this attribute.
I also want to output the value of another node which has an id attribute matching the connecteur attribute of my currently matched synonyme tag. But no results are ever found for this query, the second value-of always has empty output.
If I write, e.g. [#id='c160'], where c160 is the exact same thing that is output by the first value-of, it works! But not when comparing to the #attribute of my matched node. How can I fix this?
The XML is basically
<liste><connecteur id="c160"><forme>foo</forme></connecteur>
<connecteur id="c161"><synonyme connecteur="c160" /></connecteur>
</liste>
and the expected output in place of the synonyme is <corr>c160 foo</corr>.
The predicate you use:
[#id=#connecteur]
is looking for an element with two attributes - id and connecteur- with equal values. To look for an element with an id attribute whose value matches the value of the current element's connecteur value, you need to use:
[#id=current()/#connecteur]
See: https://www.w3.org/TR/xslt/#function-current
A better solution would be to define a key as:
<xsl:key name="ref" match="connecteur" use="#id" />
then use:
<xsl:value-of select="key('ref', #connecteur)/forme" />
to resolve the cross-reference.
See: https://www.w3.org/TR/xslt/#key
In the code bellow I'm applying all the templates to the element chapter (in the end of the code) but I would like to know how it is possible to apply all the templates to this element except a spefic one. In this case it's the element title because I'm already selecting it in the line before and it appears repeated in the html file. Someone?
<xsl:template match="chapter">
<h3>
<a name="{#id}"><xsl:value-of select="title"/></a>
</h3>
<xsl:apply-templates/>
</xsl:template>
Output:
<h3>Title</h3>
Title<br>
Text.
A plain <xsl:apply-templates/> is equivalent to <xsl:apply-templates select="node()" />, i.e. all child nodes. You can exclude certain nodes by using the XPath 2.0 except operator, e.g.
<xsl:apply-templates select="node() except title" />
This would select all child nodes except those that are elements with the name title. If you are only interested in child elements (not text nodes etc.) then you could use * except title instead.
The except operator essentially implements set difference - you're not limited to simple element names on the right, you can use any expression that returns a sequence of nodes, e.g.
node() except (title | div[#class = 'heading'])
X except Y selects all nodes that are in the sequence selected by X and not also in the sequence selected by Y
I created a component named "BusLocationLinks" it stores the name of the business as well as the coordinates for a map I created.
I have nearly 50 business locations with that same schema (BusLocationsLinks) and only want to list the element "Business Name" of all components components of that name. I've tried everything but can not make them all display. ANY ADVICE?
Here's my current code:
<xsl:template name="BusLocationLinks">
<xsl:for-each select="BusLocationLinks/BusinessName">
<li class="active">
<xsl:value-of select="BusinessName" />
</li>
</xsl:for-each>
</xsl:template>
my xml code looks similar to such:
<BusLocationLinks>
<BusinessName>Star Property</BusinessName>
</BusLocationLinks>
Without seeing your XML it is difficult to diagnose the problem. However, it is likely that you have the following structure:
<BusLocationLinks>
<BusinessName>name1</BusinessName>
<BusinessName>name2</BusinessName>
<BusinessName>name3</BusinessName>
</BusLocationLinks>
If that is the case, then you should adjust your XSLT like this:
<xsl:template name="BusLocationLinks">
<xsl:for-each select="BusinessName">
<li class="active">
<xsl:value-of select="." />
</li>
</xsl:for-each>
</xsl:template>
The body of an xsl:for-each instruction resets the context node to be one of the nodes in the selected node set (a different one each time the body of the for-each is evaluated).
In your example, that means that within the body of the for-each, the current node is one of the BusLocationLinks/BusinessName elements you selected. Your loop creates a list-item element for each of them (check your output, I expect you'll see them there) containing the value of the BusinessName child of the context node. The context node matches the expression BusLocationLinks/BusinessName, so you are looking for the values of nodes which match BusLocationLinks / BusinessName / BusinessName. If you don't have any nodes that match the expression BusLocationLinks / BusinessName / BusinessName, you'll be getting empty li elements.
Try <xsl:value-of select="."/>.
I have a variable from which I need to dynamically generate nodes
<xsl:template match="banner_discount_1 | banner_discount_2 | banner_discount_3">
<xsl:variable name="link">banner_discount_<xsl:value-of select="substring-after(name(.) ,'banner_discount_')" />_link</xsl:variable>
<xsl:value-of select="$link" />
</xsl:template>
<xsl:value-of> selects the string, but I want to be able to select the node which name matches the name of a variable.
In my case the node looks something like this:
<banner_discount_1_link />
<banner_discount_2_link />
...
Here is the xml I'm using
<banner_discount_1> 12 </banner_discount_1>
<banner_discount_2> 21 </banner_discount_2>
<banner_discount_3> 32 </banner_discount_3>
<banner_discount_1_link> link1 </banner_discount_1_link>
<banner_discount_2_link> link2 </banner_discount_2_link>
<banner_discount_3_link> link3 </banner_discount_3_link>
#MartinHonnen is on the right track, but you need to set the selection context as well.
Since you're in a template that's selecting the banner_discount_ nodes, that is your context. From your XML sample, it looks like the nodes you want to select are siblings, so this should work:
<xsl:value-of select="../*[local-name() = $link]"/>
It is preferable to target the nodes directly, but if they could be anywhere in the document, then you may resort to
<xsl:value-of select="//*[local-name() = $link]"/>
This is a last resort because it is potentially O(n) with respect to the number of nodes in the document.
Use <xsl:value-of select="*[local-name() = $link]"/>. If that does not help then consider to show a sample of the XML.